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Ta có: A = 1 + 2 + 22 + 23 + ..... + 229 + 230
=> 2A = 2.(1 + 2 + 22 + 23 + ..... + 229 + 230)
=> 2A = 2 + 22 + 23 + ..... + 229 + 231
=> 2A - A = 231 - 1
=> A = 231 - 1
=> A + 1 = 231
=> 2n + 4 = 231
=> n + 4 = 31
=> n = 31 - 4
=> n = 27
A = 1 + 3 + 32 + 33+..........+349+350
3A = 3 + 32 + 33 + 34 + ... + 350 + 351
3A - A = ( 3 + 32 + 33 + 34 + ... + 350 + 351 ) - ( 1 + 3 + 32 + 33+..........+349+350 )
2A = 351 - 1
A = ( 351 - 1 ) : 2
\(a,3^2\cdot3^4\cdot3^n=3^{12}\)
\(\Rightarrow3^{6+n}=3^{12}\)
\(\Rightarrow6+n=12\)
\(\Rightarrow n=6\)
\(b,2^n:4=16\)
\(\Rightarrow2^n:2^2=2^4\)
\(\Rightarrow2^{n-2}=2^4\)
\(\Rightarrow n-2=4\)
\(\Rightarrow n=6\)
\(c,6\cdot2^n+3\cdot2^n=9\cdot2^9\)
\(\Rightarrow2^n\left(6+3\right)=9\cdot2^9\)
\(\Rightarrow2^n\cdot9=9\cdot2^9\)
\(\Rightarrow2^n=2^9\)
\(\Rightarrow n=9\)
2^n.4=128
2^n=128:4
2^n=32
2^n=2^5
Suy ra n=5
3^n+1.9=81
3^n+1=81:9
3^n+1=9
3^n+1=3^2
Suy ra n=1
15^n-2=9^2:3^4
15^n-2=3^4:3^4
15^n-2=3^0
15^n-2=1
15^n-2=15^0
Suy ra n=2
co gi ko hieu thi hoi nha
\(3^{n+1}+3^n=324\)
\(\Leftrightarrow3^n.\left(1+3\right)=324\Leftrightarrow3^n.4=324\Leftrightarrow3^n=81\Leftrightarrow3^n=3^4\Leftrightarrow n=4\)
Vậy số tự nhiên n = 4
A)\(M=1+3+3^2+...+3^9\)\(\Rightarrow3M=3+3^2+3^3+...+3^{10}\)\(\Rightarrow3M-M=\left(3+3^2+3^3+...+3^{10}\right)-\left(1+3+3^2+...+3^9\right)\)
\(\Rightarrow2M=3^{10}-1\)\(\Rightarrow2M+1=3^{10}\)\(\Rightarrow n=10\)
B) \(A=1+4^2+...+4^{99}\)\(\Rightarrow4A=4+4^3+4^4+...+4^{100}\)\(\Rightarrow4A-A=\left(4+4^3+4^4+...+4^{100}\right)-\left(1+4^2+...+4^{99}\right)\)
\(\Rightarrow3A=4^{100}+4-4^2-1\Rightarrow3A=4^{100}-13\Rightarrow3A+13=4^{100}\Rightarrow n=100\)
Ta có : 9n = 32n
mà 9n=3n+1
=> 2n = n + 1
=> 2n - n =1
n = 1