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<=> x\(-10\left(\frac{1}{11x13}+\frac{1}{13x15}+...+\frac{1}{53x55}\right)\)) =\(\frac{3}{11}\)
x\(-10\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{53}-\frac{1}{55}\right)=\frac{3}{11}\)
X-10\(\left(\frac{1}{11}-\frac{1}{55}\right)\)=\(\frac{3}{11}\)
X-\(\frac{40}{55}\)=\(\frac{3}{11}\)
X=\(\frac{3}{11}+\frac{40}{55}=\frac{15+40}{55}=\frac{55}{55}=1\)
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chị ra tay giải cho đứa em cùng tên
50% = 1/2
x/2+2x/3 = x+4
(3x+4x)/6 =x +4
7x/6 - x =4
x/6 = 4
x = 24
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a: x/5=32/80
nên x/5=2/5
hay x=2
13/x=26/30
nên 13/x=13/15
hay x=15
-x/7=22/-77
=>x/7=2/7
hay x=2
b: x/9=28/36
=>x/9=7/9
hay x=7
-10/x=50/55
=>-10/x=10/11
hay x=-11
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x50 = x <=> x50 - x =0 <=> x(x49 - 1) =0
=>\(\orbr{\begin{cases}x=0\\x^{49}-1=0\end{cases}}\)<=>\(\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
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288:(x-3)2=2
=> (x-3)2=144
=>x-3=12(vì x thuộc N)
=> x=15
\(8.6+288:\left(x-3\right)^2=50\)
\(\Rightarrow48+288:\left(x-3\right)^2=50\)
\(\Rightarrow288:\left(x-3\right)^2=50-48=2\)
\(\Rightarrow\left(x-3\right)^2=288:2=144\)
Mà \(\left(x-3\right)^2=144=12^2\)
\(\Rightarrow x-3=12\)
\(\Rightarrow x=12+3\)
\(\Rightarrow x=15\)
\(x^{50}=x\)
\(\Rightarrow x^{50}-x=0\)
\(\Rightarrow x\cdot x^{49}-x\cdot1=0\)
\(\Rightarrow x\cdot\left(x^{49}-1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x^{49}-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x^{49}=1\end{cases}\Rightarrow}\orbr{\begin{cases}x=0\\x=1\end{cases}}}\)
Vậy: \(x\in\left\{0;1\right\}\)
\(x^{50}=x\)
\(x^{50}-x=0\)
\(x.x^{49}-x.1=0\)
\(x.\left(x^{49}-1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x^{49}-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x^{49}=1\Rightarrow x=1\end{cases}}}\)