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\(x-3\frac{1}{2}:x=-\frac{20}{7}\)
\(x-\frac{7}{2}:x=-\frac{20}{7}\)
\(x:x=-\frac{20}{7}+\frac{7}{2}\)
\(x=-\frac{40}{14}+\frac{49}{14}\)
\(x=\frac{9}{14}\)
Vậy \(x=\frac{9}{14}\)
\(\frac{3+x}{7+y}=\frac{3}{7}\)
\(\Rightarrow\left(3+x\right)\cdot7=3\cdot\left(7+y\right)\)
\(\Rightarrow21+7x=21+3y\)
\(\Rightarrow7x=3y\)
\(\Rightarrow\frac{x}{y}=\frac{3}{7}\) ; mà x + y = 20
\(\Rightarrow\hept{\begin{cases}x=20:\left(3+7\right)\cdot3=6\\y=20:\left(3+7\right)\cdot7=14\end{cases}}\)
Theo bài ra ta có: \(\frac{3+x}{7+y}\)= \(\frac{3}{7}\)
=> 7.(3+x) = 3.(7+y)
=> 21+7x = 21+3y
=> 7x=3y
=> \(\frac{x}{y}\)=\(\frac{3}{7}\)
Đặt x=3m; y=7m
Theo bài ra ta có: 3m+7m=20
=>10m=20
=> m=2
=> \(\frac{x}{y}\)=\(\frac{3.2}{7.2}\)=\(\frac{6}{14}\)
=> x=6 ; y=14
Ai k mk mk k cho
a) \(\left(3\frac{1}{2}-2x\right).3\frac{1}{3}=7\frac{1}{3}\)
\(\left(\frac{7}{2}-2x\right).\frac{10}{3}=\frac{22}{3}\)
\(\frac{7}{2}-2x=\frac{11}{5}\)
\(2x=\frac{13}{10}\)
\(x=\frac{13}{20}\)
Vậy ...
b) \(\frac{4}{9}x=\frac{9}{8}-0,125\)
\(\frac{4}{9}x=1\)
\(x=\frac{9}{4}\)
Vậy...
\(\frac{5}{6}=\frac{15}{24}\)
\(\frac{4}{7}=\frac{12}{21}\)
\(\frac{3}{9}=\frac{7}{21}\)
\(\frac{-5}{-4}=\frac{20}{16}\)
5/6 = x/24 = 5*24 = 6*x = 120 = 6*x suy ra x= 120:6=20
4/7 = 12/x = 4*x = 7*12 = 4*x = 84 suy ra x= 84:4=21
3/x = 7/21 = 3/x = 1/3 = 3*3 = 1*x = 9 = 1*x suy ra x=9:1=9
x/-4 = 20/16 = x/-4 = 5/4 = x*4 = -4*5 = x*4 = -20 suy ra x=-20:4=-5
Ta có: \(\frac{3-x}{x+2}=\frac{7-x}{x+20}\Rightarrow\left(3-x\right).\left(x+20\right)=\left(x+2\right).\left(7-x\right).\)