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\(a.\)
\(\frac{15}{33}+\frac{7}{20}+\frac{18}{33}+\frac{13}{20}\)
\(=\left(\frac{15}{33}+\frac{18}{33}\right)+\left(\frac{13}{20}+\frac{7}{20}\right)\)
\(=\frac{33}{33}+\frac{20}{20}\)
\(=1+1=2\)
\(b.\)
\(2\frac{1}{2}+\frac{4}{7}:\left(-\frac{8}{21}\right)\)
\(=\frac{5}{2}+\frac{4}{7}:\left(-\frac{8}{21}\right)\)
\(=\frac{5}{2}+\frac{4}{7}.\left(-\frac{21}{8}\right)\)
\(=\frac{5}{2}+\frac{1}{1}.\left(-\frac{3}{2}\right)\)
\(=\frac{5}{2}-\frac{3}{2}\)
\(=1\)
\(c.\)
\(\left(-\frac{1}{2}\right)^3+\frac{1}{2}:5\)
\(=-\frac{1}{8}+\frac{1}{2}.\frac{1}{5}\)
\(=-\frac{1}{8}+\frac{1}{10}\)
\(=-\frac{1}{40}\)
a) \(\frac{15}{33}+\frac{7}{20}+\frac{18}{33}+\frac{13}{20}=\left(\frac{15}{33}+\frac{18}{33}\right)+\left(\frac{7}{20}+\frac{13}{20}\right)\) = 1 + 1 = 2
b) \(2\frac{1}{2}+\frac{4}{7}:\left(\frac{-8}{21}\right)=\frac{5}{2}+\frac{4}{7}:\left(\frac{-8}{21}\right)=\frac{5}{2}+\frac{-3}{2}\) = 1
c) \(\left(\frac{-1}{2}\right)\)3 + \(\frac{1}{2}\) : 5 = \(\frac{-1}{8}+\frac{1}{10}\) = \(\frac{-1}{40}\)
Chúc bạn học tốt!

\(=\frac{\left(2^{20}-1^{20}+3^{20}\right)\cdot2^{20}}{\left(2^{20}-1^{20}+3^{20}\right)\cdot3^{20}}\left(\text{Mình làm hơi tắt, xin bạn thông cảm}\right)\)
\(=\frac{2^{20}}{3^{20}}=\left(\frac{2}{3}\right)^{20}\)

\(a.=\frac{3}{15}+\frac{-10}{15}\)
\(=-\frac{7}{15}\)
\(b.=\left(\frac{15}{12}-\frac{3}{12}\right)+\left(\frac{5}{13}-\frac{18}{13}\right)\)
\(=1+\left(-1\right)\)
\(=0\)
\(c.=\left(\frac{13}{25}-\frac{38}{25}\right)+\left(\frac{6}{41}+\frac{35}{41}\right)-\frac{1}{2}\)
\(=-1+1-\frac{1}{2}\)
\(=0-\frac{1}{2}\)
\(=-\frac{1}{2}\)
\(d.=\frac{5}{6}.\left(18\frac{2}{3}-6\frac{2}{3}\right)\)
\(=\frac{5}{6}.12\)
\(=10\)

\(\left(-\frac{1}{2}+\frac{2}{3}\right)^2.\frac{6}{5}+\frac{3}{5}\)
\(=\frac{1}{36}.\frac{6}{5}+\frac{3}{5}\Rightarrow\frac{1}{30}+\frac{18}{30}=\frac{19}{30}\)
**Trả lời:
\(\left(-\frac{20}{3}\right)^3\cdot\left(-\frac{18}{5}\right)^2\)
\(=\left(-\frac{8000}{27}\right)\cdot\frac{324}{25}\)
\(=3840\).
\(\left(-\frac{20}{3}\right)^3\cdot\left(-\frac{18}{5}\right)^2\)
\(=-\frac{20^3}{3^3}\cdot\frac{18^2}{5^2}\)
\(=\frac{-\left(2^2\cdot5\right)^3}{3^3}\cdot\frac{\left(2\cdot3^2\right)^2}{5^2}=\frac{-2^6\cdot5^3}{3^3}\cdot\frac{2^2\cdot3^4}{5^2}\)
\(=-2^8\cdot5\cdot3=-256\cdot15=-3840\)