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a,\(\frac{-2}{5}+\frac{7}{21}=\frac{-2}{5}+\frac{1}{3}=\frac{-6}{15}+\frac{5}{15}=\frac{-1}{15}\)
b,\(\left(\frac{1}{3}\right)^5.3^5-2020^0=\left(\frac{1}{3}.3\right)^5-1=1^5-1=1-1=0\)
c,\(\left(-\frac{1}{4}\right).6\frac{2}{11}+3\frac{9}{11}.\left(-\frac{1}{4}\right)\)
\(=\left(-\frac{1}{4}\right).\left(6\frac{2}{11}+3\frac{9}{11}\right)=\left(-\frac{1}{4}\right).\left[\left(6+3\right)+\left(\frac{2}{11}+\frac{9}{11}\right)\right]\)
\(=\left(-\frac{1}{4}\right).\left[9+1\right]=\frac{-1}{4}.10=\frac{\left(-1\right).10}{4}=\frac{\left(-1\right).5}{2}=\frac{-5}{2}\)

a)Ta có:
\(A=4\frac{25}{16}+25\left(\frac{9}{16}:\frac{125}{64}\right):\frac{-27}{8}\)
\(\Rightarrow A=\frac{89}{16}+25.\frac{36}{125}:\frac{-27}{8}\)
\(\Rightarrow A=\frac{89}{16}+\frac{36}{5}:\frac{-27}{8}\)
\(\Rightarrow A=\frac{89}{16}+\frac{-32}{15}\)
\(\Rightarrow A=\frac{823}{240}\)
Vậy A=.....
b)Ta có:
\(C=\frac{2^3}{3.5}+\frac{2^3}{5.7}+\frac{2^3}{7.9}+...+\frac{2^3}{101.103}\)
\(\Rightarrow C=\frac{2^2.2}{3.5}+\frac{2^2.2}{5.7}+\frac{2^2.2}{7.9}+...+\frac{2^2.2}{101.103}\)
\(\Rightarrow C=2^2\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{101.103}\right)\)
\(\Rightarrow C=4\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+....+\frac{1}{101}-\frac{1}{103}\right)\)
\(\Rightarrow C=4\left(\frac{1}{3}-\frac{1}{103}\right)\)
\(\Rightarrow C=4.\frac{100}{309}\)
\(\Rightarrow C=\frac{400}{309}\)
Vậy C=.....

\(\frac{3^{37}}{9^5.3^{16}}=\frac{3^{37}}{\left(3^2\right)^5.3^{16}}=\frac{3^{37}}{3^{10}.3^{16}}=\frac{3^{37}}{3^{26}}=3^{11}\)

\(\frac{3^{27}}{9^5.3^{16}}\)
= \(\frac{3^{27}}{3^{15}.3^{16}}\)
= \(\frac{3^{27}}{3^{31}}\)
= \(\frac{1}{3^4}\)= \(\frac{1}{81}\)
Còn gì không hiểu cứ hỏi mình.
Hk tốt

\(\frac{7}{9}\)\(\times\)\(\sqrt{324}\)\(+\)\(\frac{1}{3}\)\(\times\)\(\sqrt{81}\)\(+\)\(\left(2014\right)^o\)\(-\)\(\left|-16\right|\)
\(=\)\(\frac{7}{9}\)\(\times\)18 + \(\frac{1}{3}\)\(\times\)9 + (2014)\(^0\)- |-16|
\(=\)14 + 3 + 1 - 16
\(=\)2
Bạn K cho mình nha

\(=\dfrac{2^{16}\cdot3^9+3^8\cdot3\cdot5\cdot2^{18}}{2^9\cdot2^{10}\cdot3^9+2^{20}\cdot3^{10}}\)
\(=\dfrac{2^{16}\cdot3^9+3^9\cdot2^{18}\cdot5}{2^{19}\cdot3^9+2^{20}\cdot3^{10}}\)
\(=\dfrac{3^9\cdot2^{16}\left(1+2^2\cdot5\right)}{3^9\cdot2^{19}\cdot\left(1+2\cdot3\right)}=\dfrac{1}{8}\cdot\dfrac{21}{7}=\dfrac{3}{8}\)
\(\frac{3^{27}}{9^5.3^{16}}\)
\(=\frac{3^{27}}{3^{10}.3^{16}}\)
\(=\frac{3^{27}}{3^{26}}=3\)