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1) 2x+1+2x=2x(2+1)=24
=>2x=8 =>x=3
2) 4x+1-3.4x=4x(4-3)=>4x=16=>x=2
3) x2-x=x(x-1)=0
=>\(\orbr{\begin{cases}x=0\\x-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}}\)
\(3+2^{x-1}=24-\left[4^2-\left(2^2-1\right)\right]\)
\(\Rightarrow3+2^{x-1}=24-16+\left(4-1\right)\)
\(\Rightarrow3+2^{x-1}=8+3\)
\(\Rightarrow2^{x-1}=2^3\)
\(\Rightarrow x=4\)
\(3+2^{x-1}=24-\left[4^2-\left(2^2-1\right)\right]\)
\(\Rightarrow3+2^{x-1}=24-\left[16-\left(4-1\right)\right]\)
\(\Rightarrow3+2^{x-1}=24-\left[16-3\right]\)
\(\Rightarrow3+2^{x-1}=24-13\)
\(\Rightarrow3+2^{x-1}=11\)
\(\Rightarrow2^{x-1}=11-3\)
\(\Rightarrow2^{x-1}=8\)
\(\Rightarrow2^{x-1}=2^3\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=3+1\)
\(\Rightarrow x=4\)
Vậy x = 4
_Chúc bạn học tốt_
\(3+2^{x-1}=24-\left\{4^2-\left(2^2-1\right)\right\}\)
\(\Rightarrow3+2^{x-1}=24-\left\{16-\left(4-1\right)\right\}\)
\(\Rightarrow3+2^{x-1}=24-\left\{16-3\right\}\)
\(\Rightarrow3+2^{x-1}=24-13\)
\(\Rightarrow3+2^{x-1}=11\)
\(\Rightarrow2^{x-1}=11-3\)
\(\Rightarrow2^{x-1}=8\)
\(\Rightarrow2^{x-1}=2^3\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=3+1\)
\(\Rightarrow x=4\)
Vậy x = 4
_Chúc bạn học tốt_
a,Ta có: \(\left(x+2\right)^4=\left(x+2\right)^6\)
\(\left(x+2\right)^4-\left(x+2\right)^6=0\)
\(\left(x+2\right)^4\text{[}1-\left(x+2\right)^2\text{]=0}\)
\(\Rightarrow\orbr{\begin{cases}\left(x+2\right)^4=0\\1-\left(x+2\right)^2=0\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x+2=0\\x+2=1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-2\\x=-1\end{cases}}\)
1/
(-2)2 . 52 . (-27)
= 4 . 25 . (-27)
= 100 . (-27)
= -2700
2/
23 - (-x) = 24.
23 + x = 24
x = 24 - 23
x = 1.
1/(-2)2.52.(-27)
=[(-2).5]2*(-27)
=[-10]2*(-27)
=100*(-27)
=-2700
2/23 - -x = 24
23+x=24
x=1
a)(2x-2)3=8
(2x-2)3=(\(\pm\)2)3
Vậy 2x-2=2 hoặc 2x-2=(-2)
2x =2+2=4 2x =2+(-2)=0
x =4:2=2 x 0:2=0
Câu b mik ko biết sorry nha!
Hok tốt!
Ta có x-{[52 - (92 -16.5)30 . 24]3 + 14 } =1
=> x- {[25- ( 81-80) 30 . 24]3 +14 }=1
=> x -{[ 25-(1.24) 3 +14} =1
=> x - (1+14) =1
=> x- 15 =1
=> x=16
2x + 2x + 1 = 24
2x.(1 + 2) = 24
2x = 8 = 23
=> x = 3