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\(\frac{x}{5}=\frac{3}{15}\)suy ra x = 1
\(\frac{x}{7}=\frac{2}{14}\)suy ra x = 1
\(\frac{\left(x+1\right)}{3}=\frac{1}{2}\)suy ra x = \(\frac{1}{2}\)
\(\frac{\left(x-5\right)}{6}=\frac{1}{3}\)suy ra x = 7
\(\frac{\left(x:3\right)}{7}=2\left(\frac{1}{7}\right)\)
\(\frac{\left(x:3\right)}{7}=\frac{15}{7}\)suy ra x = 45
a) \(\frac{2}{3x}=\frac{5}{2}\Leftrightarrow3x=\frac{4}{5}\Rightarrow x=\frac{4}{15}\)
b) \(\frac{x-3}{4}=\frac{1}{2}\Rightarrow x-3=2\Rightarrow x=5\)
c) \(\frac{5}{24+x}=\frac{7}{12}\Rightarrow24+x=\frac{60}{7}\Rightarrow x=\frac{-108}{7}\)
d) \(-6x=18\Rightarrow x=-3\)
a ) \(-\frac{3}{7}.\frac{3}{11}+-\frac{3}{7}.\frac{8}{11}+1\frac{3}{7}\)
\(=-\frac{3}{7}.\left(\frac{3}{11}+\frac{8}{11}\right)+\frac{10}{7}\)
\(=-\frac{3}{7}.\frac{11}{11}+\frac{10}{7}\)
\(=-\frac{3}{7}.1+\frac{10}{7}\)
\(=\frac{10}{7}\)
b ) \(75\%.10,5=\frac{3}{4}.10,5=7,875\)
c ) \(5-3.\left(\left|-4\right|-30:15\right)\)
\(=5-3.\left(4-2\right)\)
\(=5-3.2\)
\(=5-6\)
\(=-1\)
d ) \(-\frac{5}{7}.\frac{2}{11}+-\frac{5}{7}.\frac{9}{11}+1\frac{5}{7}\)
\(=-\frac{5}{7}.\left(\frac{2}{11}+\frac{9}{11}\right)+\frac{12}{7}\)
\(=-\frac{5}{7}.1+\frac{12}{7}\)
\(=\frac{7}{7}\)
\(=1\)
Chúc bạn học tốt !!!
\(\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{x\left(x+2\right)}=\frac{11}{75}\)
\(\Leftrightarrow\frac{1}{2}\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{x}-\frac{1}{x+2}\right)=\frac{11}{75}\)
\(\Leftrightarrow\frac{1}{3}-\frac{1}{x+2}=\frac{11}{75}:\frac{1}{2}=\frac{22}{75}\Leftrightarrow\frac{1}{x+2}=\frac{1}{25}\Leftrightarrow x=23\)
Ta có:\(\left(3\frac{1}{2}-2.x\right).\frac{1}{3}=7\frac{1}{3}\)
\(\Rightarrow\left(\frac{7}{2}-2.x\right).\frac{1}{3}=\frac{22}{3}\)
\(\Rightarrow\frac{7}{2}-2.x=\frac{22}{3}:\frac{1}{3}=22\)
\(\Rightarrow2.x=\frac{7}{2}-22=\frac{-37}{2}\)
\(\Rightarrow x=\frac{-37}{2}:2=\frac{-37}{4}\)