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bài 1:
a) \(4\dfrac{1}{2}x:\dfrac{5}{12}=0,5\) ; b)\(1,5+1\dfrac{1}{4}x=\dfrac{2}{3}\)
\(\dfrac{9}{2}x:\dfrac{5}{12}=\dfrac{1}{2}\) \(\dfrac{3}{2}+\dfrac{5}{4}x=\dfrac{2}{3}\)
\(\dfrac{9}{2}x\) \(=\dfrac{1}{2}.\dfrac{5}{12}\) \(\dfrac{5}{4}x=\dfrac{2}{3}-\dfrac{3}{2}\)
\(\dfrac{9}{2}x\) \(=\dfrac{5}{24}\) \(\dfrac{5}{4}x=\dfrac{-5}{6}\)
\(x\) \(=\dfrac{5}{24}:\dfrac{9}{2}\) \(x=\dfrac{-5}{6}:\dfrac{5}{4}\)
\(x\) \(=\dfrac{5}{108}\) \(x=\dfrac{-2}{3}\)
c) Cho mình hỏi x ở đâu vậy ???
d)\(\left(x-5\right):\dfrac{1}{3}=\dfrac{2}{5}\) e)\(\left(4,5-2x\right):\dfrac{3}{4}=1\dfrac{1}{3}\)
\(\left(x-5\right)\) \(=\dfrac{2}{5}.\dfrac{1}{3}\) \(\left(\dfrac{9}{2}-2x\right):\dfrac{3}{4}=\dfrac{4}{3}\)
\(x-5\) \(=\dfrac{2}{15}\) \(\dfrac{9}{2}-2x\) =\(\dfrac{4}{3}.\dfrac{3}{4}\)
\(x\) \(=\dfrac{2}{15}+5\) \(\dfrac{9}{2}-2x=1\)
\(x\) \(=\dfrac{77}{15}\) \(2x=\dfrac{9}{2}-1\)
f) \(\left(2,7x-1\dfrac{1}{2}x\right):\dfrac{2}{7}=\dfrac{-21}{7}\) \(2x=\dfrac{7}{2}\)
\(\left(\dfrac{27}{10}x-\dfrac{3}{2}x\right):\dfrac{2}{7}=-3\) \(x=\dfrac{7}{2}:2\)
\(\left[x\left(\dfrac{27}{10}-\dfrac{3}{2}\right)\right]=-3.\dfrac{2}{7}\) \(x=\dfrac{7}{4}\)
\(x.\dfrac{6}{5}=\dfrac{-6}{7}\)
\(x=\dfrac{-6}{7}:\dfrac{6}{5}\)
\(x=\dfrac{-5}{7}\)
bài 2:
Theo bài ra ta có :\(\dfrac{a}{27}=\dfrac{-5}{9}=\dfrac{-45}{b}\)
\(\Rightarrow9a=27.\left(-5\right)\Rightarrow a=\dfrac{27.\left(-5\right)}{9}=-15\)
\(\Rightarrow\left(-5\right)b=\left(-45\right).9\Rightarrow b=\dfrac{\left(-45\right).9}{-5}=81\)
Vậy \(a=-15;b=81\)
9) \(\dfrac{x}{4}=\dfrac{9}{x}\)
Theo định nghĩa về hai phân số bằng nhau, ta có:
\(4\cdot9=x^2\\ 36=x^2\Rightarrow\left[{}\begin{matrix}x=6\\x=-6\end{matrix}\right.\)
8)
\(x:\dfrac{5}{3}+\dfrac{1}{3}=-\dfrac{2}{5}\\ x:\dfrac{5}{3}=-\dfrac{2}{5}+\dfrac{1}{3}\\ x:\dfrac{5}{3}=-\dfrac{1}{15}\\ x=\dfrac{1}{15}\cdot\dfrac{5}{3}\\ x=\dfrac{1}{9}\)
7)
\(2x-16=40+x\\ 2x-x=40+16\\ x\left(2-1\right)=56\\ x=56\)
6)
\(1\dfrac{1}{2}+x=\dfrac{3}{2}-7\\ \dfrac{3}{2}+x=\dfrac{3}{2}-7\\ \dfrac{3}{2}-\dfrac{3}{2}=-7-x\\ -7-x=0\\ x=-7-0\\ x=-7\)
5)
\(3\dfrac{1}{2}-\dfrac{1}{2}x=\dfrac{2}{3}\\ \dfrac{7}{2}-\dfrac{1}{2}x=\dfrac{2}{3}\\ \dfrac{1}{2}x=\dfrac{7}{2}-\dfrac{2}{3}\\ \dfrac{1}{2}x=\dfrac{17}{6}\\ x=\dfrac{17}{6}:\dfrac{1}{2}\\ x=\dfrac{17}{3}\)
4)
\(x\cdot\left(x+1\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x+1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=-1\end{matrix}\right.\)
3)
\(\left(\dfrac{2x}{5}+2\right):\left(-4\right)=-1\dfrac{1}{2}\\ \left(\dfrac{2x}{5}+2\right):\left(-4\right)=-\dfrac{3}{2}\\ \dfrac{2x}{5}+2=-\dfrac{3}{2}\cdot\left(-4\right)\\ \dfrac{2x}{5}+2=6\\ \dfrac{2x}{5}=6-2\\ \dfrac{2x}{5}=4\\ 2x=4\cdot5\\ 2x=20\\ x=20:2\\ x=10\)
2)
\(\dfrac{1}{3}+\dfrac{1}{2}:x=-0,25\\ \dfrac{1}{3}+\dfrac{1}{2}:x=-\dfrac{1}{4}\\ \dfrac{1}{2}:x=-\dfrac{1}{4}-\dfrac{1}{3}\\ \dfrac{1}{2}:x=-\dfrac{7}{12}\\ x=\dfrac{1}{2}:-\dfrac{7}{12}\\ x=-\dfrac{6}{7}\)
1)
\(\dfrac{4}{3}+x=\dfrac{2}{15}\\ x=\dfrac{2}{15}-\dfrac{4}{3}x=-\dfrac{6}{5}\)
a, \(2x+\dfrac{1}{4}=\dfrac{3}{2}.\)
\(2x=\dfrac{3}{2}-\dfrac{1}{4}.\)
\(2x=\dfrac{6}{4}-\dfrac{1}{4}.\)
\(2x=\dfrac{5}{4}.\)
\(x=\dfrac{5}{4}:2\)
\(x=\dfrac{5}{4.2}=\dfrac{5}{8}.\)
b, \(\left(x-5\right)-\dfrac{1}{3}=\dfrac{2}{5}.\)
\(\left(x-5\right)=\dfrac{2}{5}+\dfrac{1}{3}.\)
\(\left(x-5\right)=\dfrac{6}{15}+\dfrac{5}{15}.\)
\(\left(x-5\right)=\dfrac{11}{15}\)
\(x=\dfrac{11}{15}+5.\)
\(x=\dfrac{11}{15}+\dfrac{75}{15}.\)
\(x=\dfrac{86}{15}.\)
c, \(\left(4,5-2x\right):\dfrac{3}{4}=1\dfrac{1}{3}.\)
\(\left(4,5-2x\right)=1\dfrac{1}{3}.\dfrac{3}{4}.\)
\(\left(4,5-2x\right)=\dfrac{4}{3}.\dfrac{3}{4}.\)
\(4,5-2x=1.\) (vì 2 phân số \(\dfrac{4}{3}\) và \(\dfrac{3}{4}\) nghịch đảo nhau).
\(2x=4,5-1.\)
\(2x=3,5.\)
\(x=3,5:2.\)
\(x=1,75.\)
~ Chúc bn học tốt!!! ~
Bài mik đúng thì nhớ tick mik nha!!! :) :) :)
a;\(\dfrac{-6}{11}\) : \(\dfrac{12}{55}\) = \(\dfrac{-5}{2}\)
b;\(\dfrac{7}{12}\) + \(\dfrac{5}{72}\) - \(\dfrac{11}{36}\) = \(\dfrac{47}{72}\) - \(\dfrac{11}{36}\) = \(\dfrac{25}{72}\)
c;\(\dfrac{13}{10}\) : \(\dfrac{-5}{13}\) = \(\dfrac{-169}{50}\)
d; {\(\dfrac{5}{12}\) + \(\dfrac{5}{11}\) } : { \(\dfrac{5}{3}\) -\(\dfrac{7}{11}\) } = \(\dfrac{115}{132}\) : \(\dfrac{34}{33}\) = \(\dfrac{115}{136}\)
lưu ý mk ko chép đầu bài
mình cần gấp lắm đến chiều mai là phải nộp rùi
giúp mình nha thanks cá bạn trước 
ko có tâm trạng mà cười nữa
a) \(\left(3\dfrac{1}{3}-x\right)1\dfrac{1}{6}=\dfrac{7}{24}\)
\(\Leftrightarrow\left(\dfrac{10}{3}-x\right)\dfrac{7}{6}=\dfrac{7}{24}\)
\(\Leftrightarrow\dfrac{10}{3}-x=\dfrac{7}{24}:\dfrac{7}{6}\)
\(\Leftrightarrow\dfrac{10}{3}-x=\dfrac{1}{4}\)
\(\Leftrightarrow x=\dfrac{10}{3}-\dfrac{1}{4}\)
\(\Leftrightarrow x=\dfrac{37}{12}\).
b) \(\left(4,5-2x\right):\dfrac{3}{4}=1\dfrac{1}{3}\)
\(\Leftrightarrow\left(4,5-2x\right):\dfrac{3}{4}=\dfrac{4}{3}\)
\(\Leftrightarrow4,5-2x=\dfrac{4}{3}.\dfrac{3}{4}\)
\(\Leftrightarrow4,5-2x=1\)
\(\Leftrightarrow2x=4,5-1\)
\(\Leftrightarrow2x=3,5\)
\(\Leftrightarrow x=\dfrac{35}{2}\).
1) \(x+\dfrac{30}{100}x=-1,31\)
\(\Leftrightarrow x+\dfrac{3}{10}x=-\dfrac{131}{100}\)
\(\Leftrightarrow100x+30x=-131\)
\(\Leftrightarrow130x=-131\)
\(\Leftrightarrow x=-\dfrac{131}{130}\)
Vậy \(x=-\dfrac{131}{130}\)
b) \(\left(4,5-2x\right)\cdot\left(-1\dfrac{4}{7}\right)=\dfrac{11}{4}\)
\(\Leftrightarrow\left(\dfrac{9}{2}-2x\right)\cdot\left(-\dfrac{4}{7}\right)=\dfrac{11}{4}\)
\(\Leftrightarrow-\dfrac{18}{7}+\dfrac{8}{7}x=\dfrac{11}{4}\)
\(\Leftrightarrow-72+32x=77\)
\(\Leftrightarrow32x=77+72\)
\(\Leftrightarrow32x=149\)
\(\Leftrightarrow x=\dfrac{149}{32}\)
Vậy \(x=\dfrac{149}{32}\)
Các bạn ơi,mình ghi thiếu,còn 3 câu nữa nha!!!~~nya
e)| \(\dfrac{5}{2}\)x-\(\dfrac{1}{2}\) |-(-22).\(\dfrac{1}{3}\)(0,75-\(\dfrac{1}{7}\))=\(\dfrac{-5}{13}\):2\(\dfrac{9}{13}\)-0,5.(\(\dfrac{-2}{3}\))
f)| 5x+21 | = | 2x -63 |
g) -45 - |-3x-96 | - 54=-207
Làm ơn giúp mình với ạ!Mình đang cần gấp lắm trong ngày hôm nay ạ!!!Mình xin cảm ơn các bạn nhiều nhiều lắm luôn đó!!!Thank you very much!!!(^-^)
a, (\(\dfrac{2}{9}\)(6x - \(\dfrac{3}{4}\)) - 3(\(\dfrac{1}{4}x-\dfrac{1}{5}\)) = \(\dfrac{-8}{15}\)
<=> (\(\dfrac{4}{3}x-\dfrac{1}{6}\)) - (\(\dfrac{3}{4}x-\dfrac{3}{5}\)) = \(\dfrac{-8}{15}\)
<=> \(\dfrac{4}{3}x-\dfrac{1}{6}-\dfrac{3}{4}x+\dfrac{3}{5}=\dfrac{-8}{15}\)
<=> \(\dfrac{7}{12}x+\dfrac{13}{30}=\dfrac{-8}{15}\)
<=> \(\dfrac{7}{12}x=\dfrac{-8}{15}-\dfrac{13}{30}\)
<=> \(\dfrac{7}{12}x=-\dfrac{29}{30}\)
<=> x = \(-\dfrac{58}{35}\)
@Nguyễn Gia Hân
các bạn ơi giúp mìh với mìh đag cần gấp ai nhanh và đúng thì mih tick cho
a: \(\Leftrightarrow\dfrac{8}{5}+\dfrac{2}{5}\cdot x=\dfrac{16}{5}\)
=>2/5x=8/5
=>x=4
b: \(\Leftrightarrow\left(\dfrac{1}{24}-\dfrac{1}{25}+\dfrac{1}{25}-\dfrac{1}{26}+...+\dfrac{1}{39}-\dfrac{1}{40}\right)\cdot120+\dfrac{1}{3}x=-4\)
\(\Leftrightarrow x\cdot\dfrac{1}{3}+2=-4\)
=>1/3x=-6
=>x=-18
c: =>2|x-1/3|=0,24-4/5=-0,56<0
a)
\(\dfrac{1}{2}x+\dfrac{1}{8}x=\dfrac{3}{4}\\ x\left(\dfrac{1}{2}+\dfrac{1}{8}\right)=\dfrac{3}{4}\\ x\cdot\dfrac{5}{8}=\dfrac{3}{4}\\ x=\dfrac{3}{4}:\dfrac{5}{8}=\dfrac{6}{5}\)
b)
\(\left(2x-4,5\right):\dfrac{3}{4}-\dfrac{1}{3}=1\\\left(2x-\dfrac{9}{2}\right):\dfrac{3}{4}-\dfrac{1}{3}=1\\ \left(2x-\dfrac{9}{2}\right):\dfrac{3}{4}=1+\dfrac{1}{3}=\dfrac{4}{3}\\ \left(2x-\dfrac{9}{2}\right)=\dfrac{4}{3}\cdot\dfrac{3}{4}=1\\ 2x=1+\dfrac{9}{2}=\dfrac{11}{2}\\ x=\dfrac{11}{2}:2=\dfrac{11}{4}\)
a) 1/2 . x + 1/8 . x = 3/4
<=> ( 1/2 + 1/8 ) . x = 3/4
<=> ( 4/8 + 1/8 ) . x = 3/4
<=> 5/8 . x = 3/4
<=> x = 3/4 . 8/5
<=> x = 6/5
Vậy x = 6/5
b) ( 2x - 4,5 ) : 3/4 - 1/3 = 1
<=> ( 2x - 45/10 ) : 3/4 - 1/3 = 1
<=> ( 2x - 9/2 ) : 3/4 - 1/3 = 1
<=> ( 2x - 9/2 ) : 3/4 = 1 + 1/3
<=> ( 2x - 9/2 ) : 3/4 = 4/3
<=> 2x - 9/2 = 4/3 . 3/4
<=> 2x - 9/2 = 1
<=> 2x = 1 + 9/2
<=> 2x = 11/2
<=> x = 11/2 . 1/2
<=> x = 11/4
Vậy x = 11/4