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s1=1+2+3+...+99
s1=99+98+...+1
2s1=100+100+....+100
2s1=100.99
s1=100.99:2=4950(mấy bài sau lam tương tự nha)
4+4^2+4^3+...+4^90 chia hết cho 21
=(4+4^2+4^3)+...+(4^88+4^89+4^90)
=84.1+(4^4+4^5+4^6+...+4^90)
vì 84 chia hết cho 21 suy ra tổng trên chia hét cho 21 (ĐPCM)
a)(x-1)5=(-32)=(-2)5
=>x-1=-2
x=-2+1
x=-1
b)(23/4)*2x+1=64
(8/4)*2x+1=64
2*2x+1=64
2x+1+1=26
=>x+2=6
x=6-2
x=4
\(7^{2x-3}=7^2\cdot5+7^2\cdot2\)
\(7^{2x-3}=7^2\left(5+2\right)\)
\(7^{2x-3}=7^2\cdot7\)
\(7^{2x-3}=7^3\)
\(2x-3=3\)
\(2x=6\)
\(x=3\)
\(7^{2x-3}-2.49=49.5\)
\(7^{2x-3}-2.49=245\)
\(7^{2x-3}-2=245:49\)
\(7^{2x-3}-2=5\)
\(7^{2x-3}=5+2\)
\(7^{2x-3}=7\)
2x-3=1
2x=1+3
2x=4
x=4:2
x=2
vậy x=2
\(\frac{-5}{6}+\frac{8}{3}+\frac{29}{-6}\le x\le\frac{-1}{2}+2+\frac{5}{2}\)
\(\Rightarrow-3\le x\le4\)
\(\Rightarrow x\in\left\{-3;-2;-1;0;1;2;3;4\right\}\)
\(\left(\frac{-2}{3}-\frac{1}{2}\right):\frac{-1}{4}\le x\le\left(\frac{-5}{6}+\frac{9}{4}:\frac{-3}{2}\right)\cdot\frac{-13}{2}\)
\(\Rightarrow\frac{14}{3}\le x\le\frac{91}{6}\)
\(\Rightarrow\frac{28}{6}\le x\le\frac{91}{6}\)
\(\Rightarrow x\in\left\{\frac{28}{6};\frac{29}{6};...;\frac{90}{6};\frac{91}{6}\right\}\)
a: \(S=\dfrac{-1}{2}\cdot\dfrac{-2}{3}\cdot...\cdot\dfrac{-99}{100}=-\dfrac{1}{100}\)
c: \(5S_3=5^6+5^7+...+5^{101}\)
\(\Leftrightarrow4\cdot S_3=5^{101}-5^5\)
hay \(S_3=\dfrac{5^{101}-5^5}{4}\)
d: \(S_4=7\cdot\left(\dfrac{1}{10}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{12}+...+\dfrac{1}{69}-\dfrac{1}{70}\right)\)
\(=7\left(\dfrac{1}{10}-\dfrac{1}{70}\right)=7\cdot\dfrac{6}{70}=\dfrac{6}{10}=\dfrac{3}{5}\)
\(5^{x+2}+5^x=5^2.26\)
\(\Rightarrow5^x\left(5^2+1\right)=5^2.26\)
\(\Rightarrow5^x.26=5^2.26\)
\(\Rightarrow5^x=5^2\)
\(\Rightarrow x=2\)
5x+2 + 5x =52.26
=> 5x . 5 2 + 5x = 25 . 26
=> 5x . 25 + 5x = 650
=> 5x . (1 + 25 ) = 650
=> 5x . 26 = 650
=> 5x = 25
=> 5x = 52
=> x = 2
Vậy x = 2