Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) 160 - ( 23 . 52 - 6 . 25 ) = 160-( 8 . 25 - 6 . 25 ) = 160 - ( 25 . ( 8-6)) = 160-(25 . 2) = 160- 50 = 110
b) 4 . 52 - 32 : 24 = 4 . 25 - 4 . 8 : 16 = 4 . ( 25 - 8 : 16 ) = 4 . 24,5 = 98
a) 42 . 57 + 43 . 42 - 600
= 2394 + 1806 - 600
= 4200 - 600
= 3600.
b) 22 . 52 - 64 : 23
= 4 . 25 - 64 : 8
= 100 - 8
= 92
c) 120 - [ 100 - ( 5 - 2 )3 ]
= 120 - [ 100 - ( 5 - 2 )3 ]
= 120 - [ 100 - 33 ]
= 120 - [ 100 - 27 ]
= 120 - 73
= 47.
1.Thực hiện các phép tính sau
a)42.57+43.42-600
b)22.52-64: 23
c) 120-[100-(5-2)3]
d)(102+112+122):(132+142)
a) 42 . 57 + 43 . 42 - 600
= 2394 + 1806 - 600
= 4200 - 600
= 3600.
b) 22 . 52 - 64 : 23
= 4 . 25 - 64 : 8
= 100 - 8
= 92
c) 120 - [ 100 - ( 5 - 2 )3 ]
= 120 - [ 100 - ( 5 - 2 )3 ]
= 120 - [ 100 - 33 ]
= 120 - [ 100 - 27 ]
= 120 - 73
= 47.
a)\(12:\left\{400:\left[500-\left(125+25×7\right)\right]\right\}\)
\(12:\left\{400:\left[500-300\right]\right\}\)
\(12:2\)
\(6\)
b)\(\left[\left(7-3^3:3^2\right):2^2+99\right]-100\)
\(=\left[4:4+99\right]-100\)
\(=100-100\)
\(=0\)
\(c,3^2×\left[\left(5^2-3\right):11\right]-2^4+2×10^3\)
\(=9×2-16+2×10000\)
\(=18-16+20000\)
\(=20002\)
b/1.2.3.....2013 - 1.2.3....2012-1.2.3...20122
= (1.2.3...2012.2013-1.2.3...2012)-1.2.3...2012.2012
= 1.2.3...2012(2013-1-2012)
=1.2.3...2012.0=0
\(A,\frac{4^9.36+64}{16^4.100}=\frac{\left(2^2\right)^9.2^2.3^2+2^6}{\left(2^4\right)^4.2^2.5^2}=\frac{2^{20}.3^2+2^6}{2^{18}.5^2}=\frac{2^6\left(2^{14}.3^2+1\right)}{2^{18}.5^2}=\frac{2^{14}.3^2+1}{2^{12}.5^2}=\frac{147457}{102400}\)
B,
\(\frac{11.3^{22}.3-9^{13}}{\left(2.3^{14}\right)^2}=\frac{11.3^{22}-\left(3^2\right)^{13}}{2^2.3^{28}}=\frac{11.3^{22}-3^{26}}{2^2.3^{28}}=\frac{3^{22}\left(11.1-3^4\right)}{2^2.3^{28}}=\frac{11-81}{2^2.3^6}=-\frac{70}{2916}=-\frac{35}{1456}\)
c,
\(\frac{45^3.20^4.18}{180^5}=\frac{\left(3^2.5\right)^3.\left(5.2^2\right)^4.2.3^2}{\left(2^2.3^2.5\right)^5}=\frac{3^6.5^3.5^4.2^8.2.3^2}{2^{10}.3^{10}.5^5}=\frac{3^8.2^{10}.5^7}{2^{10}.3^{10}.5^5}=\frac{5^2}{3^2}=\frac{25}{9}\)
\(\frac{4^9\cdot36+64}{16^4\cdot100}=\frac{2^6\cdot147457}{2^{16}\cdot100}=\frac{147457}{2^{10}\cdot100}\)
\(\frac{11\cdot3^{22}\cdot3-9^{13}}{2^2\cdot3^{28}}=\frac{3^{23}\left(11-3^3\right)}{2^2\cdot3^{28}}=\frac{-16\cdot3^{23}}{2^2\cdot3^{28}}=\frac{-4}{243}\)
\(\frac{45^3\cdot20^4\cdot18}{180^5}=\frac{3^8\cdot2^9\cdot5^7}{2^{10}\cdot3^{10}\cdot5^5}=\frac{25}{18}\)
dễ vãi
A=134-{150:50-[120:4+25-(11,3+18,7)]}
=134-{150:50-[120:4+25-30]}
=134-{150:50-[30+25-30]}
=134-{150:50-[30-30+25]}
=134-{150:50-[0+25]}
=134-{150:50-25}
=134-{30-25}
=134-5
=129
B=(102+112+122):(132+142)
= [ \((10+11+12)^2\) ]: \([(13+14)^2]\)
= \(33^2\): \(27^2\)