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\(3x^2-15=93\)
\(\Leftrightarrow3x^2=93+15\)
\(\Leftrightarrow3x^2=108\)
\(\Leftrightarrow x^2=108:36\)
\(\Leftrightarrow x^2=36\)
\(\Leftrightarrow\orbr{\begin{cases}x=6\\x=-6\end{cases}}\)
~~~Học Tốt~~~
2(x + 15) + 3(x + 25) = 2050
=> 2x + 30 + 3x + 75 = 2050
=> 5x + 105 = 2050
=> 5x = 1945
=> x = 389
2 ( x + 15 ) + 3 ( x + 25 ) = 2050
2x + 30 + 3x + 75 = 2050
5x + 105 = 2050
5x = 1945
x = 389
\(a,\)\(-\frac{3}{5}\cdot x=\frac{1}{4}+0,75\)
\(-\frac{3}{5}\cdot x=\frac{1}{4}+\frac{3}{4}=\frac{4}{4}=1\)
\(x=1\div\left(-\frac{3}{5}\right)\)
\(x=-\frac{5}{3}\)
\(b,\)\(\left(\frac{1}{7}-\frac{1}{3}\right)\cdot x=\frac{28}{5}\times\left(\frac{1}{4}-\frac{1}{7}\right)\)
\(\left(\frac{3}{21}-\frac{7}{21}\right)\cdot x=\frac{28}{5}\cdot\left(\frac{7}{28}-\frac{4}{28}\right)\)
\(-\frac{4}{21}\cdot x=\frac{28}{5}\cdot\frac{3}{28}\)
\(-\frac{4}{21}\cdot x=\frac{3}{5}\)
\(x=\frac{3}{5}\div\left(-\frac{4}{21}\right)\)
\(x=-\frac{63}{20}\)
\(c,\)\(\frac{5}{7}\cdot x=\frac{9}{8}-0,125\)
\(\frac{5}{7}\cdot x=\frac{9}{8}-\frac{1}{8}\)
\(\frac{5}{7}\cdot x=1\)
\(x=1\div\frac{5}{7}\)
\(x=\frac{7}{5}\)
\(d,\)\(\left(\frac{2}{11}+\frac{1}{3}\right)\cdot x=\left(\frac{1}{7}-\frac{1}{8}\right)\cdot36\)
\(\left(\frac{6}{33}+\frac{11}{33}\right)\cdot x=\left(\frac{8}{56}-\frac{7}{56}\right)\cdot36\)
\(\frac{17}{33}\cdot x=\frac{1}{56}\cdot36\)
\(\frac{17}{33}\cdot x=\frac{9}{14}\)
\(x=\frac{9}{14}\div\frac{17}{33}\)
\(x=\frac{9}{14}\cdot\frac{33}{17}=\frac{297}{238}\)
\(3\times x^2-15=93\)
\(3\times x^2=93+15\)
\(3\times x^2=108\)
\(\Rightarrow\) \(x^2=108\div3\)
\(x^2=36\)
\(Mà\) \(36=6^2\)
\(\Rightarrow x^2=6^2\Rightarrow x=6\)
3.x2-15=93
3.x2=93+15
3.x2=108
x2=108:3
x2=36
x2=62
=>x=6
vậy x=6