![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(3.3^{x-2}+5.3^{x-1}=162\)
\(\Rightarrow3^{x-1}+5.3^{x-1}=162\)
\(\Rightarrow3^{x-1}.6=162\)
\(\Rightarrow3^{x-1}=27=3^3\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=4\)
\(3\cdot3^{x-2}+5\cdot3^{x-1}=162\)
\(3^{x-1}+5\cdot3^{x-1}=162\)
\(3^{x-1}\left(5+1\right)=162\)
\(3^{x-1}\cdot6=162\)
\(3^{x-1}=27\)
\(3^{x-1}=3^3\)
\(x-1=3\)
\(x=4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
3x-1+5.3x-1=162
=>3x-1.6=162
=>3x-1=162:6
=>3x-1=27=33
=>x-1=3
=>x=4
![](https://rs.olm.vn/images/avt/0.png?1311)
Có 3^n+1-3^n=3^n.3-3^n=3^n(3-1)=3^n.2
Suy ra 3^n.2=162
3^n=162:2=81
3^n=3^4.Suy ra n = 4
![](https://rs.olm.vn/images/avt/0.png?1311)
a ) \(5^x+5^{x+2}=650\)
\(\Leftrightarrow5^x+5^x5^2=650\)
\(\Leftrightarrow5^x\left(1+25\right)=650\)
\(\Leftrightarrow5^x=25\)
\(\Leftrightarrow5^x=5^2\)
\(\Leftrightarrow x=2\)
b ) \(3^{x-1}+5.3^{x-1}=162\)
\(\Leftrightarrow3^{x-1}\left(1+5\right)=162\)
\(\Leftrightarrow3^{x-1}=27\)
\(\Leftrightarrow3^{x-1}=3^3\)
\(\Leftrightarrow x-1=3\Leftrightarrow x=4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
c. \(3^{-1}\cdot3^x+5\cdot3^{x-1}=162\)
\(\Leftrightarrow3^{x-1}\left(1+5\right)=162\)
\(\Leftrightarrow3^{x-1}=27\)
\(\Leftrightarrow3^{x-1}=3^3\)
\(\Leftrightarrow x-1=3\)
\(\Leftrightarrow x=4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)\(\Rightarrow\orbr{\begin{cases}x=0\\x+2=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=-2\end{cases}}}\)
b)\(\Rightarrow\orbr{\begin{cases}x^2+1=0\\x^2-4=0\end{cases}\Rightarrow\orbr{\begin{cases}x^2=-1\left(VL\right)\\x^2=4\Rightarrow x=2,-2\end{cases}}}\)VL là vô lý do bình phương luôn là số dương
Ủng hộ minhf bằng cachs k đúng nha
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 5X+5X+2=650
=>5X.1+5X.52=650
=>5X.(1+52)=650
=>5X.26=650
=>5x=650:26
=>5X=25
=>5X=52
=>X=2
b) 3X-1+5.3X-1=162
=>3X-1.1+5.3X-1=162
=>3X-1.(1+5)=162
=>3X-1.6=162
=>3X-1=162:6
=>3X-1=27
=>3X-1=33
=>3X=33+1
=>3X=34
=>X=4
=> \(5^x+5^x.5^2=650\)
\(5^x\left(1+5^2\right)=650\Leftrightarrow5^x.26=650\)
\(\Leftrightarrow5^x=25;x=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{1}{9}.27^n=3^n\)
\(\Rightarrow\frac{3^n}{27^n}=\frac{1}{9}\)
\(\Rightarrow\left(\frac{3}{27}\right)^n=\frac{1}{9}\)
\(\Rightarrow\left(\frac{1}{9}\right)^n=\frac{1}{9}\)
\(\Rightarrow n=1\)
3-1 x 3n + 5 x 3n-1 = 162
=> 3n-1 + 5 x 3n-1 = 162
=> ( 5 + 1 ) x 3n-1 = 162
=> 6 x 3n-1 = 162
=> 3n-1 = 162 : 6 = 27
=> 3n-1 = 33
=> n - 1 = 3
=> n = 4
Vậy ...................
3−1.3n+5.3n−1=1623−1.3n+5.3n−1=162
⇒3n−1+5.3n−1=162⇒3n−1+5.3n−1=162
⇒3n−1(1+5)=162⇒3n−1(1+5)=162
⇒3n−1.6=162⇒3n−1.6=162
⇒3n−1=162:6=27⇒3n−1=162:6=27
⇒3n−1=33⇒3n−1=33
⇒n−1=3⇒n−1=3
⇒n=4
k nha
Gạch :D