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\(\frac{x+2}{3}=\frac{2x-1}{5}\)
=> \(\left(x+2\right)\cdot5=3\left(2x-1\right)\)
=> \(5x+10=6x-3\)
=> \(6x-5x=10+3\)
=> \(x=13\)
\(\frac{-x}{4}=\frac{-9}{x}\)
=> \(-x^2=4\cdot\left(-9\right)\)
=> \(-x^2=-36\)
=> \(x^2=36\)
=> \(\orbr{\begin{cases}x^2=6^2\\x^2=\left(-6\right)^2\end{cases}}\Rightarrow\orbr{\begin{cases}x=6\\x=-6\end{cases}}\)
Quỳnh ơi, chuyển 6x sang sẽ là -6x mà viết như cậu phải là -6x+5x :)
a, \(\frac{x+2}{3}=\frac{2x-1}{5}\)
\(\Leftrightarrow\frac{5x+10}{15}=\frac{6x-3}{15}\Leftrightarrow5x+10=6x-3\Leftrightarrow-x+13=0\Leftrightarrow x=-13\)
b, \(\frac{-x}{4}=\frac{-9}{x}\)\(\Leftrightarrow x^2=36\Leftrightarrow x=\pm6\)
a, x/4 = y/7
=> (x-y)/(4-7) = x/4 = y/7 có x - y = 9
=> 9/-3 = x/4 = y/7
=> x = -3.4 = -12 và y = -3.7 = -21
b, x/2 = y/5
=> 3x/6 = y/5
=> (3x-y)(6 - 5) = x/6 = y/5 mà 3x - y = 5
=> 5 = x/6 = y/5
=> x = 5.6 = 30 và y = 5.5 = 25
a) \(\frac{x}{4}=\frac{y}{7}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\frac{x}{4}=\frac{y}{7}=\frac{x-y}{4-7}=\frac{9}{-3}=-3\)
\(\Rightarrow\hept{\begin{cases}x=-3\cdot2=-6\\y=-3\cdot7=-21\end{cases}}\)
a, \(\frac{x-1}{9}=\frac{8}{3}\Leftrightarrow\frac{x-1}{9}=\frac{24}{9}\Leftrightarrow x-1=24\Leftrightarrow x=25\)
b, \(\frac{x+2}{3}=\frac{2x-1}{5}\Leftrightarrow\frac{5x+10}{15}=\frac{6x-3}{15}\Leftrightarrow5x+10=6x-3\)
\(\Leftrightarrow5x+10-6x+3=0\Leftrightarrow-x+13=0\Leftrightarrow x=13\)
a) \(\frac{x-1}{9}=\frac{8}{3}\)
\(\Leftrightarrow3\left(x-1\right)=8.9\)
\(\Leftrightarrow3x-3=72\)
\(\Leftrightarrow3x=75\)
\(\Leftrightarrow x=25\)
b) \(\frac{x+2}{3}=\frac{2x-1}{5}\)
\(\Leftrightarrow5\left(x+2\right)=3\left(2x-1\right)\)
\(\Leftrightarrow5x+10=6x-3\)
\(\Leftrightarrow5x-6x=-3-10\)
\(\Leftrightarrow-x=-13\)
\(\Leftrightarrow x=13\)
a, \(\frac{-x}{4}=\frac{-9}{x}\Leftrightarrow2x=36\Leftrightarrow x=18\)
b, \(\frac{-x}{4}=\frac{-18}{x+1}\Leftrightarrow x^2+x=72\Leftrightarrow x\left(x+1\right)=72\)
\(\Leftrightarrow\orbr{\begin{cases}x=72\\x=71\end{cases}}\)
a, \(\frac{-x}{4}=\frac{-9}{x}\left(x\ne0\right)\Leftrightarrow-x^2=-36\)
\(\Leftrightarrow x^2=36\Rightarrow x=\pm6\)
b, \(\frac{-x}{4}=\frac{-18}{x+1}\left(x\ne-1\right)\Leftrightarrow-x.\left(x+1\right)=-72\)
\(\Leftrightarrow x.\left(x+1\right)=72\)
\(\Leftrightarrow x^2+x-72=0\)
\(\Leftrightarrow\left(x-8\right).\left(x+9\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-8=0\\x+9=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=8\\x=-9\end{cases}}}\)
\(a,\frac{x-3}{x+4}=\frac{x+4-7}{x+4}=1-\frac{7}{x+4}\\ \Rightarrow x+4\inƯ\left(7\right)=\left\{-1;-7;1;7\right\}\)
\(b,\frac{3x-15}{x-4}=\frac{3x-12-3}{x-4}=3-\frac{3}{x-4}\\ \Rightarrow x-4\inƯ\left(3\right)=\left\{-1;1;-3;3\right\}\)
\(c,\frac{2x+11}{x+3}=\frac{2x+6+5}{x+3}=2+\frac{5}{x+3}\\ \Rightarrow x+3\inƯ\left(5\right)=\left\{-1;5;-5;1\right\}\)
\(d,\frac{x+5}{x-2}=\frac{x-2+7}{x-2}=1+\frac{7}{x-2}\\ \Rightarrow x-2\inƯ\left(7\right)=\left\{-1;-7;1;7\right\}\)
a, \(\frac{3}{7}=-\frac{x}{21}\Leftrightarrow63=-7x\Leftrightarrow x=-9\)
b, \(\frac{x-1}{6}=\frac{2}{3}\Leftrightarrow\frac{x-1}{6}=\frac{4}{6}\Leftrightarrow x-1=4\Leftrightarrow x=5\)
c, \(\frac{-15}{2x+3}=\frac{-5}{8}\Leftrightarrow-120=-10x-15\Leftrightarrow-10x=-105\Leftrightarrow x=10,5\)( chưa xem lại ko chắc , thử lại giúp mk nha )
a) \(\frac{3}{7}=\frac{-x}{21}\)
\(\Rightarrow-7x=21.3\)
\(-7x=63\)
\(x=63:\left(-7\right)\)
\(x=-9\)
Vậy x=-9
b) \(\frac{x-1}{6}=\frac{2}{3}\)
\(\Rightarrow\left(x-1\right).3=6.2\)
\(3x-3=12\)
\(3x=12+3\)
\(3x=15\)
\(x=15:3\)
\(x=5\)
Vậy x=5
a. | x+3 | +|x+9 | + | x+5 | = 4x
- Nếu x<-9 PT trở thành
-x-9-x-5-x-3=4x<=>-3x-17=4x<=> 7x=-17<=> x=-177177 (loại)
- Nếu −9≤x≤−5−9≤x≤−5thì pt có dạng
x+9-x-5-x-3=4x
<=> -x+1=4x<=>x=1515(loại)
- Nếu : −5<x≤−3−5<x≤−3PT trở thành;
x+9+x+5-x-3=4x<=>x+11=4x<=>x=113113(loại)
- Nếu −3≤x−3≤x thì pt trở thành:
x+9+x+5+x+3=4x<=>x=17
vậy qua 4TH => nghiệm PT là x=17
a, 14-3x = -x + 4
-3x + x = 4-14
-2x = -12
2x =12
x= 6
b, x-12 = -9--15
x-12 = 6
x=18
c, 16- I 5 - 2xI = 9
I 5 -2x I = 16-9
I 5-2x I = 7
\(\hept{\begin{cases}5x-2x=7\\5x-2x=-7\end{cases}}\hept{\begin{cases}2x=-2\\2x=12\end{cases}}\)
\(\hept{\begin{cases}x=-1\\x=6\end{cases}}\)
hok tốt