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7 tháng 11 2017

1)

a) \(\dfrac{5x}{10}=\dfrac{x}{2}\)

b) \(\dfrac{4xy}{2y}=2x\left(y\ne0\right)\)

c) \(\dfrac{21x^2y^3}{6xy}=\dfrac{7xy^2}{2}\left(xy\ne0\right)\)

d) \(\dfrac{2x+2y}{4}=\dfrac{2\left(x+y\right)}{4}=\dfrac{x+y}{2}\)

e) \(\dfrac{5x-5y}{3x-3y}=\dfrac{5\left(x-y\right)}{3\left(x-y\right)}=\dfrac{5}{3}\left(x\ne y\right)\)

f) \(\dfrac{-15x\left(x-y\right)}{3\left(y-x\right)}=-5x\dfrac{x-y}{y-x}=-5x\dfrac{x-y}{-\left(x-y\right)}\)

\(=-5x.\left(-1\right)=5x\left(x\ne y\right)\)

2)

a) Nhớ ghi ĐK vào nhá, lười quá :V\(\dfrac{x^2-16}{4x-x^2}=-\dfrac{\left(x-4\right)\left(x+4\right)}{x^2-4x}=\dfrac{\left(x-4\right)\left(x+4\right)}{x\left(x-4\right)}=\dfrac{x+4}{x}\)

b) \(\dfrac{x^2+4x+3}{2x+6}=\dfrac{x^2+3x+x+3}{2\left(x+3\right)}=\dfrac{x\left(x+3\right)+\left(x+3\right)}{2\left(x+3\right)}\)

\(=\dfrac{\left(x+3\right)\left(x+1\right)}{2\left(x+3\right)}=\dfrac{x+1}{2}\)

c) \(\dfrac{15x\left(x+3\right)^3}{5y\left(x+y\right)^2}=\dfrac{3x\left(x+3\right)^3}{y\left(x+y\right)^2}\) ( câu này có gì đó sai sai )

d) \(\dfrac{5\left(x-y\right)-3\left(y-x\right)}{10\left(x-y\right)}=\dfrac{5\left(x-y\right)+3\left(x-y\right)}{10\left(x-y\right)}\)

\(=\dfrac{8\left(x-y\right)}{10\left(x-y\right)}=\dfrac{8}{10}=\dfrac{4}{5}\)

e) \(\dfrac{2x+2y+5x+5y}{2x+2y-5x-5y}=\dfrac{2\left(x+y\right)+5\left(x+y\right)}{2\left(x+y\right)-5\left(x+y\right)}\)

\(=\dfrac{7\left(x+y\right)}{-3\left(x+y\right)}=-\dfrac{7}{3}\)

a. \(\left(20x^4y-25x^2y^2-3x^2y\right):5x^2y\)

\(=4x^2-5y-\frac{3}{5}\)

b. \(\left(15xy^2+17xy^3+18y^2\right):6y^2\)

\(=\frac{5}{2}x+\frac{17}{6}xy+3\)

c. \(\left[3\left(x-y\right)^4+2\left(x-y\right)^3-5\left(x-y\right)^2\right]:\left(y-x\right)^2\)

\(=\left[3\left(x-y\right)^4+2\left(x-y\right)^3-5\left(x-y\right)^2\right]:\left(x-y\right)^2\)

\(=3\left(x-y\right)^2+2\left(x-y\right)-5\)

d. \(\left(x^2-2xy+y^2\right):\left(y-x\right)\)

\(=\left(x-y\right)^2:\left(y-x\right)\)

\(=\left(y-x\right)^2:\left(y-x\right)\)

\(=y-x\)

15 tháng 11 2017

2)

a) \(\dfrac{1}{x}.\dfrac{6x}{y}\)

\(=\dfrac{6x}{xy}\)

\(=\dfrac{6}{y}\)

b) \(\dfrac{2x^2}{y}.3xy^2\)

\(=\dfrac{2x^2.3xy^2}{y}\)

\(=\dfrac{6x^3y^2}{y}\)

\(=6x^3y\)

c) \(\dfrac{15x}{7y^3}.\dfrac{2y^2}{x^2}\)

\(=\dfrac{15x.2y^2}{7y^3.x^2}\)

\(=\dfrac{30xy^2}{7x^2y^3}\)

\(=\dfrac{30}{7xy}\)

d) \(\dfrac{2x^2}{x-y}.\dfrac{y}{5x^3}\)

\(=\dfrac{2x^2.y}{\left(x-y\right).5x^3}\)

\(=\dfrac{2y}{5x\left(x-y\right)}\)

8 tháng 8 2018

a) \(2x+2y\)

\(=2\left(x+y\right)\)

b) \(5x+20y\)

\(=5\left(x+4y\right)\)

c) \(6xy-30y\)

\(=6y\left(x-5\right)\)

d) \(5x\left[x-110-10y\left(x-11\right)\right]\)

\(=5x\left(x-110-10xy+110\right)\)

\(=5x\left(x-10xy\right)\)

\(=5x^2\left(1-10y\right)\)

e) \(x^3-4x^2+x\)

\(=x\left(x^2-4x+1\right)\)

f) \(x\left(x+y\right)-\left(2x+2y\right)\)

\(=x\left(x+y\right)-2\left(x+y\right)\)

\(=\left(x+y\right)\left(x-2\right)\)

h) \(5x\left(x-2y\right)+2\left(2y-x\right)\)

\(=5x\left(x-2y\right)-2\left(x-2y\right)\)

\(=\left(x-2y\right)\left(5x-2\right)\)

i) \(x^2y^3-\dfrac{1}{2}x^4y^8\)

\(=x^2y^3\left(1-\dfrac{1}{2}xy^5\right)\)

j) \(a^2b^4+a^3b-abc\)

\(=ab\left(ab^3+a^2-c\right)\)

8 tháng 8 2018

a, 2x + 2y = 2(x + y)

b, 5x + 20y = 5x + 4.5y = 5(x + 4y)

c, 6xy - 30y = 6xy - 5.6y = 6y(x - 5)

24 tháng 2 2020

a)\(\left(4x^3-xy^2+y^3\right)\left(x^2y+2xy^2-2y^3\right)\)

\(=x^2y\left(4x^3-xy^2+y^3\right)+2xy^2\left(4x^3-xy^2+y^3\right)\)

\(-2y^3\left(4x^3-xy^2+y^3\right)\)

\(=4x^5y-x^3y^3+x^2y^4+8x^4y^2-2x^2y^4+2xy^5\)

\(-8x^3y^3+2xy^5-2y^6\)

\(=-2y^6+4x^5y+\left(2xy^5+2xy^5\right)+8x^4y^2+\left(x^2y^4-2x^2y^4\right)\)

\(-\left(x^3y^3+8x^3y^3\right)\)

\(=-2y^6+4x^5y+4xy^5+8x^4y^2-x^2y^4-9x^3y^3\)

24 tháng 2 2020

b) 

(!)  \(2\left(x+y\right)^2-7\left(x+y\right)+5\)

\(=2\left(x+y\right)^2-2\left(x+y\right)-5\left(x+y\right)+5\)

\(=2\left(x+y\right)\left(x+y-1\right)-5\left(x+y-1\right)\)

\(=\left(2x+2y-5\right)\left(x+y-1\right)\)

(!!) \(\left(x+y+z\right)^2-x^2-y^2-z^2\)

\(=\left(x^2+y^2+z^2+2xy+2yz+2zx\right)-x^2-y^2-z^2\)

\(=2\left(xy+yz+zx\right)\)

25 tháng 7 2017

\(A.2\left(2x+x^2\right)-x^2\left(x+2\right)+\left(x^3-4x+3\right)\)

\(=4x+2x^2-x^3-2x^2+x^3-4x+3\)

\(=3\)

\(\Rightarrow A:\) đúng.

\(B.x\left(x^2+x+1\right)-x^2\left(x+1\right)-x+5\)

\(=x^3+x^2+x-x^2\left(x+1\right)-x-1+6\)

\(=x^3+x\left(x+1\right)-x^2\left(x+1\right)-\left(x+1\right)+6\)

\(=x^3+\left(x+1\right)\left(x-x^2-1\right)+6\)

\(=x^3+x^2+x-x^3-x^2-x-1+6\)

\(=5\)

\(\Rightarrow B:\) đúng.

25 tháng 7 2017

\(C.3x\left(x-2\right)-5x\left(x-1\right)-8\left(x^2-3\right)\)

\(=3x^2-6x-5x^2+5x-8x^2+24\)

\(=-10x^2-x+24\)

\(\Rightarrow C:sai.\)

\(D.2y\left(y^2+y+1\right)-2y^2\left(y+1\right)-2\left(y+10\right)\)

\(=2y^3+2y+2y-2y^3-2y^2-2y-20\)

\(=-2y^2+2y-20\)

\(\Rightarrow D:sai.\)

11 tháng 7 2019

Mạn phép bỏ câu a :))

b) a2(b2 - a2) + b2(b2 + a2)

= a2.b2 + a2.(-a2) + b2.b2 + b2.a2

= a2.b2 - a4 + b4 + a2.b2 

= a4 + 2a2b2 + b2 (hđt)

c) x2(x3 + 2y - x2y) - y(x2 - x4 + y)

= x2.x3 + x2.2y + x2.(-x2y) + (-y).x2 + (-y).(-x)4 + (-y).y

= x5 + 2x2y - x4y - x2y + x4y - y2 

= x5 + (2xy2 - xy2) + (-x4y + x4y) - y2

= x5 + xy2 - y2