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Câu 3:
<=> \(\hept{\begin{cases}\left(x-y^2+z\right)^2=0\\\left(y-2\right)^2=0\\\left(z+3\right)^2=0\end{cases}}\) <=> \(\hept{\begin{cases}\left(x-2^2-3\right)^2=0\\y=2\\z=-3\end{cases}}\) <=> \(\hept{\begin{cases}x=7\\y=2\\z=-3\end{cases}}\)
Câu 4 tương tự.
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a. 2^x.4=128
2^x=128:4=32
2^x=2^5
x=5
b. x^15=x
x=1
c. 2^x.(2^2)^2=(2^3)^2
2^x.2^4=2^6
2^(x+4)=2^6
x+4=6
x=6-4=2
d. (x^5)^10=x
x^50=x
x=1
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a) 7(x-5)+14=56
<=>7(x-5)=42
<=>x-5=6
<=>x=11
b)9(x+1)-3=15
<=>9(x+1)=18
<=>x+1=2
<=>x=1
c)12(x+5)-36=48
<=>12(x+5)=84
<=>x+5=7
<=>x=2
d)5(x+14)=145
<=>x+14=29
<=>x=15
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a) \(2^x.4=128\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
vậy \(x=5\)
b) \(x^{15}=x\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
vậy \(\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
c) \(2^x.\left(2^2\right)^2=\left(2^3\right)^2\)
\(2^x.2^4=2^6\)
\(2^x=2^2\)
\(\Rightarrow x=2\)
vậy \(x=2\)
d) \(\left(x^5\right)^{10}=x\)
\(x^{50}=x\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=\pm1\end{cases}}\)
vậy \(\orbr{\begin{cases}x=0\\x=\pm1\end{cases}}\)
a, 2x.4 = 128
2x = 128 : 4
2x = 32
2x = 25
=> x = 5
b, x15 = x
=>x15 - x = 0
=> x14.x - x = 0
=> x(x14 - 1) = 0
=> x = 0 hoặc x14 - 1 =0
=> x = 0 hoặc x14 = 1
=> x = 0 hoặc x = 1 hoặc x = -1
Mà x \(\in\)N
=> x = 0 hoặc x = 1
c, 2x.(22)2 = (23)2
2x.24 = 26
2x = 26 : 24
2x = 22
=> x = 2
d, (x5)10 = x
=> x50 = x
=> x50 - x = 0
=> x49.x - x = 0
=> x(x49 - 1) = 0
=> x = 0 hoặc x49 - 1 = 0
=> x = 0 hoặc x49 = 1
=> x = 0 hoặc x = 1
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2^x.4=128\)
\(\Rightarrow2^x=128:4\)
\(\Rightarrow2^x=32=2^5\)
\(\Rightarrow x=5\)
tíc mình nha
Ta có: A = 1 + 2 + 22 + 23 + 24 + ...... + 2100
=> 2A = 2 + 22 + 23 + 24 + ...... + 2101
=> 2A - A = 2101 - 1
=> A = 2101 - 1
![](https://rs.olm.vn/images/avt/0.png?1311)
a) (4x - 1)2 = 25.9
=> (4x - 1)2 = 52 . 32 = 152
=> 4x - 1 = 15
=> 4x = 16
=> x = 4
b) 2x + 2x+3 = 144
=> 2x + 2x . 23 = 144
=> 2x (1 + 23) = 144
=> 2x . 9 = 144
=> 2x = 16
=> x = 4
c) đề chắc chắn đúng chứ :v
d) (2x + 1)3 - 12 = 15
=> (2x + 1)3 = 27
=> (2x + 1)3 = 33
=> 2x + 1 = 3 => 2x = 2 => x = 1
2. 2x = 16 => 2x = 24 => x = 4
3x = 81 => 3x = 34 => x = 4
x3 = 64 => x3 = 43 => x = 4
x2 =81 => x2 = 92 => x = 9
![](https://rs.olm.vn/images/avt/0.png?1311)
2x*(22)2=(23)2
=>2x*24=26
=>2x=26/24
=>2x=26-4
=>2x=22
=>x=2
2x . (22)4 = (23)2
= 2x . 16 = 64
2x = 64 : 16
22 = 4
22 = 22
Suy ra : x = 2