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Bài 1:
A,
(100+121+144)÷(169+196)
=365:365=1
B
,1.2.3...7.8.(9-1-8)
=1.2.3...7.8.0=0
C,
3^2.2^4.2^32/11.2^13.2^22-2^26
=3^2.2^36/11.2^35-2^36
=3^2.2^36/2^35-(11-2)
=9.2/9=2
D,
=1152-374-1152+(-65)+374
=(1152-1152)+(-374+374)+(-65)
=0+0+(-65)=-65
E,
=13-(12-11-10+9)+(8-7-6+5)-(4-3-2+1)
=13-0+0-0=13
Bài 2:
A,(19x+50)÷14=25-16
(19x+50)÷14=9
19x+50=126
19x=76
x=4
B,
31x+(1+2+3+...+30)=1240
31x+465=1240
31x=775
×=25
\(\frac{3^2.4^2.2^{32}}{11.2^{13}.4^{11}-16^9}=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}=\frac{9.2}{9}=2\)
\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}=\frac{2^{19}.3^9+3.5.2^{18}.3^8}{6^9.2^{10}+6^{10}.2^{10}}=\frac{2^{19}.3^9+3^9.5.2^{18}}{6^9.2^{10}.\left(1+6\right)}=\frac{2^{18}.3^9.\left(2+5\right)}{2^9.3^9.2^{10}.7}=\frac{2^{18}.7}{2^{19}.7}=\frac{1}{2}\)
b/1.2.3.....2013 - 1.2.3....2012-1.2.3...20122
= (1.2.3...2012.2013-1.2.3...2012)-1.2.3...2012.2012
= 1.2.3...2012(2013-1-2012)
=1.2.3...2012.0=0
a) 42 . 57 + 43 . 42 - 600
= 2394 + 1806 - 600
= 4200 - 600
= 3600.
b) 22 . 52 - 64 : 23
= 4 . 25 - 64 : 8
= 100 - 8
= 92
c) 120 - [ 100 - ( 5 - 2 )3 ]
= 120 - [ 100 - ( 5 - 2 )3 ]
= 120 - [ 100 - 33 ]
= 120 - [ 100 - 27 ]
= 120 - 73
= 47.
1.Thực hiện các phép tính sau
a)42.57+43.42-600
b)22.52-64: 23
c) 120-[100-(5-2)3]
d)(102+112+122):(132+142)
a) 42 . 57 + 43 . 42 - 600
= 2394 + 1806 - 600
= 4200 - 600
= 3600.
b) 22 . 52 - 64 : 23
= 4 . 25 - 64 : 8
= 100 - 8
= 92
c) 120 - [ 100 - ( 5 - 2 )3 ]
= 120 - [ 100 - ( 5 - 2 )3 ]
= 120 - [ 100 - 33 ]
= 120 - [ 100 - 27 ]
= 120 - 73
= 47.
(214+215+216):(211+212+213)=214(1+2+22):211(1+2+22)=214:211=214-11=23=8
\(\left(2^{14}+2^{15}+2^{16}\right):\left(2^{11}+2^{12}+2^{13}\right)=\left(2^{14}:2^{11}\right)+\left(2^{15}:2^{12}\right)+\left(2^{16}:2^{13}\right)=8+8+8=24\)