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\(\left(\frac{1}{2}+x\right)+\left(\frac{1}{4}+x\right)+\left(\frac{1}{8}+x\right)+\left(\frac{1}{16}+x\right)=1\)
\(\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)+\left(x+x+x+x\right)=1\)
\(\frac{15}{16}+4x=1\)
\(4x=\frac{1}{16}\)
\(x=\frac{1}{64}\)
( x + x + x + x ) + ( \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\) ) = 1
x * 4 + \(\frac{15}{16}\) = 1
x * 4 = 1 - \(\frac{15}{16}\)
x * 4 = \(\frac{1}{16}\)
x = \(\frac{1}{16}\) : 4
x = \(\frac{1}{64}\)
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\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
\(\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
\(4x+\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
\(4x+\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}\right)=1\)
\(4x+\left(1-\frac{1}{16}\right)=1\)
\(4x+\frac{15}{16}=1\)
\(4x=\frac{1}{16}\)
\(\Rightarrow x=\frac{1}{64}\)
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
\(\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
\(4x+\frac{15}{16}=1\)
\(4x=\frac{1}{16}\)
\(x=\frac{1}{16}\div4\)
\(x=\frac{1}{64}\)
Vậy ...
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1+|-2|+3+|-4|+5=15=> x+15=16=> x=1 thay vào ta được:
|1+1|+|1-2|+|1+3|+|1-4|+|1+5|=16
16 = ( x - 1 )4
24 = ( x - 1 )4
24 = ( 3 - 1 )4
=> x = 3
k chắc ! Cũng ms hk
Sai bỏ qua . Thanks
16 = ( x - 1 )4
24 = ( x - 1 )4
( x - 1 )4 = 24
=> x - 1 = 2
x = 2 + 1
x = 3
Vậy x = 3