Question

[Công chúa Lọ Lem]

So sánh : \(\frac{n}{n+3}\)và \(\frac{n+1}{n+2}\);\(\left(n\in N\cdot\right)\)

Answer 1

[Đinh Đức Hùng]

Ta có : 

\(\frac{n}{n+3}< \frac{n}{n+2}\)

\(\frac{n+1}{n+2}>\frac{n}{n+2}\)

\(\Rightarrow\frac{n}{n+3}< \frac{n}{n+2}< \frac{n+1}{n+2}\)

Vậy \(\frac{n}{n+3}< \frac{n+1}{n+2}\)