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c)\(x^2+x+\dfrac{1}{4}=\left(x+\dfrac{1}{2}\right)^2\)
d)\(\dfrac{a^2}{4}-2a+4=\left(\dfrac{a}{2}-2\right)^2\)
e) \(4y^2-9x^2=\left(2y-3x\right)\left(2y+3x\right)\)
f)\(9y^2-\dfrac{1}{4}=\left(3y-\dfrac{1}{2}\right)\left(3y+\dfrac{1}{2}\right)\)
g)\(8x^3+8a^3=\left(2x+2a\right)\left(4x^2-4xa+4a^2\right)\)
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c) 5(x^2+8x+16)+4(x^2-10x+25)-9(x^2-16)
=5x^2+40x+80+4x^2-40x+100-9x^2+144
=80+100+144
=324
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a,\(0,04x^2-64y^2=\left(0,2x\right)^2-\left(8y\right)^2=\left(0,2x-8y\right)\left(0,2x+8y\right)\)
b,\(-x^3+9x^2-27x+27=-x^3+3x^2+6x^2-18x-9x+27\)
\(=-x^2\left(x-3\right)+6x\left(x-3\right)-9\left(x-3\right)=\left(-x^2+6x-9\right)\left(x-3\right)\)
\(=-\left(x-3\right)^3\)
Nhớ tick mình nha bạn,cảm ơn nhiều nha.
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a) \(\left(9m^3-5p^2n\right)^2\)
b) \(\left(x^4-y^2\right)^3\)
c) \(\left(4x^5-3x^3\right)^3\)
d: \(=\left(x+y\right)^3+3\left(x+y\right)^2+3\left(x+y\right)+1\)
\(=\left(x+y+1\right)^3\)
a: \(=\left(9m^3-5p^2n\right)^2\)
b: \(=\left(x^4-y^2\right)^3\)
c: \(=\left(4x^5-3x^3\right)^3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1 : hđt bạn tự làm nhé
Bài 2 :
\(\left(x-1\right)\left(x^2+x+1\right)-\left(x-4\right)^2x\)
\(=x^3-1-x\left(x^2-8x+16\right)=x^3-1-x^3+8x^2-16x\)
\(=8x^2-16x-1\)
\(\left(x+7\right)\left(x^2-7x+49\right)-\left(5-x\right)\left(5+x\right)\left(x-1\right)\)
\(=x^3+343-\left(25-x^2\right)\left(x-1\right)=x^3+343-\left(25x-25-x^3+x^2\right)\)
\(=x^3+343+x^3-x^2-25x+25=2x^3-x^2-25x+368\)
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\(27x^3y-9xy^2=9xy\left(3x^2-y\right)\)
\(3x\left(x+y\right)-12x^2\left(x+y\right)=3x\left(x+y\right)\left(1-4x\right)\)