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5 tháng 9 2020

Mấy bài dài dài kia tí mình làm cho :) 

( x - 1 )3 - x( x - 2 )2 + 1 

= x3 - 3x2 + 3x - 1 - x( x2 - 4x + 4 ) + 1

= x3 - 3x2 + 3x - x3 + 4x2 - 4x

= x2 - x = x( x - 1 )

2x( 3x + 2 ) - 3x( 2x + 3 )

= 6x2 + 4x - 6x2 - 9x

= -5x

( x + 2 )3 + ( x - 3 )2 - x2( x + 5 )

= x3 + 6x2 + 12x + 8 + x2 - 6x + 9 - x3 - 5x2

= 2x2 + 6x + 17

( 2x + 3 )( x - 5 ) + 2x( 3 - x ) + x - 10

= 2x2 - 7x - 15 + 6x - 2x2 + x - 10

= -25

( x + 5 )( x2 - 5x + 25 ) - x( x - 4 )2 + 16x

= x3 + 53 - x( x2 - 8x + 16 ) + 16x

= x3 + 125 - x3 + 8x2 - 16x + 16

= 8x2 + 125

( -x - 2 )3 + ( 2x - 4 )( x2 + 2x + 4 ) - x2( x - 6 )

= -x3 - 6x2 - 12x - 8 + 2x3 - 16 - x3 + 6x2

= -12x - 24 = -12( x + 2 )

5 tháng 9 2020

Tương tự ... 

a, \(\left(x-1\right)^3-x\left(x-2\right)^2+1=x^3-3x^2+3x-1-x^3+4x^2-4x+1=x^2-x\)

b, \(2x\left(3x+2\right)-3x\left(2x+3\right)=6x^2+4x-6x^2-9x=-5x\)

c, \(\left(x+2\right)^3+\left(x-3\right)^2-x^2\left(x+5\right)=x^3+6x^2+12x+8+x^2+6x+9-x^3-5x^2=2x^2+18x+17\)

5 tháng 9 2020

a, \(\left(x+1\right)\left(x-2\right)=x^2-2x+x-2=x^2-x-2\)

b, \(-7x^2\left(3x-4y\right)=-21x^3+28x^2y\)

c, \(\left(x+4\right)\left(x-2\right)-\left(x-3\right)^2=x^2-2x+4x-8-\left(x^2-6x+9\right)\)

\(=x^2+2x-8-x^2+6x-9=8x-17\)

5 tháng 9 2020

Bạn ơi bạn giúp mình hết đc k??

a) Ta có: \(\left(x^2-1\right)\left(x^2+2x\right)\)

\(=x^4+2x^3-x^2-2x\)

b) Ta có: \(\left(2x-1\right)\left(3x+2\right)\left(3-x\right)\)

\(=\left(6x^2+4x-3x-2\right)\left(3-x\right)\)

\(=\left(6x^2+x-2\right)\left(3-x\right)\)

\(=18x^2-6x^3+3x-x^2-6+2x\)

\(=-6x^3+17x^2+5x-6\)

c) Ta có: \(\left(x+3\right)\left(x^2+3x-5\right)\)

\(=x^3+3x^2-5x+3x^2+9x-15\)

\(=x^3+6x^2+4x-15\)

d) Ta có: \(\left(x+1\right)\left(x^2-x+1\right)\)

\(=x^3+1\)

e) Ta có: \(\left(2x^3-3x-1\right)\left(5x+2\right)\)

\(=10x^4+4x^3-15x^2-6x-5x-2\)

\(=10x^4+4x^3-15x^2-11x-2\)

f) Ta có: \(\left(x^2-2x+3\right)\left(x-4\right)\)

\(=x^3-4x^2-2x^2+8x+3x-12\)

\(=x^3-6x^2+11x-12\)

g) Ta có: \(\left(4x-1\right)\left(3x+1\right)-5x\left(x-3\right)-\left(x-4\right)\left(x-3\right)\)

\(=12x^2+4x-3x-1-5x^2+15x-\left(x^2-7x+12\right)\)

\(=7x^2+16x-1-x^2+7x-12\)

\(=6x^2+23x-23\)

h) Ta có: \(\left(5x-2\right)\left(x+1\right)-3x\left(x^2-x-3\right)-2x\left(x-5\right)\left(x-4\right)\)

\(=5x^2+5x-2x-2-3x^3+3x^2+9x-2x\left(x^2-9x+20\right)\)

\(=-3x^3+8x^2+12x-2-2x^3+18x^2-40x\)

\(=-5x^3+26x^2-28x-2\)

17 tháng 10 2018

\(2x^2\left(3x-5x^3\right)+10x^5-5x^3\)

\(=\left(6x^3-10x^5\right)+10x^5-5x^3\)

\(=6x^3-10x^5+10x^5-5x^3\)

\(=\left(6x^3-5x^3\right)-\left(10^5-10^5\right)\)

\(=x^3\)

\(\left(x+2\right)\left(x^2-2x+4\right)+\left(x-4\right)\left(x+2\right)\)

\(=\left(x+2\right)\left[\left(x^2-2x+4\right)\right]+\left(x-4\right)\)

\(=\left(x+2\right)\left(x^2-2x+4+x-4\right)\)

\(=\left(x+2\right)\left[\left(x-2x\right)+\left(4-4\right)+x^2\right]\)

\(=\left(x+2\right)\left(-1+x\right)\)

\(=-x+x^2+\left(-2\right)+2x\)

\(=x+x^2+\left(-2\right)\)