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3x + 5 . 3x+1 = 432
3x + 5 . 3x . 3 = 432
3x + 15 . 3x = 432
3x . ( 1 + 15 ) = 432
3x . 16 = 432
3x = 432 : 16
3x = 27
3x = 33
=> x = 3
Vậy x = 3
3x + 5.3.3x = 432 <=> 3x.( 1+ 5.3) = 432 <=> 3x = 432/16 = 27 = 33 <=> x=3
3.3\(^x\)+5.3\(^{x+1}\) = 16
=> 3\(^{x+1}\) + 5. 3\(^{x+1}\) = 16
=> 3\(^{x+1}\) . ( 1+5 ) = 16
=> 3\(^{x+1}\) . 6 = 16
=> 3\(^{x+1}\) = \(\dfrac{8}{3}\)
=> x không thuộc giá trị nào
\(2^{x+2}-2^x=96\)
\(\Rightarrow2^x\cdot2^2-2^x=96\)
\(\Rightarrow2^x\left(2^2-1\right)=96\)
\(\Rightarrow2^x\left(4-1\right)=96\)
\(\Rightarrow2^x\cdot3=96\)
\(\Rightarrow2^x=96:3\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
\(5^x+5^{x+1}=750\)
\(\Rightarrow5^x+5^x\cdot5=750\)
\(\Rightarrow5^x\left(1+5\right)=750\)
\(\Rightarrow5^x\cdot6=750\)
\(\Rightarrow5^x=750:6\)
\(\Rightarrow5^x=125\)
\(\Rightarrow5^x=5^3\)
\(\Rightarrow x=3\)
\(2^{x+3}+2^x=144\)
\(\Rightarrow2^x\cdot2^3+2^x=144\)
\(\Rightarrow2^x\left(2^3+1\right)=144\)
\(\Rightarrow2^x\cdot9=144\)
\(\Rightarrow2^x=144:9\)
\(\Rightarrow2^x=16\)
\(\Rightarrow2^x=2^4\)
\(\Rightarrow x=4\)
\(3^{x-1}+5.3^{x-1}=486\)
\(\Rightarrow3^{x-1}.\left(5+1\right)=486\)
\(3^{x-1}.6=486\)
\(3^{x-1}=81\)
\(3^{x-1}=3^4\)
\(\Rightarrow x-1=4\)
\(\Rightarrow x=5\)
<=> 3x-1 +5.3x-1 =486
<=> 3x-1 . (1+5) = 486
<=> 3x-1 . 6 =486
<=> 3x-1 = 486 :6
<=> 3x-1 = 81
<=> 3x-1 = 34
<=> X-1=4
<=> X = 4+1
<=> X=5
1 ) <=> 5.3x = 405
<=> 3x = 81 = 34
=> x = 4
2 ) <=> 2x ( 7.23 - 5.22 + 1 ) = 1184
<=> 2x ( 7.8 - 5.4 + 1 ) = 1184
<=> 2x ( 56 - 20 + 1 ) = 1184
<=> 2x . 37 = 1184
<=> 2x = 32 = 25
=> x = 5
1 ) <=> 5.3x = 405
<=> 3x = 81 = 34
=> x = 4
2 ) <=> 2x ( 7.23 - 5.22 + 1 ) = 1184
<=> 2x ( 7.8 - 5.4 + 1 ) = 1184
<=> 2x ( 56 - 20 + 1 ) = 1184
<=> 2x . 37 = 1184
<=> 2x = 32 = 25
=> x = 5
mk để mk đc trong 290đ đc ko!?
66 - 5.3x = 21
5.3x = 66 - 21
5.3x = 45
3x = 45 : 5
3x = 9
3x = 32
x = 2
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