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a,1/3.x+1/4=7/12
1/3.x=7/12-1/4
1/3.x=1/3
x=1/3:1/3
x=1
b,x-40%.x=-3,6
x^2-4 phần 100=-3,6
x^2 =-3,6+40phaanf 100
x^2=-3,2
x=-1,6
(3^3)^2 + 2^x = 733
729 + 2^x = 733
2^x = 733 - 729
2^x = 4
Vậy x = 2
k cho mình nha
e: =>-40+3+33+40-x=47
=>36-x=47
=>x=-11
f: =>x(x-3)(11-x)(11+x)=0
hay \(x\in\left\{0;3;11;-11\right\}\)
g: =>-62-38-x+2x=-100
=>x-100=-100
hay x=0
i: =>x-12-2x-31=6
=>-x-43=6
=>x+43=-6
hay x=-49
h: =>(x+1)=0
=>x=-1
f: =>x(x-3)(x+11)(x-11)=0
hay \(x\in\left\{0;3;-11;11\right\}\)
\(\left(19x+2,25\right)\div14=\left(13-8\right)^2-4\)
\(\left(19x+\frac{9}{4}\right)\div14=\left(13-8\right)^2-4\)
\(\left(19x+\frac{9}{4}\right)\div14=5^2-4\)
\(\left(19x+\frac{9}{4}\right)\div14=25-4\)
\(\left(19x+\frac{9}{4}\right)\div14=21\)
\(\left(19x+\frac{9}{4}\right)=21\times14\)
\(\left(19x+\frac{9}{4}\right)=294\)
\(19x=294-\frac{9}{4}\)
\(x=\frac{1167}{4}\div19\)
\(x=\frac{1167}{76}\)
\(1+2+3+4+...+x=378\)
\(\left(1+x\right)\cdot x\div2=378\)
\(\left(1+x\right)\cdot x=378\times2\)
\(\left(1+x\right)\cdot x=756\)
\(\left(1+x\right)\cdot x=28\cdot27\)
\(\Rightarrow x=27\)