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2346 : (25 + x) = 23
=> 25 + x = 2346 : 23 = 102
=> x = 102 - 25 = 77
Vậy x = 77
2(x-3) + 5(x+4) = 49
=> 2x - 6 + 5x + 20 = 49
=> 7x + (20 - 6) = 49
=> 7x + 14 = 49
=> 7x = 49 - 14 = 35
=> x = 35 : 7 = 5
Vậy x = 5
(2x-10)3 . 251007 = \(5^2.5^{2015}\)
\(\left(2x-10\right)^3.5^{2014}=5^{2014}.5^3\)
\(\left(2x-10\right)^3=5^3\)
2x - 10 = 5
=> 2x = 5 + 10 = 15
=> x = 15 2 = 7,5
Vậy x = 7,5
1. a. 2346:(25+x)=23
=> 25+x=2346:23
=> 25+x=102
=> x=102-25
=> x=77
b. 2(x-3)+5(x+4)=49
=> 2x-6+5x+20=49
=> 7x+14=49
=> 7x=49-14
=> 7x=35
=> x=35:7
=> x=5
c. (2x-10)3.251007=52.52015
=> (2x-10)3.(52)1007=52017
=> (2x-10)3.52014=52017
=> (2x-10)3=52017:52014
=> (2x-10)3=53
=> 2x-10=5
=> 2x=5+10
=> 2x=15
=> x=15:2
=> x=7,5
\(a,\left(7x-11\right)^3=2^5.5^2+200.\)
\(\left(7x+11\right)^3=32.25+200.\)
\(\left(7x+11\right)^3=800+200.\)
\(\left(7x-11\right)^3=1000.\)
\(\left(7x-11\right)^3=10^3.\)
\(\Rightarrow7x-11=10.\)
\(\Rightarrow x=\left(10+11\right):3=7\in Z.\)
Vậy.....
\(b,3^x+25=26.2^2+2.3^0.\)
\(3^x+25=26.4+2.\)
\(3^x+25=104+2.\)
\(3^x+25=106.\)
\(3^x=106-25.\)
\(3^x=81.\)
\(3^x=3^4\Rightarrow x=4\in Z.\)
Vậy.....
\(c,2^x+3.2=64.\)(có vấn đề).
\(d,5^{x+1}+5^x=750.\)
\(5^x.5^1+5^x+1=750.\)
\(5^x\left(5^1+1\right)=750.\)
\(5^x\left(5+1\right)=750.\)
\(5^x.6=750.\)
\(5^x=750:6.\)
\(5^x=125.\)
\(5^x=5^3\Rightarrow x=3\in Z.\)
Vậy.....
\(e,x^{15}=x.\)
\(\Rightarrow x\left(x^{14}-1\right)=0\Rightarrow\left\{{}\begin{matrix}x=0\\x=1\end{matrix}\right..\)
\(f,\left(x-5\right)^4=\left(x-5\right)^6.\)
\(\Leftrightarrow\left(x-5\right)^4-\left(x-5^6\right)=0.\)
\(\Leftrightarrow\left(x-5\right)^4\left[1-\left(x-5\right)^2\right]=0.\)
\(\Leftrightarrow\left(x-5\right)^4\left(1-x+5\right)\left(1+x-5\right)=0.\)
\(\Leftrightarrow\left(x-5\right)^4\left(6-x\right)\left(x-4\right)=0.\)
\(\Leftrightarrow\left(x-5\right)^4=0\Rightarrow x-5=0\Rightarrow x=5\in Z.\)
\(6-x=0\Rightarrow x=6\in Z.\)
\(x-4=0\Rightarrow x=4\in Z.\)
Vậy.....
a) 5x * 5 = 54
5x+1 = 54
=> x = 3
c) (x-1)2=25
(x-1)2=52
x - 1 = 5
x = 6
a, 5x . 5 = 54
=> 5x + 1 = 54
=> x + 1 = 4
=> x = 3
vậy_
câu b đề k rõ
c, (x - 1)2 = 25
=> (x - 1)2 = (+ 5)2
=> x - 1 = + 5
=> x = 6 hoặc x = -4
\(5^{-3}.5^{2x}=5^{3x}\)
\(\Rightarrow5^{-3}=5^{3x}\div5^{2x}\)
\(\Rightarrow5^{-3}=5^x\)
\(\Rightarrow x=-3\)
5-3 . 25x = 53x
5-3 . (52)x=53x
5-3 = 53x : 52x
5-3 = 5x
x = -3
đúng 100% nhé bn
a, 2x - 20 = 35 : 32
=> 2x - 1 = 33
=> 2x - 1 = 27
=> 2x = 28
=> x = 14
b, 525.5x + 1 = 525
=> 525+x+1 = 525
=> 25 + x + 1 = 25
=> 26 + x = 25
=> x = -1
a. 2x - 20 = 35 : 32
2x - 1 = 33
2x = 27 + 1
2x = 28
x = 28 : 2
x = 14.
Tìm x , biết:
a, ( 2x + 1)2 = 93
b, ( 2x + 1)3 = 1252
c, 252< 5x+3 < 254
d, x15= x
e, ( x - 5)4 = ( x-5)6
A) \(\left(2x+1\right)^2=9^3\)
\(\Rightarrow\left(2x+1\right)^2=9^2\times9\)
\(\Rightarrow2x+1=81\)
\(\Rightarrow2x=81-1\)
\(\Rightarrow2x=80\)
\(\Leftrightarrow x=40\)
B) \(\left(2x+1\right)^3=125^2\)
\(\Rightarrow\left(2x+1\right)^3=5^3\)
\(\Rightarrow2x+1=5\)
\(\Rightarrow2x=5-1\)
\(\Leftrightarrow x=2\)
C) \(25^2< 5^{x+3}< 25^4\)
\(\Leftrightarrow5^4< 5^{x+3}< 5^6\)
\(\Leftrightarrow4< x+3< 6\)
\(\Rightarrow x+3=5\)
\(\Rightarrow x=2\)
D) \(x^{15}=x\)
Nếu \(x>1\)thì \(x^{15}>x\)
Vậy \(x=1\)
E) \(\left(x-5\right)^4=\left(x-5\right)^6\)
\(\Rightarrow\left(x-5\right)^4-\left(x-5\right)^6=0\)
\(\Rightarrow\left(x-5\right)\times\left(1^4-1^6\right)=0\)
\(\Rightarrow x-5=0\)
\(\Leftrightarrow x=5\)
KÍCH MK NHA BẠN
a) 2(x-1)^2=800 5^x+1.5^5=5^9
(x-1)^2=800:2 5^x.5.5^5=5^9
(x-1)^2=400 5^x.5^6=5^9
(x-1)^2=20^2 5^x=5^9:5^6
(x-1)=20 5^x=5^3
x=20+1 => x=3
x=21
c) 25^2 : 5(x-1)=25 d)4^x . 7 +8^2=176
625:5(x-1)=25 4^x . 7+64=176
5(x-1)=625:25 4^x . 7=176:64
5(x-1)=25 4^x . 7=112
x-1=25:5 4^x =112:7
x-1=5 4^x=16
x=5+1 mà 16=4^2
x=6 =>4^x=4^2
=>x=2
bài e) mình ko biết !! ^.^