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a, \(n+8\)chia hết cho \(n-9\)
\(\Rightarrow n+8-n+9\) chia hết cho \(n-9\)
\(\Rightarrow17\)chia hết cho \(n-9\)
\(\Rightarrow n-9\inƯ\left(17\right)=1;-1;17;-17\)
TH1 : \(n-9=1\Rightarrow n=10\)
TH2 :\(n-9=-1\Rightarrow n=8\)
TH3: \(n-9=17\Rightarrow n=26\)
TH4: \(n-9=-17\Rightarrow n=-8\)
Vậy \(n\in10;8;26;-8\)
b, \(2^n.4^{12}=8^{30}:16^{10}\)
\(\Rightarrow2^n.2^{24}=2^{90}:2^{40}\)
\(\Rightarrow2^n.2^{24}=2^{50}\)
\(\Rightarrow2^n=2^{26}\)
\(\Rightarrow n=26\)
Vậy \(n=26\)
c, \(2^n+2+2^n+1+2^n=112\)
\(\Rightarrow3.2^n+3=112\)
\(\Rightarrow3.2^n=109\)
\(\Rightarrow2^n=\frac{109}{3}\)
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a, 3n+2 chia hết n-1
=> 3(n-1)+5 chia hết cho n-1
Mà 3(n-1) chia hết cho n-1
=> 5 chia hết cho n-1
Lại có n thuộc N
=> n-1 thuộc Ư(5)=1,-1,5,-5
=> n=2,0,6,-4
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a) 3n+2 chia hết cho n-1
=>3(n-1)+5 chia hết cho n-1 = 5 chia hết cho n-1
=>n-1 thuộc Ư(5)={-1;1;-5;5}
n-1=-1=>n=0 = n-1=1=>n=2
n-1=-5=>n=-4 = n-1=5=>n=6
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2x.162 = 1024
=> 2x.(24)2 = 210
=> 2x + 4.2 = 10
=> x + 8 = 10
=> x = 2
vậy_
64.4x = 168
=> 43.4x = (42)8
=> 43 + x = 416
=> 3 + x = 16
=> x = 13
vậy_
2x = 16
=> 2x = 24
=> x = 4
vậy_
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