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hok tốt
aggg
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A=2008.2008=2.1004.2.1004=4.1004^2
B=2006.2010=2.1003.2.1005=4.1005.1003
ta có:1004^2>1003.1005
A>B
b)4835+90=47.102+41+90=47.102+131
47.36+50<4835+90
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hok tốt
am
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link tham khảo
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hok tốt
n
link tham khảo
link : https://olm.vn/hoi-dap/detail/13491883964.html
hok tốt
alll
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1:a) A=2008.2008=2.1004.2.1004=4.
B=2006.2010=2.1003.2.1005=4.1005.1003
ta có:>1003.1005
A>B
b)4835+90=47.102+41+90=47.102+131
47.36+50<4835+90
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A = 2008 . 2008 = 2. 1004 .2. 1004 = 4 . 1004 ^ 2
B = 2006 . 2012 = 2 . 1005 . 2 . 1003 = 4 . 1005 . 1003
Ta có : 1004 ^ 2 > 1003 . 1005
A>B
Mình chỉ làm đc thế thôi !
-Học tốt-
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a) ta có: A = 2008.2008 = 2008.2006 + 2008.2
B = 2006.2010 = 2006.2008 + 2006.2
=> 2008.2 > 2006.2 => 2008.2006 + 2008.2 > 2006.2008 + 2006.2 => A > B
b) ta có: A = 47.36 + 53
B = 48.53 + 90 = 47.53 + 47+ 90 = 47.53 + 137
=> 47.36 < 47.53
53 < 137
=> 47.36 + 52 < 47.53 + 137
=> A < B
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Ta có: a = 2002.2002 = 2002.(2000 + 2) = 2002.2000 + 2002.2
b = 2000.2004 = 2000.(2002 + 2) = 2000.2002 + 2000.2
Do 2002. 2000 = 2000. 2002 và 2002.2 > 2000.2
Nên a > b
Có: `B=48.35+90`
`=> B=48.(36-1)+90`
`=> B=48.36-48+90`
`=> B=48.36+42`
`=> B=36(47+1)+42`
`=> B=47.36+36+42`
`=> B=47.36+78>A=47.36+53`
`A=47.36+53=(48-1).(35+1)+53`
`=48.35-35+48-1+53`
`=48.35+65<48.35+90=B`
`=>A<B`