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\(\left(2x-2\right)\left(x-4\right)=0\)
\(=>2x-2=0;x-4=0\)
\(TH1:2x-2=0\)
\(2x=2\)
\(=>x=1\)
\(TH2:x-4=0\)
\(x=4\)
\(=>x\in\left\{1;4\right\}\)
\(\left(2x-1\right)\left(x-2\right)=0\)
\(=>2x-1=0;x-2=0\)
\(TH1:2x-1=0\)
\(2x=1\)
\(=>x=\frac{1}{2}\)
\(TH2;x-2=0\)
\(x=2\)
\(=>x\in\left\{\frac{1}{2};2\right\}\)
7.(x+2)-4.(x-1)=30
7x+14-4x+4=30
3x+18=30
3x=12
x=4
Vậy x=4
(2x -2).(x-4)=0
suy ra 2x-2=0 hoặc x-4=0
suy ra x=1 hoặc x=4
Vậy x=1 hoặc x=4
(2x -1).(x-2)=0
suy ra 2x-1=0 hoặc x-2=0
suy ra x=1/2 hoặc x=2
Vậy x=1/2 hoặc x=2
a)15.102 : (2x - 6) = 30
15 . 100 : (2x - 6) = 30
100 : (2x - 6) = 30 : 15
100 : (2x - 6) = 2
2x - 6 = 100 : 2
2x - 6 = 50
2x = 50 + 6
2x = 56
x = 56 : 2
x =28
b) (2x + 1 )3 =125
(2x + 1 )3 = 53
Suy ra 2x + 1 = 5
2x = 5 - 1
2x = 4
x = 4:2
x = 2
a )15.102:(2x-6)=30
15.100:(2x-6)=30
100:(2x-6)=30:15
100:(2x-6)=2
2x-6 = 100:2
2x-6 = 50
2x = 50+6
2x = 56
x = 56:2
x = 28
ý b) m chịu
1500: [(30x + 40) : x]=30
=>(30x + 40): x = 1500 : 30
=>30x : x+ 40:x=50
=> 30 + 40 :x=50
=> 40 :x=50-30
=> 40:x=20
=>x=40:20
=>x=2
: [(30x + 40) : x] = 30(2x - 15)5 = (2x - 15)3
=>(30x+40):x=1500 : 30=50
40:x = 50-30
40:x=20
x=2
1) \(4\left(2x-1\right)^2-10=54\)
\(\Leftrightarrow4\left(2x-1\right)^2=64\)
\(\Leftrightarrow\left(2x-1\right)^2=16\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}2x-1=4\\2x-1=-4\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=\frac{5}{2}\\x=-\frac{3}{2}\end{array}\right.\)
2)\(5\left(3^{2x-1}+30\right)=165\)
\(\Leftrightarrow3^{2x-1}+30=33\)
\(\Leftrightarrow3^{2x-1}=3\)
\(\Leftrightarrow2x-1=1\)
\(\Leftrightarrow x=1\)
\(a,x=3x^2\Rightarrow x-3x^2=0\Rightarrow x\left(1-3x\right)=0\Rightarrow\orbr{\begin{cases}x=0\\1-3x=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x=\frac{1}{3}\end{cases}}\)
\(b,\left(2x-6\right)\left(x+4\right)+2\left(2x-6\right)=0\)
\(\Rightarrow\left(2x-6\right)\left(x+4+2\right)=0\)
\(\Rightarrow\left(2x-6\right)\left(x+6\right)=0\)
\(\Rightarrow\orbr{\begin{cases}2x-6=0\\x+6=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=-6\end{cases}}\)
\(c,\left(2x-5\right)\left(x+9\right)+6x-15=0\)
\(\Rightarrow\left(2x-5\right)\left(x+9\right)+3\left(2x-5\right)=0\)
\(\Rightarrow\left(2x-5\right)\left(x+9+3\right)=0\)
\(\Rightarrow\left(2x-5\right)\left(x+12\right)=0\)
\(\Rightarrow\orbr{\begin{cases}2x-5=0\\x+12=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{5}{2}\\x=-12\end{cases}}\)
\(\Leftrightarrow2x+1+2x+2+2x+3+....+2x+101=5757\)
\(\Leftrightarrow2x.101+\left[1+2+3+....+101\right]=5757\)
\(\Leftrightarrow202x+\frac{\left[101+1\right]101}{2}=5757\)
\(\Leftrightarrow202x+5151=5757\)
\(\Leftrightarrow202x=606\)
\(\Leftrightarrow x=3\)
Vậy x=3
Có tất cả 2015 số hạng
Tổng bằng (2x+1+2x+2015).2015/2=0
4x+2016=0
4x=0-2016=-2016
x=(-2016):4=-504
100% đúng
5^x + 5^ ( x + 2 ) = 650
5x + 5x . 52 = 650
5x .( 1 + 25 ) = 650
5x . 26 = 650
5x = 650 : 26
5x = 25
5x = 52
=> x = 2
Vậy x = 2
Ta có : \(2x+\left(2x+1\right)+\left(2x+2\right)+...+\left(2x+30\right)=1271\)
=> \(2x.31+\left(2.1+\left(30-1\right).1\right).\frac{30}{2}=1271\)
=> \(62x+465=1271\)
=> \(62x=806\)
=> \(x=13\)
Vậy phương trình có nghiệm là \(S=\left\{13\right\}\)