Question

[Thảo Linh]

Thực hiện phép tính 

Answer 1

[Nguyễn Đăng Nhân]

\(\left(-8\right)+\frac{-3}{5}-\frac{7}{10}+9+\frac{-33}{30}\)

\(=\left(-8\right)+\frac{-3}{5}+\frac{-7}{10}+9+\frac{-33}{10}\)

\(=\left[\left(-8\right)+9\right]+\frac{-3}{5}+\frac{-7}{10}+\frac{-33}{10}\)

\(=1+\frac{-3}{5}+\frac{-7}{10}+\frac{-33}{10}\)

\(=1+\frac{-18}{30}+\frac{-21}{30}+\frac{-33}{30}\)

\(=1+\frac{\left[\left(-18\right)+\left(-21\right)+\left(-33\right)\right]}{30}\)

\(=1+\frac{-\left(18+21+33\right)}{30}\)

\(=1+\frac{72}{30}\)

\(=\frac{1\cdot30+72}{30}\)

\(=\frac{102:6}{30:6}=\frac{17}{5}\)