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\(\left|x-3\right|=2x+4\)
\(\left|x-3\right|=2x+2\cdot2\)
\(\left|x-3\right|=2\left(x+2\right)\)
\(\Rightarrow\orbr{\begin{cases}x-3=-\left[2\cdot\left(x+2\right)\right]\\x-3=2\left(x+2\right)\end{cases}}\) \(\Rightarrow\orbr{\begin{cases}x-3=-\left[2x+4\right]\\x-3=2x+2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x-3=-2x-4\\x=2x+2+3\end{cases}}\) \(\Rightarrow\orbr{\begin{cases}x=-2x-4+3\\x=2x+5\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-2x-1\\x=2x+5\end{cases}}\) \(.....................\)
Bài 1
\(\left(\frac{1}{2}-x\right)^2=\frac{4}{9}\)
\(\Leftrightarrow\left(\frac{1}{2}-x\right)^2=\left(\frac{2}{3}\right)^2\)
\(\Leftrightarrow\frac{1}{2}-x=\frac{2}{3}\)
\(\Leftrightarrow\frac{3}{6}-\frac{4}{6}=x\)
\(\Leftrightarrow x=\frac{-1}{6}\)
Bài 2
Để \(\frac{2x+1}{x-1}\in Z\)
\(\Leftrightarrow\frac{2X-2+3}{X-1}\in Z\)
\(\Leftrightarrow2+\frac{3}{X-1}\in Z\)
\(\Rightarrow3⋮X-1\)
\(\Rightarrow X-1\inƯ\left(3\right)\)
\(\Rightarrow X-1=\left\{-3,-1,1,3\right\}\)
\(\Rightarrow X=\left\{-2,0,2,4\right\}\)
Tìm x
\(a,2x-25\%=\frac{1}{2}\)
\(b,\left(\frac{3x}{7}+1\right).\left(-0,25\right)=\frac{-1}{28}\)
\(\)
a, \(\frac{64}{2^n}=16\Leftrightarrow\frac{64}{2^n}=\frac{64}{4}\Leftrightarrow2^n=4\Leftrightarrow n=2\)
b, \(\left(\frac{1}{3}\right)^{2n-1}=\left(\frac{1}{3}\right)^3\Leftrightarrow2n-1=3\Leftrightarrow n=2\)
a)\(\frac{64}{2^n}=16\Leftrightarrow2^n.16=64\Leftrightarrow2^n=4\Leftrightarrow2^n=2^2\Leftrightarrow n=2\)
b)\(\left(\frac{1}{3}\right)^{2n-1}=\frac{1}{27}\)
\(\Leftrightarrow\left(\frac{1}{3}\right)^{2n-1}=\left(\frac{1}{3}\right)^3\)
\(\Leftrightarrow2n-1=3\Leftrightarrow2n=4\Leftrightarrow n=2\)
=\(\left(4-2+3\right)\cdot\frac{-1}{2}\)
=\(5\cdot\left(\frac{-1}{2}\right)\)
=\(\frac{5\cdot\left(-1\right)}{2}\)
=\(\frac{-6}{2}\)
\(=\left(-3\right)\)
Có 2 trg hợp nhé: Nếu x là dấu nhân thì thực hiện theo phép nhân
Nếu x là ẩn số thì ko làm đc nhé vì ko có kết quả
Nên làm theo trường hợp 1
\(4.\frac{-1}{2}-2.\frac{-1}{2}+3.\frac{-1}{2}\)\(=\)\(\left(\frac{-1}{2}\right).\left(4-2+3\right)=\left(\frac{-1}{2}\right).5=\frac{-1.5}{2}=\frac{-5}{2}\)
\(a,\frac{2}{3}\cdot x-\frac{4}{7}=\frac{1}{8}\)
\(\Leftrightarrow\frac{2}{3}\cdot x=\frac{1}{8}+\frac{4}{7}\)
\(\Leftrightarrow\frac{2}{3}\cdot x=\frac{7}{56}+\frac{32}{56}\)
\(\Leftrightarrow\frac{2}{3}\cdot x=\frac{39}{56}\)
\(\Leftrightarrow x=\frac{39}{56}:\frac{2}{3}=\frac{39}{56}\cdot\frac{3}{2}=\frac{39\cdot3}{56\cdot2}=\frac{117}{112}\)
\(b,\frac{2}{7}-\frac{8}{9}\cdot x=\frac{2}{3}\)
\(\Leftrightarrow\frac{8}{9}\cdot x=\frac{2}{7}-\frac{2}{3}\)
\(\Leftrightarrow\frac{8}{9}\cdot x=\frac{6}{21}-\frac{14}{21}\)
\(\Leftrightarrow\frac{8}{9}\cdot x=\frac{-8}{21}\)
\(\Leftrightarrow x=\frac{-8}{21}:\frac{8}{9}=\frac{-8}{21}\cdot\frac{9}{8}=\frac{-8\cdot9}{21\cdot8}=\frac{-1\cdot3}{7\cdot1}=\frac{-3}{7}\)
Làm nốt hai bài cuối đi nhé
Study well >_<
Mk k chép lại đề bài nha
a)\(\frac{2}{3}.x=\frac{1}{8}+\frac{4}{7}\)
\(\frac{2}{3}.x=\frac{7}{56}+\frac{32}{56}\)
\(\frac{2}{3}.x=\frac{39}{56}\)
\(x=\frac{39}{56}:\frac{2}{3}\)
\(x=\frac{39}{56}.\frac{3}{2}\)
\(x=\frac{117}{112}\)
Mk sợ sai lém!!!
a) \(\frac{1}{4}+\frac{1}{3}\div\left(2x-1\right)=-5\)
\(\Leftrightarrow\frac{1}{3}\div\left(2x-1\right)=-5-\frac{1}{4}\)
\(\Leftrightarrow\frac{1}{3}\div\left(2x-1\right)=\frac{-20}{4}-\frac{1}{4}\)
\(\Leftrightarrow\frac{1}{3}\div\left(2x-1\right)=\frac{-21}{4}\)
\(\Leftrightarrow\left(2x-1\right)=\frac{1}{3}\div\frac{-21}{4}\)
\(\Leftrightarrow\left(2x-1\right)=\frac{-4}{63}\)
\(\Leftrightarrow2x=\frac{-4}{63}+1\)
\(\Leftrightarrow2x=\frac{-4}{63}+\frac{63}{63}\)
\(\Leftrightarrow2x=\frac{59}{63}\)
\(\Leftrightarrow x=\frac{59}{63}\div2\)
\(\Leftrightarrow x=\frac{59}{126}\)
b) \(-\left(5\frac{3}{8}+x-7\frac{5}{24}\right)\div2019\frac{11}{37}=0\)
\(\Leftrightarrow-\left(5\frac{3}{8}+x-7\frac{5}{24}\right)=0.2019\frac{11}{37}\)
\(\Leftrightarrow-5\frac{3}{8}-x+7\frac{5}{24}=0\)
\(\Leftrightarrow\frac{-43}{8}-x+\frac{173}{24}=0\)
\(\Leftrightarrow\frac{-129}{24}-x+\frac{173}{24}=0\)
\(\Leftrightarrow-x+\frac{44}{24}=0\)
\(\Leftrightarrow x=\frac{44}{24}-0\)
\(\Leftrightarrow x=\frac{44}{24}=\frac{11}{6}\)
\(\frac{2x-1}{-27}=\frac{3}{1-2x}\)
\(\Rightarrow\left(2x-1\right).\left(1-2x\right)=3.\left(-27\right)\)
\(-4x^2=-81\) ( chỗ này bn tự phân tích ra nha!)
\(x^2=\frac{-81}{-4}=\frac{81}{4}=\left(\frac{9}{2}\right)^2=\left(-\frac{9}{2}\right)^2\)
=> x = 9/2 hoặc x = -9/2