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\(0,5x-75\%x=\left(\frac{1}{3}-1\right)^2\)
\(\Leftrightarrow\frac{1}{2}x-\frac{3}{4}x=\left(-\frac{2}{3}\right)^2\)
\(\Leftrightarrow-\frac{1}{4}x=\frac{4}{9}\)
\(\Leftrightarrow x=-\frac{16}{9}\)
\(0,5x-75\%x=\left(\frac{1}{3}-1\right)^2\)
\(< =>\frac{1}{2}x-\frac{3}{4}x=\left(-\frac{2}{3}\right)^2\)
\(< =>-\frac{1}{4}x=\frac{4}{9}\)
\(=>x=\frac{-16}{9}\)
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Bài 1:
0,5\(x\) - \(\dfrac{2}{3}\)\(x\) = \(\dfrac{7}{12}\)
\(\dfrac{1}{2}\)\(x\) - \(\dfrac{2}{3}x\) = \(\dfrac{7}{12}\)
(\(\dfrac{1}{2}-\dfrac{2}{3}\))\(x\) = \(\dfrac{7}{12}\)
- \(\dfrac{1}{6}\)\(x\) = \(\dfrac{7}{12}\)
\(x\) = \(\dfrac{7}{12}\) : (- \(\dfrac{1}{6}\))
\(x\) = - \(\dfrac{7}{2}\)
Vậy \(x\) = - \(\dfrac{7}{2}\)
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a: =>3/2x=64/15
=>x=128/45
b: =>-1/6x=7/12
=>x=-7/2
c: =>11/2*x=1/2
=>x=1/2:11/2=1/11
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\(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)ĐKXĐ: \(x\ne-\frac{1}{2};x\ne-3\)
\(\Rightarrow\left(x+1\right)\left(x+3\right)=\left(2x+1\right)\left(0,5x+2\right)\)
\(\Leftrightarrow x^2+x+3x+3=x^2+0,5x+4x+2\)
\(\Leftrightarrow x^2+4x+3=x^2+4,5x+2\)
\(\Leftrightarrow x^2-x^2+4x-4,5x=2-3\)
\(\Leftrightarrow-0,5x=-1\)
\(\Leftrightarrow x=2\)
vậy x=2
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0,5x-2/3(x-1)=1/6
1/2x-(2/3x-2/3)=1/6
1/2x-2/3x+2/3=1/6
x.(1/2-2/3)=1/6-2/3
x.(-1/6)=-1/2
x.(-1/6)=-1/2
x=-1/2:(-1/6)
x=-1/2.(-6)
x=3
Vậy x=3
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