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\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5750\)
\(\left(x+x+x+...+x\right)+\left(1+2+3+...+100\right)=5750\)
\(\Rightarrow100x+5050=5750\Rightarrow x=5750-5050\)
\(100x=700\Rightarrow x=700:100=7\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a ) (x+1)+...+(x+100)
= (x+x+..+x)+(1+..+100)
=100x + (100+1).100:2
=100x + 5050
=5750
<=> 100x = 5750 - 5050
<=> 100x = 700
=> x = 700 : 100 = 7
b) 720 : [ 41-(2x-5)]= 40
41-(2x-5) = 720 : 40
41-(2x-5) = 18
2x-5 = 41-18= 23
2x = 23+5 = 28
=> x = 28:2 = 14
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720:[41-(2x - 5)]=23.5
720:[41-(2x - 5)]=8.5
720:[41-(2x - 5)]=40
41-(2x - 5)=720:40
41-(2x - 5)=18
2x - 5=41-18
2x - 5=23
2.x=23+5
2.x=28
x=28:2
x=14
![](https://rs.olm.vn/images/avt/0.png?1311)
720 : [41-(2x-5)] =2^3 . 5
<=> 41-(2x-5)=720:40=18
<=> 2x-5=41-18=23
<=>2x=23+5=28
<=> x=28:2=14
2^x-15=17
<=> 2^x=17+15=32
<=> 2^x=2^5
<=> x=5
(7x-11)^3= 2^5.5^2+200
<=> (7x-11)^3=1000
<=> (7x-11)^3=10^3
<=> 7x-11=10
<=> 7x=10+11=21
<=> x=21:7=3
![](https://rs.olm.vn/images/avt/0.png?1311)
720 : [ 41 - (2x - 5)] = 23 . 5
=> 720 : [ 41 - ( 2x - 5)] = 40
=> 41 - (2x - 5) = 18
=> 2x - 5 = 23
=> 2x = 28
=> x = 14
Vậy x = 14
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : 53.5x-2= 252
=> 5x+1=(52)2=54
=> x+1 = 4
=> x=4-1=3
vậy .....
A) 720 : (41 - x) = 23. 5
= 720 : (41 - x) = 40
=> 41-x=720 : 40 = 18
=> x = 41-18=23
vậy x =23
Sửa đề :
720 : [ 41-(2x-5)]=23.5
Giải :
720 : [ 41-(2x-5)]=23.5
=> 720:[41-(2x-5)]=40
=> 41-(2x-5)=18
=> 2x-5=23
=> 2x=28
=> x = 14
14