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a) 175 - (4 - x) : 3 = 95
=> (4 - x) : 3 = 175 - 95
=> (4 - x) : 3 = 80
=> 4 - x = 80 . 3
=> 4 - x = 240
=> x = 4 - 240
=> x = -236
Vậy x = -236
b) (3x - 5) - 14 = 71
=> 3x - 5 = 71 + 14
=> 3x - 5 = 85
=> 3x = 85 + 5
=> 3x = 90
=> x = 90 : 3
=> x = 30
Vậy x = 30
a) 420 + 65.4 = (x+175):5+30 b) x - 4867 = (175.2050.70):25+23
(x+175):5+30 = 420 + 65.4 x - 4867 = 1004523
(x+175):5+30 = 680 x = 999656
(x+175):5 = 650
x+175 = 3250
x = 3075
a) \(\left[\left(x+32\right)-17\right].2=42\)
\(\left[\left(x+32\right)-17\right]=42:2\)
\(\left[\left(x+32\right)-17\right]=21\)
\(\left(x+32\right)=21+17\)
\(\left(x+32\right)=38\)
\(x=38-32\)
\(x=6\)
b) \(125+\left(145-x\right)=175\)
\(\left(145-x\right)=175-125\)
\(\left(145-x\right)=50\)
\(x=145-50\)
\(x=95\)
a)\(2.x-138=8.9\)
\(2.x-138=72\)
\(2.x=72+138\)
\(2.x=210\)
\(x=210\div2\)
\(x=105\)
b)\(\left\{\left(6x-72\right)\div2-84\right\}.28=5628\)
\(\left(6x-72\right)\div2-84=201\)
\(\left(6x-72\right)\div2=285\)
\(6x-72=570\)
\(6x=642\)
\(x=107\)
c)\(420+65.4=\left(x+175\right)\div5+30\)
\(420+260=\left(x+175\right)\div5+30\)
\(680=\left(x+175\right)\div5+30\)
\(650=\left(x+175\right)\div5\)
\(3250=x+175\)
\(3075=x\)
a: =>3[(2x-1)^2-4]=49*125:175+196=231
=>(2x-1)^2-4=77
=>(2x-1)^2=81
=>2x-1=9 hoặc 2x-1=-9
=>x=5 hoặc x=-4
b: \(\Leftrightarrow2\cdot3^x\cdot3-4^3=7^2\cdot\left(27-25\right)\)
=>\(6\cdot3^x=49\cdot2+64=162\)
=>3^x=27
=>x=3
Lời giải:
a.
$3[(2x-1)^2-4]-14^2=7^2.5^3:175=35$
$3[(2x-1)^2-4]=35+14^2=231$
$(2x-1)^2-4=231:3=77$
$(2x-1)^2=77+4=81=9^2=(-9)^2$
$\Rightarrow 2x-1=9$ hoặc $2x-1=-9$
$\Rightarrow x=5$ hoặc $x=-4$
b.
$2.3^{x+1}-4^{10}:4^7=(7^5:7^3).(3^3-5^2)=7^2.2=98$
$2.3^{x+1}-4^3=98$
$2.3^{x+1}=98+4^3=162$
$3^{x+1}=162:2=81=3^4$
$\Rightarrow x+1=4$
$\Rightarrow x=3$
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=>a,blà các nghiệm của phương trình:
\(x^2-175x+4687=0\)
=>x=33,009 hoặc x=141,99
=>(a,b)=(33,009;141,99) hoặc (a,b)=(141,99;33,009)