\(\frac{a}{4}-\frac{1}{2}=\frac{b}{3}\)

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26 tháng 8 2015

Ta có:

1/2=2/4

Suy ra a/4-2/4=b/3

Suy ra a-2/4=b/3

Suy ra (a-2).3=4.b

Suy ra a-2=4

Suy ra a=6

3=b

Suy ra b=3

vậy a=6

b=3

Nhớ l.i.k.e cho mình nha

 

24 tháng 6 2018

\(\frac{A}{B}=\frac{\frac{9}{1}+\frac{8}{2}+\frac{7}{3}+\frac{6}{4}+\frac{5}{5}+\frac{4}{6}+\frac{3}{7}+\frac{2}{8}+\frac{2}{9}}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}}\)

\(\frac{A}{B}=\frac{\left(\frac{8}{2}+1\right)+\left(\frac{7}{3}+1\right)+...+\left(\frac{1}{9}+1\right)+1}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{10}}\)

\(\frac{A}{B}=\frac{\frac{10}{2}+\frac{10}{3}+\frac{10}{4}+...+\frac{10}{9}+\frac{10}{10}}{\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}}\)

\(\frac{A}{B}=\frac{10\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{10}\right)}{\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}}\)

\(\frac{A}{B}=10\)

24 tháng 6 2018

\(A=\frac{9}{1}+\frac{8}{2}+\frac{7}{3}+...+\frac{2}{8}+\frac{1}{9}\)

Tách 9=1+1+...+1 ( có 9 số 1)

\(\Rightarrow A=1+\left(\frac{8}{2}+1\right)+\left(\frac{7}{3}+1\right)+...+\left(\frac{2}{8}+1\right)+\left(\frac{1}{9}+1\right)\)

\(A=\frac{10}{10}+\frac{10}{2}+\frac{10}{3}+...+\frac{10}{8}+\frac{10}{9}\)

\(A=10.\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}\right)\)

\(\Rightarrow A:B=\frac{10.\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}\right)}{\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}}=10\) ( vì \(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}\ne0\) )

Vậy \(A:B=10\)

10 tháng 10 2015

A = \(10\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}\right)\)

A : B = 10 

10 tháng 7 2019

B1:

Ta có: a - b = ab => a = ab + b = b(a + 1)

Thay a = b(a + 1) vào a  - b  = a : b ta có: \(a-b=\frac{b\left(a+1\right)}{b}=a+1\)

=> a - b = a + 1 => a - a - b = 1 => -b = 1 => b = -1 

Lại có: ab = a - b

<=> a x (-1) = a - (-1) <=> -a = a + 1 <=> -a - a = 1 <=> -2a = 1 <=> a = -1/2

Vậy...

B2:

a, \(3y\left(y-\frac{2}{5}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}3y=0\\y-\frac{2}{5}=0\end{cases}\Rightarrow\orbr{\begin{cases}y=0\\y=\frac{2}{5}\end{cases}}}\)

b, \(7\left(y-1\right)+2y\left(y-1\right)=0\)

\(\Rightarrow\left(y-1\right)\left(7+2y\right)=0\)

\(\Rightarrow\orbr{\begin{cases}y-1=0\\7+2y=0\end{cases}\Rightarrow}\orbr{\begin{cases}y=1\\2y=7\end{cases}\Rightarrow}\orbr{\begin{cases}y=1\\y=\frac{7}{2}\end{cases}}\)

B3: \(K=\frac{-2}{3}+\frac{3}{4}-\frac{-1}{6}+\frac{-2}{5}\)

\(K=\left(-\frac{2}{3}+\frac{1}{6}\right)+\left(\frac{3}{4}-\frac{2}{5}\right)\)

\(K=\left(\frac{-4}{6}+\frac{1}{6}\right)+\left(\frac{15}{20}-\frac{8}{20}\right)\)

\(K=\frac{-1}{2}+\frac{7}{20}=\frac{-10}{20}+\frac{7}{20}=\frac{-3}{20}\)

15 tháng 7 2016

A = 1/2 + 1/12 + 1/30 + ... + 1/2450

A = 1/1.2 + 1/3.4 + 1/5.6 + ... + 1/49.50

A = 1 - 1/2 + 1/3 - 1/4 + 1/5 - 1/6 + ... + 1/49 - 1/50

A = (1 + 1/3 + 1/5 + ... + 1/49) - (1/2 + 1/4 + 1/6 + ... + 1/50)

A = (1 + 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + ... + 1/49 + 1/50) - 2.(1/2 + 1/4 + 1/6 + ... + 1/50)

A = (1 + 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + ... + 1/49 + 1/50) - (1 + 1/2 + 1/3 + ... + 1/25)

A = 1/26 + 1/27 + 1/28 + ... + 1/50 = B

=> A:B = 1

15 tháng 7 2016

\(A=\frac{1}{2}+\frac{1}{12}+\frac{1}{30}+....+\frac{1}{2450}\)

\(A=\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{49.50}\)

\(A=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{49}-\frac{1}{50}\)

\(A=\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{49}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{50}\right)\)

\(A=\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{49}+\frac{1}{50}\right)-2\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{50}\right)\)

\(A=\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{49}+\frac{1}{50}\right)-\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{25}\right)\)

\(A=\frac{1}{26}+\frac{1}{27}+\frac{1}{28}+...+\frac{1}{49}+\frac{1}{50}=B\)

Vậy A = B

5 tháng 7 2017

3. S= -1/6 + -1/20 + 1/10 + 1/6

=0

4. A= -1 -1 -1 -1 -.... -1 [ có (50-2): 2 +1 = 25 số -1)

=-25

2 tháng 1 2017

\(\frac{a}{2}\)=\(\frac{b}{3}\)\(\frac{c}{4}\)=\(\frac{a+2b-c}{2+6-4}\)=\(\frac{20}{4}\)=5

\(\frac{a}{2}\)= 5 suy ra a=2.5=10

\(\frac{b}{3}\)=5 suy ra b=3.5=15

\(\frac{c}{4}\)=5 suy ra c=4.5=20

vậy a=10,b=15,c=20

2

2x-\(\frac{2}{3}\)=\(\frac{1}{3}\)

2x=\(\frac{1}{3}\)\(\frac{2}{3}\)

2x=1

x=1:2

x=\(\frac{1}{2}\)

k cho mình nhé có cơ hội thì kết bạn luôn