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c) C = 4 + 42 + 43 + 44 + ... + 449
=>4C=42 + 43 + 44 + ... + 450
=>4C-C=42 + 43 + 44 + ... + 450-4-42-43-44-...-449
=>C(4-1)=450-4
=>C.3=450-4
=>C=\(\frac{4^{50}-4}{3}\)
d) D = 1 + 7 + 72 + 73 + ... + 779
=>7D=7 + 72 + 73 + ... + 780
=>7D-D=7 + 72 + 73 + ... + 780-1-7-72-73-...-779
=>D(7-1)=780-1
=>D.6=780-1
=>D=\(\frac{7^{80}-1}{6}\)

a) A = 2 + 22 + 23 +...+ 229
=>2A= 22 + 23 +...+ 230
=>2A-A= 22 + 23 +...+ 230-2-22-23-...-229
=>A.(2-1)=230-2
=>A=230-2
b) B = 1 + 3 + 32 + 33 + ... + 339
=>3B=3 + 32 + 33 + ... + 340
=>3B-B=3 + 32 + 33 + ... + 340-1 - 3 - 32 - 33 - ... - 339
=>B(3-1)=340-1
=>B.2=340-1
=>B=\(\frac{3^{40}-1}{2}\)
nhiều wa 2 câu trước
a) A= 2 + 2^2 + 2^3 + ... + 2^29
2A= 2. (2 + 2^2 + 2^3 + ... + 2^29)
2A= 2^2 + 2^3 + 2^4 + ... +2^29 + 2^30
- (dấu trừ viết ra đầu dòng nha)
A= 2 + 2^2 + 2^3 + 2^4 ... + 2^29
1A= 2^29 - 2
A= 2^29 -2 trên 1
kick mk nha

a) \(S=1+3^2+3^4+3^6+...+3^{2002}\)
\(3^2.S=3^2+3^4+3^6+3^8+...+3^{2004}\)
\(9S-S=\left(3^2+3^4+3^6+3^8+...+3^{2004}\right)-\left(1+3^2+3^4+3^6+...+3^{2002}\right)\)
\(8S=3^{2004}-1\)
\(S=\frac{3^{2004}-1}{8}\)
b) \(S=1+3^2+3^4+3^6+...+3^{2002}\)
\(=\left(1+3^2+3^4\right)+3^6\left(1+3^2+3^4\right)+...+2^{1998}\left(1+3^2+3^4\right)\)
\(=\left(1+3^2+3^4\right)\left(1+3^6+...+3^{1998}\right)\)
\(=91\left(1+3^6+...+3^{1998}\right)\)
\(=7.13\left(1+3^6+...+3^{1998}\right)\)
Vậy S chia hết cho 7

\(A=3+3^3+3^5+...+3^{2019}\)
\(3^2A=3^3+3^5+3^7+...+3^{2021}\)
\(9A-A=3^{2021}-3\) hay \(8A=3^{2021}-3\)
\(A=\frac{3^{2021}-3}{8}\)

\(7I=7+7^2+7^3+7^4+...+7^{102}\)
\(6I=7I-I=7^{102}-1\Rightarrow I=\frac{7^{102}-1}{6}\)


a) 125 : 34 = (12.12.12.12.12):(3.3.3.3)
= 248832 : 81
= 3072
b) Mình ko biết
a, \(12^5\div3^4=\left(3.2^2\right)^5\div3^4=3^5.2^{10}\div3^4=3.2^{10}\)
b, \(2^{11}\div2^7.32^{12}=2^{11}\div2^7.\left(2^5\right)^{12}=2^4.2^{30}=2^{34}\)