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\(320\div x-10=5\cdot48\div24\)
\(320\div x-10=240\div24\)
\(320\div x-10=10\)
\(320\div x=10+10\)
\(320\div x=20\)
\(x=320\div20\)
\(x=16\)

a) \(\frac{24}{x}\div\frac{8}{3}=\frac{3}{5}\)
\(\frac{24}{x}\cdot\frac{3}{8}=\frac{3}{5}\)
\(\frac{24}{x}=\frac{3}{5}\div\frac{3}{8}\)
\(\frac{24}{x}=\frac{24}{15}\)
Vậy x = 15
b) Tương tự

a) \(\frac{1}{3}-\frac{2}{x}=\frac{1}{6}\)
=> \(\frac{2}{x}=\frac{1}{3}-\frac{1}{6}\)
=> \(\frac{2}{x}=\frac{1}{6}\)
\(\Rightarrow x=12\)
Vậy x = 12
b) \(\frac{x-1}{2}=\frac{3}{4}\)
\(\Rightarrow\left(x-1\right).4=2.3\)
=> 4x - 4 = 6
=> 4.(x-1) = 6
=> x-1 = 6:4 = 1,5
=> x = 1,5 + 1
=> x = 2,5
Vậy x = 2,5

a, 6/9+5/7+1/3=2/3+5/7+1/3=5/7+1=12/7
b, 17/7+6/5-20/14=17/7+6/5-10/7=6/5+1=11/5
c,2/5x1/4+3/4x2/5=2/5x(1/4+3/4)=2/5x1=2/5
d, 6/11:4/6+5/11:2/3=6/11:2/3+5/11:2/3=(6/11+5/11):2/3=3/2
nha

X x\(\frac{1}{2}\)+ X x\(\frac{3}{4}\)=\(\frac{6}{7}\)
=>X x(\(\frac{1}{2}\)+ \(\frac{3}{4}\)) =\(\frac{6}{7}\)
=>X x \(\frac{5}{4}\)=\(\frac{6}{7}\)
=>X=\(\frac{6}{7}\): \(\frac{5}{4}\)
=>X=\(\frac{24}{35}\)