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= -7/21 < hoặc bằng X . X < hoặc bằng -6/21
=> X =-7/21 hoặc X = -6/21
\(\Leftrightarrow\frac{-2}{17}\le\frac{x}{17}\le\frac{2}{17}\Rightarrow x\in\left(-2;-1;0;1;2\right)\)
\(\Leftrightarrow\frac{-1}{24}\le\frac{x}{24}\le\frac{5}{24}\Rightarrow x\in\left(-1;0;1;2;3;4;5\right)\)
2 câu sau tự làm nha
\(-\frac{5}{17}+\frac{3}{17}\le\frac{x}{17}\le\frac{13}{17}+-\frac{11}{17}\)
\(\frac{-2}{17}\le\frac{x}{17}\le\frac{2}{17}\)
=> \(x\in\left\{-2;-1;0;1;2\right\}\)
1)
\(\frac{7.8^3-5.2^{10}}{\left(-16\right)^2}\)
= \(\frac{7.2^8.2-5.2^8.2^2}{16^2}\)
= \(\frac{2^8.\left(2.7-5.2^2\right)}{2^8}\)
= \(\frac{2^8.\left(-6\right)}{2^8}\)
= \(-6\)
\(\frac{x}{4}=\frac{18}{x+1}\)
\(\Leftrightarrow\)\(x\left(x+1\right)=4.18\)
\(\Leftrightarrow\)\(x\left(x+1\right)=72\)
\(\Leftrightarrow\)\(x^2+x-72=0\)
\(\Leftrightarrow\)\(\left(x-8\right)\left(x+9\right)=0\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x-8=0\\x+9=0\end{cases}}\)\(\Leftrightarrow\)\(\orbr{\begin{cases}x=8\\x=-9\end{cases}}\)
Vậy....
tim x thuoc Z biet x4 = 18x+1
giup voi
Toán lớp 6
Đường Quỳnh Giang 14 giây trước (18:57)
Thống kê hỏi đáp
Báo cáo sai phạm
x4 =18x+1
⇔x(x+1)=4.18
⇔x(x+1)=72
⇔x2+x−72=0
⇔(x−8)(x+9)=0
⇔[
x−8=0 |
x+9=0 |
⇔[
x=8 |
x=−9 |
Vậy \(x=8\)hoặc \(-9\)
a) \(\frac{x}{3}-\frac{10}{21}=-\frac{1}{7}\)
\(\Rightarrow\frac{x}{3}=-\frac{1}{7}+\frac{10}{21}\)
\(\Rightarrow\frac{x}{3}=\frac{7}{21}\)
\(\Rightarrow\frac{x}{3}=\frac{1}{3}\)
\(\Rightarrow x=1\)
\(x-25\%=\frac{1}{2}\)
\(\Rightarrow x-\frac{1}{4}=\frac{1}{2}\)
\(\Rightarrow x=\frac{1}{2}+\frac{1}{4}\)
\(\Rightarrow x=\frac{3}{4}\)
c) \(-\frac{5}{6}+\frac{8}{3}+-\frac{29}{6}\le x\le-\frac{1}{2}+2+\frac{5}{2}\)
\(\Rightarrow-3\le x\le4\)
\(\Rightarrow x\in\left\{-3;-2;-1;0;1;2;3;4\right\}\)
Câu 2 :
\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)
\(\frac{28}{15}.\frac{3}{4}-\left(\frac{104}{195}+\frac{25}{100}\right).\frac{24}{47}-\frac{51}{13}:3\)
\(\frac{28}{15}.\frac{3}{4}-\frac{47}{60}.\frac{24}{47}-\frac{51}{13}:3\)
\(\frac{7}{5}-\frac{2}{5}-\frac{51}{13}.\frac{1}{3}\)
\(\frac{7}{5}-\frac{2}{5}-\frac{17}{13}\)
\(-\frac{4}{13}\)
\(\frac{-1}{3}\le x\le\frac{-2}{7}\Rightarrow\frac{-7}{21}\le x\le\frac{-6}{21}\Rightarrow x\varepsilon\left\{\frac{-7}{21};\frac{-6}{21}\right\}\)
Nobita kun trả lời đúng đấy