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(7.x + 1) : 2 - 23 = 2
=> (7.x + 1) : 2 = 2 + 23
=> (7.x + 1) : 2 = 25
=> 7.x + 1 = 25 . 2
=> 7.x + 1 = 50
=> 7.x = 50 - 1
=> 7.x = 49
=> x = 49 : 7 = 7
(7.x + 1) : 2 - 23 = 2
=> (7.x + 1) : 2 = 2 + 23
=> 7.x + 1 = 25 . 2
=> 7.x = 50 - 1
=> 7.x = 49
x = 49 : 7 = 7
Vậy.............
hok tốt
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x^2 - 1 = 80
=> x^2 = 80 + 1
=> x^2 =81
=> x^2 =9^2
=> x = 9
Vậy x = 9
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a. (x + 3)2 = 16
(x + 3)2 = 42
x + 3 = 4
x = 4 - 3
x = 1
b. (3.2)x+1 = 96
2x+1 = 96 : 3
2x + 1 = 32
2x+1 = 25
x +1 = 5
x = 5 - 1
x = 4
c. 3(x - 5)2 = 27
(x - 5)2 = 27 : 3
(x - 5)2 = 9
(x - 5)2 = 32
x - 5 = 3
x = 3 + 5
x = 8
d. 2x. 5 = 80
2x = 80 : 5
2x = 16
2x = 24
x = 4
a) \(\left(x+3\right)^2=16\)
\(\left(x+3\right)^2=4^2\)
\(x+3=4\)
\(x=4-3=1\)
Vậy x = 1
b) \(\left(3.2\right)^{x+1}=96\)
\(\left(3.2\right)^{x+1}=2^5.3\)
\(2^{x+1}=2^5\)
\(x+1=5\)
\(x=5-1=4\)
Vậy x = 4
c) \(3\left(x-5\right)^2=27\)
\(\left(x-5\right)^2=9\)
\(\left(x-5\right)^2=3^2\)
\(x-5=3\)
\(x=5+3=8\)
Vậy x = 8
d) \(2^{\left(x.5\right)}=80\)
\(1^{\left(x.5\right)}=40\)
\(x.5=2^3.5\)
\(x=2^3=8\)
Vậy x = 8
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\(4.2^x+2^x=80\)
\(2^x.\left(4+1\right)=80\)
\(2^x.5=80\)
\(2^x=16\)
\(2^x=2^4\)
\(\Rightarrow x=4\)
2x+2x+1+2x+2+...+2x+2015=22019−82x+2x+1+2x+2+...+2x+2015=22019−8
⇒2x(1+2+22+...+22015)=22019−8⇒2x(1+2+22+...+22015)=22019−8
⇒2x(22016−1)=22019−8⇒2x(22016−1)=22019−8
⇒2x=22019−822016−1⇒2x=22019−822016−1
⇒2x=⇒2x=23.(22016−1)22016−123.(22016−1)22016−1
⇒2x=23⇒2x=23
⇒x=3⇒x=3
Vậy x=3