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\(\frac{21^4}{27\cdot(-343)}+7\)
\(=\frac{(3\cdot7)^4}{3^3\cdot(-7)^3}+7\)
\(=\frac{3^4\cdot7^4}{3^3\cdot(-7)^3}+7\)
\(=3\cdot(-7)+7=-14\)
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\(A=\frac{2^{19}.\left(2^3\right)^3+15.\left(2^2\right)^9.\left(3^2\right)^4}{2^9.3^9.2^{10}+\left(2^2.3\right)^{10}}=\frac{2^{19}.3^9+15.2^{18}.3^8}{2^{19}.3^9+2^{20}.3^{10}}=\frac{2^{18}.3^8.\left(2.3+15\right)}{2^{19}.3^9.\left(1+2.3\right)}\)
\(=\frac{2^{18}.3^8.21}{2^{19}.3^9.7}=\frac{21}{2.3.7}=\frac{1}{2}\)
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Ta có: 2^4 = 16 , 6^7= 279936
9^3=729, 4^6= 4096
Và 16.279936=4478976
729.4096=2985984
=> 4478976:2985984= \(\frac{3}{2}\)
Vậy kết quả của phép tính là \(\frac{3}{2}\)
\(\frac{2^4.6^7}{9^3.4^6}\)
\(=\frac{2^4.\left(2.3\right)^7}{\left(3^2\right)^3.\left(2^2\right)^6}\)
\(=\frac{2^4.2^7.3^7}{3^6.2^{12}}\)
\(=\frac{2^{11}.3^7}{3^6.2^{12}}\)
\(=\frac{3}{2}\)
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1.
a. \(\frac{5^4.18^4}{125.9^5.16}=\frac{5^4.2^4.3^8}{5^3.3^{10}.2^4}=\frac{5}{3^2}=\frac{5}{9}\)
2.
a . x : ( 0,25 ) 4 = ( 0,5 ) 2
=> x : ( 0,5 ) 8 = ( 0,5 ) 2
=> x = ( 0,5 ) 2 . ( 0,5 ) 8
=> x = ( 0,5 ) 10
=> x = \(\frac{1}{1024}\)
Bài 1.\(\frac{5^4\cdot18^4}{125\cdot9^5\cdot16}=\frac{5^4\cdot9^4\cdot2^4}{5^3\cdot9^5\cdot2^4}=\frac{5}{9}\)
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\(\frac{5^3.5^8}{25^4}\)
\(=\frac{5^{11}}{25^4}\)
\(=\frac{48828125}{390625}\)
\(\frac{5^3.5^8}{25^4}=\frac{5^8.5^3}{\left(5^2\right)^4}\)
\(\Rightarrow\frac{5^8.5^3}{5^8}=5^3=125\)
Hk tốt
\(\left(\frac{2}{-3}\right)^2-\frac{-5}{2}\)
\(=\left(\frac{-2}{3}\right)^2-\frac{-5}{2}\)
\(=\frac{4}{9}-\frac{-5}{2}\)
\(=\frac{53}{18}\)