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a) \(=-\frac{91}{50}:4\)
\(=-\frac{91}{200}\)
b) \(=\frac{5}{18}-\frac{26}{5}+\frac{18}{5}\)
\(=-\frac{119}{90}\)
\(\left(\frac{9}{25}-2,18\right):\left(3\frac{4}{5}+0,2\right)\)
\(=\left(-1,82\right):4\)
\(=-0,455\)
Câu 1 :
\(\frac{\left(-5\right)^{32}.20^{43}}{\left(-8\right)^{29}.125^5}\)
= \(\frac{5^{32}.2^{86}.5^{43}}{\left(-2\right)^{87}.5^{15}}\)
= \(\frac{5^{72}.\left(-2\right)^{86}}{\left(-2\right)^{87}.5^{75}}\)
= \(\frac{1}{-2}\)
Câu 2 :
\(\frac{5^4.18^4}{125.9^5.16}\)
= \(\frac{5^4.2^4.3^8}{5^3.3^{10}.2^4}\)
= \(\frac{5}{3^2}\)
= \(\frac{5}{9}\)
Câu 3 :
\(\frac{9^{18}.2^{29}}{8^9.27^{12}}\)
= \(\frac{3^{36}.2^{29}}{2^{27}.3^{36}}\)
= \(2^2\)
= 4
a) \(9,2\cdot2\frac{1}{2}-\left(2\cdot0,125-1\frac{5}{12}\right):\frac{1}{4}\)
\(=23-\left(0,25-\frac{17}{12}\right):\frac{1}{4}\)
\(=23-\left(-\frac{7}{6}\right):\frac{1}{4}\)
\(=23-\left(-\frac{14}{3}\right)\)
\(=\frac{83}{3}\)
b) \(\frac{\sqrt{3^2}-\sqrt{39^2}}{\sqrt{59-10-\sqrt{91^2}}}\)
\(=\frac{3-39}{\sqrt{59-10-91}}\)
\(=\frac{-36}{\sqrt{-42}}\)
Vì -42 < 0 \(\Leftrightarrow\)Biểu thức không tồn tại
c) \(\frac{5}{18}-1,456:\frac{7}{25}+4,5\cdot\frac{4}{5}\)
\(=\frac{5}{18}-\frac{26}{5}+\frac{18}{5}\)
\(=\frac{5}{18}-\frac{8}{5}\)
\(=\frac{-119}{90}\)
Ta có : \(\left(2^2:\frac{4}{3}-\frac{1}{2}\right).\frac{6}{5}-17\)
=\(=\left(4.\frac{3}{4}-\frac{1}{2}\right).\frac{6}{5}-17\)
\(=\frac{5}{2}.\frac{6}{5}-17\)
\(=3-17=-14\)
Tụi quá mới lớp 5 thui
a, (\(\frac{9}{25}\) - 2.18) : (\(3\frac{4}{5}\) + 0,2)
= (\(\frac{9}{25}\) - 36) : 4
= \(\frac{-891}{25}\) :4
= -8,91
tạm thời làm tới đây
Chúc bạn học tốt 
a) (925−2.18):(345+0,2)
= (\(\frac{9}{25}\) - 36) : (\(\frac{19}{5}\) + 0,2)
= \(\frac{-891}{25}\) : 4
= \(\frac{-891}{100}\)
b) 518−1,456:725+4,5.45
= \(\frac{5}{18}\) - (1,456 : \(\frac{7}{25}\)) + (4,5 . \(\frac{4}{5}\))
= \(\frac{5}{18}\) - \(\frac{26}{5}\) + \(\frac{18}{5}\)
= \(\frac{-443}{90}\) + \(\frac{18}{5}\)
= \(\frac{-119}{90}\).
\(a,\left(\frac{1}{\sqrt{625}}+\frac{1}{5}+1\right):\left(\frac{1}{25}-\frac{1}{\sqrt{25}}-1\right)\)
\(=\left(\frac{1}{25}+\frac{1}{5}+1\right):\left(\frac{1}{25}-\frac{1}{5}-1\right)\)
\(=\frac{31}{25}:\left(-\frac{29}{25}\right)\)
\(=\frac{31}{25}.\frac{-25}{29}\)
\(=-\frac{31}{29}\)
\(b,\left[18\frac{1}{6}-\left(0,06:7\frac{1}{2}+3\frac{2}{5}.0,38\right)\right]:\left(19-2\frac{2}{3}.4\frac{3}{4}\right)\)
\(=\left[\frac{109}{6}-\left(\frac{3}{50}:\frac{15}{2}+\frac{17}{5}.\frac{19}{50}\right)\right]:\left(19-\frac{8}{3}.\frac{19}{4}\right)\)
\(=\left(\frac{109}{6}-\frac{13}{10}\right):\frac{19}{3}\)
\(=\frac{253}{15}.\frac{3}{19}\)
\(=\frac{253}{95}\)
Số to :v
a) \(\frac{17}{9}-\frac{17}{9}:\left(\frac{7}{3}+\frac{1}{2}\right)\)
= \(\frac{17}{9}-\frac{17}{9}:\frac{17}{6}\)
= \(\frac{17}{9}-\frac{2}{3}\)
= \(\frac{11}{9}\)
b) \(\frac{4}{3}.\frac{2}{5}-\frac{3}{4}.\frac{2}{5}\)
= \(\frac{2}{5}.\left(\frac{4}{3}-\frac{3}{4}\right)\)
= \(\frac{2}{5}.\frac{7}{12}\)
= \(\frac{7}{30}\)
Mình lười làm quá, hay mình nói kết quả cho bn thôi nha
c) -6
d) 3
e) 3
g) 12
h) \(\frac{23}{18}\)
i) \(\frac{-69}{20}\)
k) \(\frac{-1}{2}\)
l) \(\frac{49}{5}\)
lớp 7???
lớp 6!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!