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\(\frac{x}{2^2}+\frac{x}{2^3}+\frac{x}{2^4}=\frac{x}{3^2}+\frac{x}{3^3}+\frac{x}{3^4}\)
\(\Leftrightarrow\frac{x}{4}+\frac{x}{8}+\frac{x}{16}=\frac{x}{9}+\frac{x}{27}+\frac{x}{81}\)
\(\Leftrightarrow\frac{4x}{16}+\frac{2x}{16}+\frac{x}{16}=\frac{9x}{81}+\frac{3x}{81}+\frac{x}{81}\)
\(\Leftrightarrow\frac{7x}{16}=\frac{13x}{81}\Leftrightarrow567x=208x\Leftrightarrow x=\frac{1}{359}\)

4) \(2.3^x+3^{x-1}=7.\left(3^2+2.6^2\right)\)
\(\Rightarrow2.3^x+3^{x-1}=567\)
\(\Rightarrow7.3^{x-1}=567\)
\(\Rightarrow3^{x-1}=567\div7\)
\(\Rightarrow3^{x-1}=81\)
\(\Rightarrow3^{x-1}=3^4\)
\(\Rightarrow x-1=4\)
\(\Rightarrow x=4+1\)
\(\Rightarrow x=5\)
Vậy \(x=5\)

2x + 2x + 1 + 2x + 2 + 2x + 3 = 480
2x + 2x . 2 + 2x . 22 + 2x . 23 = 480
2x . ( 1+ 2 + 22 + 23) = 480
2x . 15 = 480
2x = 32
2x = 25
=> x = 5
Vậy x = 5

2x + 2x+1 +2x+2 + 2x+3 = 120
Suy ra 2x .1 + 2x . 2 + 2x . 22 + 2x . 23 = 120
Suy ra 2x .( 1 + 2 + 4 + 8 ) = 120
Suy ra 2x . 15 = 120
Suy ra 2x = 120 : 15
Suy ra 2x = 8
Suy ra 2x = 23
Do đó x = 3
Vậy x = 3
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=120\)
\(\Rightarrow2^x+2^x.2+2^x.2^2+2^x.2^3=120\)
\(\Rightarrow2^x+2^x.2+2^x.4+2^x.8=120\)
\(\Rightarrow2^x\left(1+2+4+8\right)=120\)
\(\Rightarrow2^x.15=120\)
\(\Rightarrow2^x=120:15\)
\(\Rightarrow2^x=8\)
\(\Rightarrow2^x=2^3\)
\(\Rightarrow x=3\)

2x+ 2x+1+ 2x+2 + 2x+3 = 2x+ 2x.2 + 2x.22 + 2x.23 = 2x(1+ 2 + 22 + 23) = 2x.15 = 120 => 2x =120:15 = 8 => x = 3

a)\(\Rightarrow\orbr{\begin{cases}x=0\\x+2=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=-2\end{cases}}}\)
b)\(\Rightarrow\orbr{\begin{cases}x^2+1=0\\x^2-4=0\end{cases}\Rightarrow\orbr{\begin{cases}x^2=-1\left(VL\right)\\x^2=4\Rightarrow x=2,-2\end{cases}}}\)VL là vô lý do bình phương luôn là số dương
Ủng hộ minhf bằng cachs k đúng nha

4 x 3x-1 + 2 x 3x+2 = 4 x 36 +2 x 39
=> 3x-1 = 36 => x - 1 = 6 => x = 6 + 1 = 7
=> 3x+2 = 39 => x + 2 = 9 => x = 9 - 2 = 7
Vậy x = 7
\(4.3^{x-1}+2.3^{x+2}=4.3^6+2.3^9\)
\(\Rightarrow2.3^{x-1}\left(2+27\right)=2.3^6\left(2+27\right)\)
\(\Rightarrow2.3^{x-1}=2.3^6\)
\(\Rightarrow x-1=6\Leftrightarrow x=7\)

(4x-3)4=(4x-3)2
\(\Rightarrow\)(4x-3)4 - (4x-3)2=0
\(\Rightarrow\)(4x-3)2.[(4x-3)2-1]=0
\(\Rightarrow\)(4x-3)2-1=0:(4x-3)2
\(\Rightarrow\)(4x-3)2-1=0
\(\Rightarrow\)(4x-3)2=0+1
\(\Rightarrow\)(4x-3)2=1
\(\Rightarrow\)(4x-3)2=12
\(\Rightarrow\)4x-3=1
\(\Rightarrow\)4x=1+3
\(\Rightarrow\)x=4:4
\(\Rightarrow\)x=1
(x-1)3=125
\(\Rightarrow\)(x-1)3=53
\(\Rightarrow\)x-1=5
\(\Rightarrow\)x=5+1
\(\Rightarrow\)x=6
2x+2 - 2x=96
\(\Rightarrow\)2x. 4 - 2x=96
\(\Rightarrow\)2x . (4-1) = 96
\(\Rightarrow\)2x . 3 =96
\(\Rightarrow\)2x = 96:3
\(\Rightarrow\)2x = 32
\(\Rightarrow\)2x = 25
\(\Rightarrow\)x =5
2x +2x+3=320
<=>2x.(1+23)=320
Ủa số lẻ rứa??
Ta có: \(2^x+2^{x+3}=320\)
\(\Leftrightarrow2^x\cdot9=320\)
\(\Leftrightarrow2^x=\dfrac{320}{9}\)
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