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l) (x + 9) . (x2 – 25) = 0
<=> (x + 9) . (x – 5) . (x + 5) = 0
<=> \(\left[{}\begin{matrix}\text{x + 9 = 0}\\x-5=0\\x+5=0\end{matrix}\right.\left[{}\begin{matrix}x=-9\\x=5\\x=-5\end{matrix}\right.\)
Vậy S = \(\left\{-9,5,-5\right\}\)
e) |x - 4 |< 7
<=> \(\left[{}\begin{matrix}x-4=7\\x-4=-7\end{matrix}\right.< =>\left[{}\begin{matrix}x=11\\x=-3\end{matrix}\right.\)
Vậy S = \(\left\{11;-3\right\}\)
I,(x+9).(x^2-25)=0
tương đương:x+9=0
x^2-25=0
tương đương : x=-9
x=5
e,\(\left|x-4\right|\)=7
tương đương x-4=4
x-4=-4
tương đương :x=0
x=-8
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\(\frac{-4}{7}=\frac{x-40}{31-5x}\)
\(-4\left(31-5x\right)=7\left(x-40\right)\)
\(-124+20x=7x-280\)
\(20x-7x=124-280\)
\(13x=-156\)
\(x=-12\)
Vậy: \(x\in\left\{-12\right\}\)
=.= hk tốt!!
\(-\frac{4}{7}=\frac{x-40}{31-5x}\)
=> 7 ( x - 40 ) = - 4 ( 31 - 5x )
=> 7x - 7 . 40 = - 4 . 31 + 20x
=> 7x - 280 = - 124 + 20x
=> 124 - 280 = 20x - 7x
=> -156 = 13x
=> x = -12
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Bài 1:
a) Ta có: \(-5x+32=\left(-2\right)^3\)
\(\Leftrightarrow-5x+32=-8\)
\(\Leftrightarrow-5x=-40\)
hay x=8
Vậy: x=8
b) Ta có: \(-2x+36=6\)
\(\Leftrightarrow-2x=6-36=-30\)
hay x=15
Vậy: x=15
e) Ta có: \(\left(x+9\right)\left(x^2-25\right)=0\)
\(\Leftrightarrow\left(x+9\right)\left(x-5\right)\left(x+5\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+9=0\\x-5=0\\x+5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-9\\x=5\\x=-5\end{matrix}\right.\)
Vậy: \(x\in\left\{-9;5;-5\right\}\)
b,-2x+36=6
tương đương -2x=-30
tương đương x=15
a, -5x+32=(-2)^3
tương đương -5x+32=8
tương đương -5x=-24
tương đương x=24/5
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BT1 :thực hành phép tính
4/3+-11/31+3/10-20/31-2/5 = 7/30
7/12-1/-16+3/4 = 67/48
2/11.-5/4+-9/11.5/4+ 1 và 3/4 = -1/4 * và 3/4 là sao bạn *
-9/27-25/75 = -2/3
tìm x,biết
5-x-16=40+x
4x-10=15-x
15-x=4x-5
x-15=6+4x
-12+x=5x-20
7x-4=20+3x
5x-7=-21-2x
x+15=20-4x
17-x=7-6x
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a) 100 - 7 (x - 5) = 31 +33
100 - 7 (x - 5) = 31 + 27
100 - 7 (x - 5) = 58
7 (x - 5) = 100 - 58
7 (x - 5) = 42
x - 5 = 42 : 7
x - 5 = 6
x = 6 + 5
x = 11
b) 24 + 5x = 75 : 73
24 + 5x = 75 - 3
24 + 5x = 72 = 49
5x = 49 - 24
5x = 25
x = 25 : 5
x = 5
mik làm từng bước một nên hơi dài, mong bạn thông cảm nha !!!!
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\(\frac{-4}{-7}=\frac{x-40}{31-5x}\)
\(\Leftrightarrow\frac{4}{7}=\frac{x-40}{31-5x}\)
\(\Leftrightarrow4\left(31-5x\right)=7\left(x-40\right)\)
\(\Leftrightarrow124-20x=7x-280\)
\(\Leftrightarrow-20x-7x=-280-124\)
\(\Leftrightarrow-27x=-404\)
\(\Leftrightarrow x=\frac{404}{27}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 100 - 7 ( x - 5 ) = 31 + 33
100 - 7 ( x - 5 ) = 31 + 27
100 - 7 ( x - 5 ) = 58
7 ( x - 5 ) = 100 - 58
7 ( x - 5 ) = 42
x - 5 = 42 : 7
x - 5 = 6
=> x = 6 +5
=> x = 11
Vậy x = 11
b, 12 ( x - 1 ) : 3 = 43 + 23
12 ( x - 1 ) : 3 = 64 + 8
12 ( x - 1 ) : 3 = 72
12 ( x - 1 ) = 72 . 3
12 ( x - 1 ) = 216
x - 1 = 216 : 12
x - 1 = 18
=> x = 18 + 1
=> x = 19
Vậy x = 19
c, 24 + 5x = 75 : 73
24 + 5x = 72
24 + 5x = 49
5x = 49 - 24
5x = 25
=> x = 25 : 5
=> x = 5
Vậy x = 5
d, 5x - 206 = 24 . 4
5x - 206 = 16 . 4
5x - 206 = 64
5x = 64 + 206
5x = 270
=> x = 270 : 5
=> x = 54
Vậy x = 54
e, 125 = x3
53 = x3
=> x = 5
Vậy x = 5
g, 64 = x2
82 = x2
=> x = 8
Vậy x = 8
Trả lời:
\(\frac{-4}{7}=\frac{x-40}{31-5x}\)
\(\Rightarrow-4\left(31-5x\right)=7\left(x-40\right)\)
\(\Rightarrow-124+20x=7x-280\)
\(\Rightarrow20x-7x=-280+124\)
\(\Rightarrow13x=-156\)
\(\Rightarrow x=-156:13\)
\(\Rightarrow x=-12\)
Vậy x = -12
\(\frac{-4}{7}=\frac{x-40}{31-5x}\)
\(\Rightarrow\)\(\left(-4\right)\left(31-5x\right)=7\left(x-40\right)\)
\(\Rightarrow\)\(-124+20x=7x-280\)
\(\Rightarrow\)\(20x-7x=-280+124\)
\(\Rightarrow\)\(13x=-156\)
\(\Rightarrow\)\(x=-12\)
Vậy \(x=-12\)