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a) 5 69 : 5 67 – 3 40 : 3 39 = 5 2 – 3 1 = 25 – 3 = 22
b) 155 – [ 2 . ( 30 + 5 – 26 ) . ( 24 : 3 )]
= 155 – [ 2 . 9 . 8 ] = 155 – 144 = 11
c) 37 . 143 + 37 . 57 + 1300
= (37 . 143 + 37.57) + 1300
= 37.(143+ 57) + 1300
= 37. 200 + 1300
= 7400 + 1300
8700.
Bài 1 :
\(a,569:569-340:339\)
=\(1-\frac{340}{339}\)
=\(-\frac{1}{339}\)
\(b,155-\left[2.\left(30+5-26\right).\left(24:2\right)\right]\)
=\(155-\left[2.9.12\right]\)
=\(155-216\)
=\(-61\)
\(c,37.143+37.57+1300\)
=\(37.\left(143+57\right)+1300\)
=\(37.200+1300\)
=\(7400+1300\)
=\(8700\)
Bài 2 :
\(95-5x=23+18:9\)
=>\(95-5x=23+2=25\)
=>\(5x=95-25=70\)
=>\(x=70:5=14\)
Vậy x ∈ {14}
569 : 567 - 340 : 339
= 1.0035273368606 - 1.0029498525073
= 0.0005774843533
Hk tốt,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
k nhé
26.66+34.66-280
= 66.(26+34)-280
=66.60 -280
= 3960-280
= 3680
a) 271 × 275 = 271 × (273 + 2) = 271 × 273 + 271 × 2
273 × 273 = (271 + 2) × 273 = 271 × 273 + 2 × 273
Vì 271 × 2 < 2 × 273
=> 271 × 275 < 273 × 273
b) 569 × 564 = (567 + 2) × 564 = 567 × 564 + 2 × 564
567 × 566 = 567 × (564 + 2) = 567 × 564 + 567 × 2
Vì 2 × 564 < 567 × 2
=> 569 × 564 < 567 × 566
a) 271 × 275 = 271 × (273 + 2) = 271 × 273 + 271 × 2
273 × 273 = (271 + 2) × 273 = 271 × 273 + 2 × 273
Vì 271 × 2 < 2 × 273
=> 271 × 275 < 273 × 273
b) 569 × 564 = (567 + 2) × 564 = 567 × 564 + 2 × 564
567 × 566 = 567 × (564 + 2) = 567 × 564 + 567 × 2
Vì 2 × 564 < 567 × 2
=> 569 × 564 < 567 × 566
\(a,\dfrac{3^{43}+3^4}{3^{39}+1}\)
\(=\dfrac{3^4\cdot\left(3^{39}+1\right)}{3^{39}+1}\)
\(=3^4\)
\(=81\)
a) \(125-\left(-75\right)+32-\left(48+32\right)\)
\(=125+75+32-48-32\)
\(=200+\left(32-32\right)-48\)
\(=200+0-48\)
\(=200-48\)
\(=152\)
b) \(3.\left(-4\right)^2+2.\left(-5\right)-20\)
\(=3.16-10-20\)
\(=48-30\)
\(=18\)
c) \(-1685+\left(-2365\right)+569-1685\)
\(=\left(-1685-1685\right)-2365+569\)
\(=-3370-2365+569\)
\(=-5735+569\)
\(=-5166\)
= -0,1368920138
5,774843533*10-04