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\(\frac{17}{23}\)=\(\frac{85}{115}\)
Mà \(\frac{85}{115}\)> \(\frac{85}{117}\)
=> \(\frac{17}{23}\)>\(\frac{85}{117}\)
đổi : \(\frac{17}{23}=\frac{85}{115}\)
Do \(\frac{85}{115}>\frac{85}{117}\)
\(\Rightarrow\frac{17}{23}>\frac{85}{117}\)

Cách 1 :
Ta có : \(\frac{11}{12}=\frac{198}{216}\)
\(\frac{17}{18}=\frac{201}{216}\)
Vì : 198 < 201 => \(\frac{198}{216}=\frac{11}{12}< \frac{201}{216}=\frac{17}{18}\)
Cách 2 :
Có : \(\frac{11}{12}=1-\frac{1}{12}\)
\(\frac{17}{18}=1-\frac{1}{18}\)
Vì : \(\frac{1}{12}>\frac{1}{18}\)=>\(\frac{11}{12}< \frac{17}{18}\)
Ủng hộ nhá !!!

\(\frac{7}{13}=1-\frac{5}{13}< 1-\frac{5}{8}=\frac{3}{8}\)

\(\frac{17171718}{19191919}>\frac{17171717}{19191919}=\frac{17.1010101}{19.1010101}=\frac{17}{19}\)
=>\(\frac{17}{19}< \frac{17171718}{19191919}\)\
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Ta có: \(\frac{17171718}{19191919}=\frac{17171717}{19191919}+\frac{1}{19191919}=\frac{17}{19}+\frac{1}{19191919}\)
Vì \(\frac{17}{19}< \frac{17}{19}+\frac{1}{19191919}\)nên \(\frac{17}{19}< \frac{17171718}{19191919}\)

a) \(\frac{5}{6}\)= \(\frac{15}{18}\); b) \(\frac{99}{100}\)< \(\frac{100}{99}\); c ) \(\frac{15}{17}\)> \(\frac{13}{18}\)vì \(\frac{15}{17}\)> \(\frac{15}{18}\)> \(\frac{13}{18}\);
d) \(\frac{222}{333}\)= \(\frac{2}{3}\)\(=1-\frac{1}{3}\); \(\frac{3333}{4444}\)= \(\frac{3}{4}\)= \(1-\frac{1}{4}\); vì \(\frac{1}{3}\)> \(\frac{1}{4}\)nên \(\frac{222}{333}\)< \(\frac{3333}{4444}\)
e) \(\frac{292929}{272727}\)= \(\frac{29}{27}\)= \(1+\frac{2}{17}\); \(\frac{347347}{345345}\)= \(\frac{347}{345}\)= \(1+\frac{2}{345}\)nên \(\frac{292929}{272727}\)> \(\frac{347347}{345345}\)
\(\frac{17}{2}=8\frac{1}{2}>5\)
5<17/2