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1
\(\left(x-2\right):2.3=6\)
\(\Leftrightarrow\left(x-2\right):2=2\)
\(\Leftrightarrow\left(x-2\right)=4\)
\(\Leftrightarrow x=4+2=6\)
c) ta có
\(\left[\left(2x+1\right)+1\right]m:2=625\)
\(\Leftrightarrow\left[\left(2x+1\right)+1\right]\left\{\left[\left(2x+1\right)-1\right]:2+1\right\}=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-1:2+1=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-2+1=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-2=1249\)
\(\Leftrightarrow\left(2x+1\right)^2+1=1251\)
\(\Leftrightarrow\left(2x+1\right)^2=1250\)
...
2
\(\left(x-\frac{1}{2}\right).\frac{5}{3}=\frac{7}{4}-\frac{1}{2}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right).\frac{5}{3}=\frac{5}{4}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)=\frac{5}{4}:\frac{5}{3}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)=\frac{5}{4}.\frac{3}{5}\)
\(\Leftrightarrow x-\frac{1}{2}=\frac{3}{4}\)
\(\Leftrightarrow x=\frac{3}{4}+\frac{1}{2}=\frac{5}{4}\)

a. x:(1/2+2/3)=6/5
=>x:7/6=6/5
=>x=6/5*7/6=>x=7/5
b.(x-1/2)-5(x-2/3)=3/2x
=>x-1/2-5x+10/3=3/2x
=>-4x+17/6=3/2x
=>17/6x=3/2x--4x
=>17/6=x(3/2+4)=>17/6=11/2x=>x=17/33
c.-5(x+1/5)-1/2(x-2/3)=x
=>-5x-1-1/2x+1/3=x=>-11/2x-2/3=x
=>-2/3=x+11/2x=>-2/3=x(1+11/2)=>-2/3=13/2x
=>x=-4/39
a) x : (1/2 + 2/3) = 6/5
=> x : 7/6 = 6/5
=> x = 6/5 x 7/6
x = 7/5
b) , c) ko bít hihi


1.
a)\(0< x-1\le2\)
Mà \(x\in Z\)
\(\Rightarrow x-1\in Z\)
\(\Rightarrow x-1=1\)
\(\Rightarrow x=2\in Z\)
Vậy x=2
Các phần khác bn làm tương tự nha
d)\(\left|x\right|< 3\)
\(\Rightarrow-3< x< 3\)
\(\Rightarrow x\in\left\{-2;-1;0;1;2\right\}\)
Vậy \(x\in\left\{-2;-1;0;1;2\right\}\)
2.
c)Các phần a,b bn tự làm nha
3-|2x+1|=(-5)
\(\Rightarrow\left|2x+1\right|=3-\left(-5\right)\)
\(\Rightarrow\left|2x+1\right|=3+5\)
\(\Rightarrow\left|2x+1\right|=8\)
\(\Rightarrow2x+1=8\) hoặc \(2x+1=-8\)
\(\Rightarrow2x=8-1\) \(\Rightarrow2x=-8-1\)
\(\Rightarrow2x=7\) \(\Rightarrow2x=-9\)
\(\Rightarrow x=\frac{7}{2}=3,5\notin Z\) \(\Rightarrow x=\frac{-9}{2}=-4,5\in Z\)
Vậy \(x\in\varnothing\)
Chúc bn học tốt

\(1,-\frac{1}{5}x-\frac{2}{3}=\frac{1}{10}x+\frac{5}{6}\)
\(-\frac{1}{5}x-\frac{2}{3}-\frac{1}{10}x-\frac{5}{6}=0\)
\(-\frac{3}{10}x-\frac{3}{2}=0\)
\(-\frac{3}{10}x=\frac{3}{2}\)
\(x=-5\)
\(2,2\left(x-\frac{1}{3}\right)-3\left(x-\frac{1}{2}\right)=\frac{1}{2}x\)
\(x-\frac{2}{3}-3x+\frac{3}{2}=\frac{1}{2}x\)
\(-2x+\frac{5}{6}=\frac{1}{2}x\)
\(-2x-\frac{1}{2}x+\frac{5}{6}=0\)
\(-\frac{5}{2}x=-\frac{5}{6}\)
\(x=\frac{1}{3}\)
1/2 * x + 3/5 * x - 2 * 3/5 = 3
x* ( 1/2 + 3/5 ) - 6/5 = 3
x* 11/10 = 21/5
x = 21/5 : 11/10 = 42/11. ( nhớ tk cho mk nha , cảm ơn nhìu ! )
lạc đề rồi đấy