![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
|x - 3| - 16 = -4
|x - 3| = -4 + 16
|x - 3| = 12
|x| = 12 + 3
|x| = 15
Vậy |x| thuộc { -15 ; 15 }
![](https://rs.olm.vn/images/avt/0.png?1311)
a)Ta thấy x2+4>0 lđ với mọi x
(x-1)(x2+4)<0 <=> x-1<0 <=> x<1
b) Ta có: \(|x-5|\ge0lđ\Leftrightarrow|x-5|+5\ge5\)
Mà \(|x-5|+5=x\)
=> x\(\ge5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
|x/2-1|=3
=>x/2-1=3 hoặc -3
=>x/2= 4 hoặc -2
=>x:2=4 hoặc -2
=>x=2 hoặc -1
b,|x2x2-1|=3 \(\Leftrightarrow\left[{}\begin{matrix}\dfrac{x}{2}-1=3\\\dfrac{x}{2}-1=-3\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}\dfrac{x}{2}=4\\\dfrac{x}{2}=-2\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-1\end{matrix}\right.\)
c, |-x+2525|+1212=3,5 \(\Leftrightarrow\left|-x+\dfrac{2}{5}\right|=3,5-\dfrac{1}{2}\) \(\Leftrightarrow\left|-x+\dfrac{2}{5}\right|=3\) \(\Leftrightarrow\left[{}\begin{matrix}-x+\dfrac{2}{5}=3\\-x+\dfrac{2}{5}=-3\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{13}{5}\\x=\dfrac{-7}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}-x=\dfrac{-13}{5}\\-x=\dfrac{7}{2}\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(\frac{x-1}{9}=\frac{8}{3}\Leftrightarrow\frac{x-1}{9}=\frac{24}{9}\Leftrightarrow x-1=24\Leftrightarrow x=25\)
b, \(\frac{x+2}{3}=\frac{2x-1}{5}\Leftrightarrow\frac{5x+10}{15}=\frac{6x-3}{15}\Leftrightarrow5x+10=6x-3\)
\(\Leftrightarrow5x+10-6x+3=0\Leftrightarrow-x+13=0\Leftrightarrow x=13\)
a) \(\frac{x-1}{9}=\frac{8}{3}\)
\(\Leftrightarrow3\left(x-1\right)=8.9\)
\(\Leftrightarrow3x-3=72\)
\(\Leftrightarrow3x=75\)
\(\Leftrightarrow x=25\)
b) \(\frac{x+2}{3}=\frac{2x-1}{5}\)
\(\Leftrightarrow5\left(x+2\right)=3\left(2x-1\right)\)
\(\Leftrightarrow5x+10=6x-3\)
\(\Leftrightarrow5x-6x=-3-10\)
\(\Leftrightarrow-x=-13\)
\(\Leftrightarrow x=13\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1) tính
a) (-10) : (-5) x (-25) x 20
= 2 x (- 25) x 20
= (- 50) x 20
= - 1000
b) (- 32 - 15) : (-5)
= (-47) : (-5)
= \(\frac{47}{5}\)
c) (-42 + 8) x (-6)
= (- 34) x (- 6)
= 204
2) tìm x
a) \(2\times x-35=15\)
=> \(2\times x=15+35\)
=> \(2\times x=50\)
=> \(x=50:2\)
=> \(x=25\)
b) \(\left|-45\right|-x=20\)
=> \(45-x=20\)
=> \(x=45-20\)
=> \(x=25\)
#)Giải :
Bài 1 :
a)\(\left(-10\right):\left(-5\right).\left(-25\right).20\)
\(=2.\left(-500\right)\)
\(=-1000\)
b)\(\left(-25-15\right):\left(-5\right)\)
\(=\left(-40\right):\left(-5\right)\)
\(=8\)
c)\(\left(-42+8\right).\left(-6\right)\)
\(=\left(-34\right).\left(-6\right)\)
\(=216\)
Bài 2 :
a)\(2x-35=15\)
\(2x=50\)
\(x=25\)
b)\(\left|-45\right|-x=20\)
\(\orbr{\begin{cases}\left|-45\right|>0\\\left|-45\right|< 0\end{cases}\Rightarrow\orbr{\begin{cases}45-x=20\\-45-x=20\end{cases}\Rightarrow}\orbr{\begin{cases}x=25\\x=-65\end{cases}}}\)
Tim x biet
a) x - \(\frac{5}{7}\)=\(\frac{1}{9}\)
b)\(\frac{-3}{7}\)- x = \(\frac{4}{5}+\frac{-2}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x-\frac{5}{7}=\frac{1}{9}\)
\(x=\frac{52}{63}\)
\(\frac{-3}{7}-x=\frac{4}{5}+\frac{-2}{3}\)
\(\frac{-3}{7}-x=\frac{2}{15}\)
\(x=\frac{-59}{105}\)
\(\left(x-1\right)^5=-32\)
\(\left(x-1\right)^5=\left(-2\right)^5\)
\(x-1=-2\)
\(x=-2+1\)
\(x=-1\)