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11 tháng 8 2022

36-x/35=9/21

= x/ 35 = 36 - 9/21

= x/35 = 249/7

=  x * 7 = 35 * 249

= x*7 = 8715 

= x = 8715 : 7

= x = 1245 

 

\(36-\dfrac{x}{35}=\dfrac{9}{21}\)

\(\dfrac{x}{35}=36-\dfrac{9}{21}\)

\(\dfrac{x}{35}=\dfrac{249}{7}\)

\(x=\dfrac{249}{7}:35\)

\(x=\dfrac{249}{245}\)

12 tháng 3 2020

=9( 1/4.5+1/5.6+...+1/36.37)

=9( 1/4-1/37)... tự yinhs nha

28 tháng 7 2015

\(\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+....+\frac{2}{x\left(x+1\right)}=\frac{2}{9}\)

\(\frac{2}{6.7}+\frac{2}{7.8}+\frac{2}{8.9}+.....+\frac{2}{x\left(x+1\right)}=\frac{2}{9}\)

\(2\left(\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+....+\frac{1}{x}-\frac{1}{x+1}\right)=\frac{2}{9}\)

\(\frac{1}{6}-\frac{1}{x+1}=\frac{2}{9}:2=\frac{1}{9}\)

\(\frac{1}{x+1}=\frac{1}{6}-\frac{1}{9}=\frac{1}{18}\)

=> x+1 = 18

=> x = 18 - 1

=> x = 17

21 tháng 5 2016

a, x : 35,2 = 35

x = 35 x 35,2 

x = 1232

b, X : 36 = 57 ( dư 35 )

x = 36 x 57 ( dư 35 )

x = 2052 + 35

x = 2087

21 tháng 5 2016

X thứ nhất = 1232

X thứ hai = 2087

10 tháng 6 2015

1> a) \(\frac{5}{7}x4:\frac{5}{9}=\frac{5}{7}:\frac{5}{9}x4=\frac{5}{7}x\frac{9}{5}x4=\frac{9}{7}x4=\frac{9x4}{7}=\frac{36}{7}\)

\(b,8x\frac{2}{3}:\frac{1}{2}=8x\frac{2}{3}x\frac{2}{1}=8x2x\frac{2}{3}=16x\frac{2}{3}=\frac{32}{3}\)

\(c,6:\frac{3}{5}-\frac{7}{6}x\frac{6}{7}=6x\frac{5}{3}-1=10-1=9\)

\(\frac{21}{5}x\frac{10}{11}+\frac{57}{11}=\frac{42}{11}+\frac{57}{11}=\frac{99}{11}=9\)

2) a) \(\frac{35}{9}:x=\frac{35}{6}\)

\(x=\frac{35}{9}:\frac{35}{6}\)

\(x=\frac{35}{9}x\frac{6}{35}\)

\(x=\frac{2}{3}\)

b) \(\left(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+\frac{1}{5x6}\right)x10-X=0\)

\(\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+.....+\frac{1}{5}-\frac{1}{6}\right)x10-X=0\)

\(\left(\frac{1}{1}-\frac{1}{6}\right)x10-X=10\)

\(\frac{5}{6}x10-X=0\)

\(X=\frac{5}{6}x10=\frac{25}{3}\)

Đúng nha !!!!

10 tháng 6 2015

1/a/\(\frac{5}{7}\cdot4:\frac{5}{9}=\frac{20}{7}:\frac{5}{9}=\frac{20}{7}\cdot\frac{9}{5}=\frac{36}{7}\)

b/\(8\cdot\frac{2}{3}:\frac{1}{2}=\frac{16}{3}:\frac{1}{2}=\frac{16}{3}\cdot\frac{2}{1}=\frac{32}{3}\)

c/\(6:\frac{3}{5}-\frac{7}{6}\cdot\frac{6}{7}=6\cdot\frac{5}{3}-1=10-1=9\)

2/a/\(\frac{35}{9}:x=\frac{35}{6}\)

\(x=\frac{35}{9}:\frac{35}{6}=\frac{35}{9}\cdot\frac{6}{35}\)

\(x=\frac{2}{3}\)

 

b/\(\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}\right)\cdot10-x=0\)

\(\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}\right)\cdot10-x=0\)

\(\left(\frac{30}{60}+\frac{10}{60}+\frac{5}{60}+\frac{2}{30}\right)\cdot10-x=0\)

\(\frac{47}{60}\cdot10-x=0\)

\(\frac{47}{6}-x=0\)

\(x=\frac{47}{6}-0\)

\(x=\frac{47}{6}\)

5 tháng 8 2020

chuyển đổi lại : (7x - 3) : 12 = 13

=> (7x - 3) = 13 * 12

=> 7x - 3 = 156

=> 7x = 159

=> x=  159/7

[(7x - 31) : 5] * 36 = 7236

=> [(7x - 31) : 5] = 7236 : 36 = 201

=> (7x - 31) : 5 = 201

=> 7x - 31 = 1005

=> 7x = 1036

=> x = 148

1 + 2 + 3 + 4 + 5 +... + 100 + x = 5350

SSH : \(\left(100-1\right):1+1=100\)

=> tổng : \(\frac{\left(1+100\right)\cdot100}{2}=5050\)

=> 5050 + x = 5350

=> x = 5350 - 5050 = 300

80 - 9(x - 4) = 35

=> 9(x - 4) = 80 - 35 = 45

=> x - 4 = 45 : 9

=> x - 4 = 5

=> x = 9

(3x - 21) : 4 + 108 = 114

=> (3x - 21) : 4 = 114 - 108 = 6

=> 3x - 21 = 24

=> 3x = 45

=> x = 15

[(6x - 72) : 2 - 84]*14 = 2814

=> [(6x - 72) : 2 - 84] = 201

=> (6x - 72) : 2 - 84 = 201

=> (6x - 72) : 2 = 285

=> 6x - 72 = 570

=> 6x = 642

=> x = 107

28x + 12x = 80

=> 40x = 80

=> x = 2

249 - 7(1 + x) = 200

=> 7(1 + x) = 49

=> 1 + x = 7

=> x = 6

20 - [(x - 5) * 7 + 4] = 2

=> [(x - 5) * 7 + 4] = 18

=> (x - 5)*7 + 4 = 18

=> (x - 5) * 7 = 14

=> x - 5 = 2

=> x = 7

\(\frac{7x-33}{12}=13\)

\(7x-33=13\cdot12\)

\(7x-33=156\)

\(7x=156+33\)

\(7x=189\)

\(x=\frac{189}{7}=27\)

\(\frac{7x-31}{5}\cdot36=7236\)

\(\frac{7x-31}{5}=\frac{7236}{36}\)

\(\frac{7x-31}{5}=201\)

\(7x-31=201\cdot5\)

\(7x-31=1005\)

\(7x=1005+31\)

\(7x=1036\)

\(x=\frac{1036}{7}=148\)

\(1+2+3+4+5+..+100+x=5350\)

\(\left(1+2+3+4+5+...+100\right)+x=5350\)

Phần 1 + 2 + 3 + 4 + 5 + ... + 100 có số số hạng là :

             \(\frac{100-1}{1}+1=100\) ( số hạng )

\(\Rightarrow\frac{\left(100+1\right)\cdot100}{2}+x=5350\)

\(5050+x=5350\)

\(x=5350-5050=300\)

\(80-9\left(x-4\right)=35\)

\(9\left(x-4\right)=80-35\)

\(9\left(x-4\right)=45\)

\(x-4=\frac{45}{9}\)

\(x-4=5\)

\(x=5+4=9\)

\(\frac{3x-21}{4}+108=114\)

\(\frac{3x-21}{4}=114-108\)

\(\frac{3x-21}{4}=6\)

\(3x-21=6\cdot4\)

\(3x-21=24\)

\(3x=24+21\)

\(3x=45\)

\(x=\frac{45}{3}=15\)

\(14\left(\frac{6x-72}{2}-84\right)=2814\)

\(3x-36-84=\frac{2814}{14}\)

\(3x-120=201\)

\(3x=201+120\)

\(3x=321\)

\(x=\frac{321}{3}=107\)

\(28x+12x=80\)

\(x\left(28+12\right)=80\)

\(x\cdot40=80\)

\(x=\frac{80}{40}=2\)

\(249-7\left(1+x\right)=200\)

\(-7\left(1+x\right)=200-249\)

\(-7\left(1+x\right)=-49\)

\(1+x=\frac{-49}{-7}\)

\(1+x=7\)

\(x=7-1=6\)

\(20-7\left(x-5\right)+4=2\)

\(20-7\left(x-5\right)=2-4\)

\(20-7\left(x-5\right)=-2\)

\(-7\left(x-5\right)=-2-20\)

\(-7\left(x-5\right)=-22\)

\(x-5=\frac{-22}{-7}\)

\(x=\frac{22}{7}+5=\frac{57}{7}\)

17 tháng 8 2015

Dấu chấm là dấu nhân

\(1+\frac{2}{3}+\frac{5}{6}+\frac{9}{10}+...+\frac{44}{45}\)

\(=1+1-\frac{1}{3}+1-\frac{1}{6}+1-\frac{1}{10}+...+1-\frac{1}{45}\)

\(=8-2\cdot\left(\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+...+\frac{1}{9\cdot10}\right)\)

\(=8-2\cdot\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\right)\)

\(=8-2\cdot\left(\frac{1}{2}-\frac{1}{10}\right)\)

\(=8-2\cdot\frac{2}{5}\)

\(=8-\frac{4}{5}\)

\(=\frac{36}{5}\)

18 tháng 8 2015

Đặt \(A=1+\frac{2}{3}+\frac{5}{6}+\frac{9}{10}+\frac{20}{21}+\frac{27}{28}+\frac{35}{36}+\frac{44}{45}\)

\(=1+1-\frac{1}{3}+1-\frac{1}{6}+1-\frac{1}{10}+1-\frac{1}{21}+1-\frac{1}{28}+1-\frac{1}{36}+1-\frac{1}{45}\)

\(=8-\left(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+\frac{1}{45}\right)\)

\(\Leftrightarrow\frac{1}{2}.A=4-\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}\right)\)

\(=4-\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\right)\)

\(=4-\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{6}-\frac{1}{10}\right)\)

\(=4-\frac{11}{30}=\frac{109}{30}\)

\(\Rightarrow A=\frac{109}{15}\)