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\(3x+36=-7x-64\)
\(10x=-100\)
\(x=-10\)
\(-5x-178=14x+145\)
\(-19x=323\)
\(x=-17\)
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\(a,3x-32>-5x+1\)
\(\Leftrightarrow3x+5x>32+1\)
\(\Leftrightarrow8x>33\)
\(\Leftrightarrow x>\frac{33}{8}=4,125\approx4\)
Vậy \(x>4,x\inℤ\)
\(b,15+4x< 2x-145\)
\(\Leftrightarrow4x-2x< -145-15\)
\(\Leftrightarrow2x< -160\)
\(\Leftrightarrow x< \frac{-160}{2}=-80\)
Vậy \(x< -80,x\inℤ\)
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\(X^2=49\\ Mà:7^2=49;\left(-7\right)^2=49\\ \Rightarrow X=7.hoặc.x=-7\\ ----\\ b,\left(5x+1\right)^2=121=11^2=\left(-11\right)^2\\ Nên:5x+1=11.hoặc.5x+1=-11\\ Nên:5x=10.hoặc.5x=-12\\ Vậy:x=2.hoặc.x=-\dfrac{12}{5}\\ ---\\ 3x+36=-7x-64\\ \Rightarrow3x+7x=-64-36\\ \Rightarrow10x=-100\\ \Rightarrow x=-\dfrac{100}{10}=-10\\ ---\\ -5x-1178=14x+145\\ \Rightarrow14x+5x=-1178-145\\ \Rightarrow19x=-1323\\ \Rightarrow x=\dfrac{-1323}{19}\)
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a) x2 - 145 = -64
x2=-64+145
x2=81
x2=92
=>x=+9
Vậy x=+9
b) (3x - 4)(5x+15)=0
.\(\Rightarrow\orbr{\begin{cases}3x-4=0\\5x+15=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}3x=4\Rightarrow x=\frac{4}{3}\\5x=-15\Rightarrow x=-15:5=-3\end{cases}}\)
Vậy..............................................
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2^4 .x - 3^2 .x = 145 - 255 : 51
16.x - 9.x = 145 - 5
16.x - 9.x = 140
(16 - 9).x = 140
7x = 140
x = 140 : 7
x = 20
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x(24-32)=145-5
\(\Leftrightarrow\)7x=140
\(\Leftrightarrow\)x=20
5(x+35)-200=288-93
\(\Leftrightarrow\)5(x+35)=288+200-93=395
\(\Leftrightarrow\)x+35=79
\(\Leftrightarrow\)x=44
a, Lời giải
\(x\left(2^4-3^2\right)=145-5\)
\(\Leftrightarrow7x=140\)
\(\Leftrightarrow x=140:7\)
\(\Rightarrow x=20\)
b, Lời giải
\(5\left(x+35\right)-200=288-93\)
\(\Leftrightarrow5\left(x+35\right)=395\)
\(\Leftrightarrow x+35=395:5\)
\(\Leftrightarrow x+35=79\)
\(\Leftrightarrow x=79-35\)
\(\Rightarrow x=44\)
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a) \(\left[\left(x+32\right)-17\right].2=42\)
\(\left[\left(x+32\right)-17\right]=42:2\)
\(\left[\left(x+32\right)-17\right]=21\)
\(\left(x+32\right)=21+17\)
\(\left(x+32\right)=38\)
\(x=38-32\)
\(x=6\)
b) \(125+\left(145-x\right)=175\)
\(\left(145-x\right)=175-125\)
\(\left(145-x\right)=50\)
\(x=145-50\)
\(x=95\)
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\(\left(x.7-7\right)\left(x.12+24\right)=0\)
=> \(\orbr{\begin{cases}x.7-7=0\\x.12+24=0\end{cases}}\)
=> \(\orbr{\begin{cases}7x=7\\12x=-24\end{cases}}\)
=> \(\orbr{\begin{cases}x=1\\x=-2\end{cases}}\)
\(170-\left(4+5x\right)=101\)
=> \(4+5x=170-101\)
=> \(4+5x=69\)
=> \(5x=69-4\)
=> \(5x=65\)
=> \(x=65:5=13\)
(x.7-7).(x.12+24)=0
* x.7-7=0 * x.12+24=0
x.7=7 x.12=24
x=7:7 x=24:12
x=1 x=2
vạy x=1 hoặc x=2
170-(4+5x)=101
4+5x=170-101
4+5x=69
5x=69-4
5x=65
x=65:5
x=13
vậy x=13
250:(2x-4)=145-120
250:(2x+4)=25
2x+4=250:25
2x+4=10
2x=10+4
2x=14
x=14:2
x=7
vậy x=7
6.x+3.x-4.x=105
x.(6+3-4)=105
x.(9-4)=105
x.5=105
x=105:5
x=21
vậy x=21
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\(\left(2^3+4^2\right)\times x+2^5\times5x=100\)
\(\left(8+16\right)\times x+32\times5x=100\)
\(32x+32x\times5=100\)
\(32x\times\left(1+5\right)=100\)
\(32x\times6=100\)
\(32x=\frac{100}{6}\)
\(x=\frac{50}{3}-32\)
\(x=-\frac{46}{3}\)