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\(\frac{3}{4}+\frac{2}{3}=\frac{9}{12}+\frac{8}{12}=\frac{17}{12}\)
\(\frac{9}{2}-4=\frac{9}{2}-\frac{8}{2}=\frac{1}{2}\)
\(\frac{4}{5}\times\frac{3}{2}=\frac{4\times3}{5\times2}=\frac{12}{10}=\frac{6}{5}\)
\(\frac{5}{6}:\frac{6}{5}=\frac{5}{6}\times\frac{5}{6}=\frac{25}{36}\)
\(3+\frac{2}{5}-\frac{3}{4}\times\frac{4}{5}\)
\(=3+\frac{2}{5}-\frac{3}{4}\)
\(=\frac{3\times20+2\times4-3\times5}{20}\)
\(=\frac{60+8-15}{20}\)
\(=\frac{68-15}{20}\)
\(=\frac{53}{20}\)
\(5-\frac{7}{9}+\frac{2}{3}-\frac{5}{6}:\frac{4}{9}\)
\(=5-\frac{7}{9}+\frac{2}{3}-\frac{45}{24}\)
\(=\frac{5\times72-7\times8+2\times24-45\times3}{72}\)
\(=\frac{360-56+48-135}{72}\)
\(=\frac{217}{72}\)
\(a.\frac{3}{7}.\frac{5}{6}+\frac{5}{6}.\frac{4}{7}=\left(\frac{3}{7}+\frac{4}{7}\right).\frac{5}{6}=1.\frac{5}{6}=\frac{5}{6}\)
\(b.\frac{1}{6}:\frac{4}{5}+\frac{1}{8}:\frac{4}{5}=\left(\frac{1}{6}+\frac{1}{8}\right):\frac{4}{5}=\left(\frac{4}{24}+\frac{3}{24}\right):\frac{4}{5}=\frac{7}{24}:\frac{4}{5}=\frac{7.5}{24.4}\)\(=\frac{35}{96}\)
\(c.\frac{1}{6}:\frac{4}{5}-\frac{1}{8}:\frac{4}{5}=\left(\frac{1}{6}-\frac{1}{8}\right):\frac{4}{5}=\left(\frac{4}{24}-\frac{3}{24}\right):\frac{4}{5}\)\(=\frac{1}{24}:\frac{4}{5}=\frac{1.5}{24.4}=\frac{5}{96}\)
a) \(\frac{3}{7}\cdot\frac{5}{6}+\frac{5}{6}\cdot\frac{4}{7}\)
\(=\left(\frac{3}{7}+\frac{4}{7}\right)\cdot\frac{5}{6}\)
\(=1\cdot\frac{5}{6}\)
\(=\frac{5}{6}\)
b) \(\frac{1}{6}:\frac{4}{5}+\frac{1}{8}:\frac{4}{5}\)
\(=\left(\frac{1}{6}+\frac{1}{8}\right):\frac{4}{5}\)
\(=\frac{7}{24}:\frac{4}{5}\)
\(=\frac{35}{96}\)
c) \(\frac{1}{6}:\frac{4}{5}-\frac{1}{8}:\frac{4}{5}\)
\(=\left(\frac{1}{6}-\frac{1}{8}\right):\frac{4}{5}\)
\(=\frac{1}{24}:\frac{4}{5}\)
\(=\frac{5}{96}\)
Ta có 19/18=1+1/18
2005/2004=1+1/2004
Vì 1/18>1/2004 nên 1+1/18 >1/2004 +1 hay 19/18>2005/2004
1. Ta có: \(\frac{19}{18}>\frac{18}{18}=1=\frac{2005}{2005}>\frac{2004}{2005}\)
hay: 19/18 > 1 > 2004/2005
Vậy 19/18 > 2004/2005
2. \(\frac{3}{6}=\frac{1}{2}=\frac{7}{14};\frac{2}{7}=\frac{4}{14};\frac{4}{7}=\frac{8}{14}\)
Vì 4/14 < 7/14 < 8/14
nên: 2/7 < 3/6 < 4/7.
3. \(\frac{12}{25};\frac{9}{5}=\frac{45}{25};\frac{3}{5}=\frac{15}{25};\frac{1}{25}\)
Vì 45/25 > 15/25 > 12/25 > 1/25
nên: 9/5 > 3/5 > 12/25 > 1/25
4. \(\frac{35}{42}+\frac{14}{42}=\frac{35+14}{42}=\frac{49}{42}\)
5. \(\frac{6}{16}+\frac{32}{16}=\frac{6+32}{16}=\frac{38}{16}=\frac{19}{8}\).
\(\frac{3}{4}:\frac{5}{6}+\frac{1}{4}:\frac{5}{6}\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right):\frac{5}{6}\)
\(=1:\frac{5}{6}\)
\(=1\times\frac{6}{5}\)
\(=\frac{6}{5}\)
\(\frac{3}{4}:\frac{5}{6}+\frac{1}{4}:\frac{5}{6}\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right):\frac{5}{6}\)
\(=1:\frac{5}{6}\)
\(=1\times\frac{6}{5}\)
\(=\frac{6}{5}\)
\(\frac{5}{8}:x=\frac{3}{4}\)
\(x=\frac{5}{8}:\frac{3}{4}\)
\(x=\frac{5}{6}\)
\(\frac{2}{4}+\frac{3}{4}:\frac{1}{2}\)
\(=\frac{2}{4}+\frac{6}{4}\)
\(\frac{8}{4}=2\)
Hok tốt
\(\dfrac{5}{2}\left(tạ\right)=2,5\left(tạ\right)=25\left(yến\right)\) nha bạn
\(\frac52\)tạ = 4 yến vì:
1 tạ = 10 yến
\(\frac52\) tạ = 10 yến x \(\frac52\) = 4 yến