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a) 3x = 3-12. 3-15 . 332 =35
x = 5
b) 2x = 29 .2-30. 29 = 2-12
x = -12
c) 2x = 214 / 29 = 25
x = 5
Câu 9:
\(3^x=9^{-6}\cdot27^{-6}\cdot81^8\)
\(\Leftrightarrow3^x=\dfrac{1}{9^6\cdot27^6}\cdot81^8=\dfrac{1}{3^{12}\cdot3^{18}}\cdot3^{32}=3^2\)
=>x=2
Câu 18:
\(4^{x+3}-3\cdot4^{x+1}=13\cdot4^{11}\)
\(\Leftrightarrow4^x\cdot64-3\cdot4^x\cdot4=13\cdot4^{11}\)
\(\Leftrightarrow4^x\left(64-3\cdot4\right)=13\cdot4^{11}\)
\(\Leftrightarrow4^x=13\cdot4^{10}\cdot4:52=4^{10}\)
=>x=10
a)\(\left(-3\right)^{x+3}=-\frac{1}{27}\)
\(\left(-3\right)^{x+3}=\left(-\frac{1}{3}\right)^3\)
\(\left(-3\right)^{x+3}=\left(-\frac{3^0}{3^1}\right)^3\)
\(\left(-3\right)^{x+3}=\left(-3^{-1}\right)^3\)
\(\left(-3\right)^{x+3}=\left(-3\right)^{-3}\)
\(\Rightarrow x+3=-3\)
\(\Rightarrow x=-6\)
b)\(\left(-6\right)^{2x+2}=\frac{1}{36}\)
\(\left(-6\right)^{2x+2}=\left(-\frac{1}{6}\right)^2\)
\(\left(-6\right)^{2x+2}=\left(-\frac{6^0}{6^1}\right)^2\)
\(\left(-6\right)^{2x+2}=\left(-6^{-1}\right)^2\)
\(\left(-6\right)^{2x+2}=\left(-6\right)^{-2}\)
\(\Rightarrow2x+2=-2\)
\(\Rightarrow2x=-4\)
\(\Rightarrow x=-2\)
c)\(\left(-3\right)^{x+5}=\frac{1}{81}\)
\(\left(-3\right)^{x+5}=\left(-\frac{1}{3}\right)^4\)
\(\left(-3\right)^{x+5}=\left(-\frac{3^0}{3^1}\right)^4\)
\(\left(-3\right)^{x+5}=\left(-3^{-1}\right)^4\)
\(\left(-3\right)^{x+5}=\left(-3\right)^{-4}\)
\(\Rightarrow x+5=-4\)
\(\Rightarrow x=-9\)
d)\(\left(\frac{1}{9}\right)^x=\left(\frac{1}{27}\right)^6\)
\(\left[\left(\frac{1}{3}\right)^2\right]^x=\left[\left(\frac{1}{3}\right)^3\right]^6\)
\(\left(\frac{1}{3}\right)^{2x}=\left(\frac{1}{3}\right)^{18}\)
\(\Rightarrow2x=18\)
\(\Rightarrow x=9\)
e)\(\left(\frac{4}{9}\right)^x=\left(\frac{8}{27}\right)^6\)
\(\left[\left(\frac{2}{3}\right)^2\right]^x=\left[\left(\frac{2}{3}\right)^3\right]^6\)
\(\left(\frac{2}{3}\right)^{2x}=\left(\frac{2}{3}\right)^{18}\)
\(\Rightarrow2x=18\)
\(\Rightarrow x=9\)
1) MK không chép lại đề nữa nhé!
3x = (32 ) -6 . (33 ) -5 . (34)8
3 x = 3-12.3-15 . 332
3x= 3-27.332
3x= 35
=>x= 5
Vậy x=5
h) \(5^x+5^{x+2}=650\)
\(\Leftrightarrow5^x+5^x.5^2=650\)
\(\Leftrightarrow5^x\left(1+25\right)=650\)
\(\Leftrightarrow5^x.26=650\)
\(\Leftrightarrow5^x=25\)
\(\Leftrightarrow x=2\)
haizzz,đăng ít thôi,chứ nhìn hoa mắt quá =.=
bây định làm j ở chỗ này vậy??? có j ib ns vs nhao chớ sao ns ở đây
a) Ta có: \(\frac{x^7}{81}=27\)
\(\Rightarrow x^7=27.81=2187\)
Mà \(2187=3^7\) \(\Rightarrow x^7=3^7\Leftrightarrow x=3\)
Vậy x = 3
b) Ta có: \(\frac{x^8}{9}=729\)
\(\Rightarrow x^8=729.9=6561\)
Mà \(6561=3^8\) \(\Rightarrow x^8=3^8\Leftrightarrow x=3\)
Vậy x = 3
CHÚC BẠN HỌC TỐT
1: \(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{8}\right)^6\)
\(\Leftrightarrow\left(\dfrac{1}{2}\right)^{4x}=\left(\dfrac{1}{2}\right)^{18}\)
=>4x=18
hay x=9/2
2: \(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{8}\right)^{36}\)
\(\Leftrightarrow\left(\dfrac{1}{2}\right)^{4x}=\left(\dfrac{1}{2}\right)^{108}\)
=>4x=108
hay x=27
3: \(\left(\dfrac{1}{81}\right)^x=\left(\dfrac{1}{27}\right)^4\)
\(\Leftrightarrow\left(\dfrac{1}{3}\right)^{4x}=\left(\dfrac{1}{3}\right)^{12}\)
=>4x=12
hay x=3
\(3^x=9^{-6}.27^{-5}.81^8\)
\(3^x=\left(3^2\right)^{-6}.\left(3^3\right)^{-5}.\left(3^4\right)^8\)
\(3^x=3^{2.\left(-6\right)}.3^{3.\left(-5\right)}.3^{4.8}\)
\(3^x=3^{-12}.3^{-15}.3^{32}\)
\(3^x=3^{\left(-12\right)+\left(-15\right)+32}\)
\(3^x=3^5\)
\(\Rightarrow x=5\)
\(3^x=9^{-6}.27^{-5}.81^8\)
\(3^x=3^{-12}.3^{-15}.3^{32}=3^5\)
\(x=5\left(dox\ne\pm1;0\right)\)
Vậy...