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a/ 507>497=(72)7=714
=> 507>714
b/ 12410 < 12510=(53)10=530
=> 12410 < 530
c/ 921=(32)21=342
7297=(36)7=342
=> 921 = 7297
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a) ta có: 3100 = (32)50 = 950
b) ta có: 330 = (33)10 = 2710 > 810
c) ta có: 36.67 = 62.67 = 69
Lại có: 433 > 427 = (43)9 = 649 > 69
=> 433>36.67
\(a,\)\(3^{100}\)\(=3^{2.50}\)=\(\left(3^2\right)\)\(^{50}\)\(=9^{50}\)
\(\Rightarrow\)\(3^{100}\)= \(9^{50}\)
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So sánh:
a) 5^300 và 3^500
b) (-16)^11 và (-32)^9
c) (2^2)^3 và 2^2^3
d) 2^30 + 2^30 + 4^30 và 3^20 + 6^20 + 8^20
e) 4^30 và 3×24^10
g) 2^0 + 2^1 + 2^2 + 2^3 +...+ 2^50 và 2^51
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\(3^{40}=\left(3^4\right)^{10}=81^{10}\)
\(4^{30}=\left(4^3\right)^{10}=64^{10}\)
Vì \(81>64\)
`-> 81^10 > 64^10`
`-> 3^40 > 4^30`
`----`
`2^75=(2^3)^25=8^25`
`3^50=(3^2)^25=9^25`
Vì `9>8`
`-> 9^25 > 8^25`
`-> 3^50 > 2^75`.
a: 3^40=81^10
4^30=64^10
=>3^40>4^30
b: 2^75=8^25
3^50=9^25
=>2^75<3^50
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a) 10249=(210)9=290
vì 2100>290 nên 2100>10249
b)912=(32)12=324
277=(33)7=321
vì 324 > 321 nên 912>277
c)12580=(53)80=5240
25118=(52)118=5236
vì 5240>5236 nên 12580>25118
d)100020=(103)20=1060
vì 1030<1060 nên 1030<100020
e)10750=(1072)25=1144925
7375=(733)25=38901725
vì 1144925<38901725 nên 10750<7375
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a/ \(2^{100}=\left(2^3\right)^{100}=8^{100}>8^{30}\)
b/ \(3^{75}=\left(3^3\right)^{25}=27^{25}\)
\(4^{50}=\left(4^2\right)^{25}=16^{25}\)
\(\Rightarrow3^{75}>4^{50}\)
c/ \(9^{199}=\left(3^2\right)^{199}=3^{398}\)
\(27^{121}=\left(3^3\right)^{121}=3^{363}\)
\(\Rightarrow9^{199}>27^{121}\)
d/ \(26^{38}>16^{38}=\left(2^4\right)^{38}=2^{152}\)
\(64^{25}=\left(2^6\right)^{25}=2^{150}\)
\(\Rightarrow26^{38}>64^{25}\)
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320320 và 274274
Ta có: 274=(33)4=312<320274=(33)4=312<320
⇒320>274⇒320>274
225225 và 166166
Ta có:
166=(24)6=224<225166=(24)6=224<225
⇒225>224⇒225>224
534534 và 25.53025.530
Ta có:
25.530=532<53425.530=532<534
⇒534>25.530⇒534>25.530
10301030 và 450450
Ta có:
450=(22)50=2100=(210)10=102410450=(22)50=2100=(210)10=102410
1030=(103)10=100010<1024101030=(103)10=100010<102410
⇒1030<450
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Có : (-1/5)^30 = -1/5^30
(-1/5)^50 = -1/5^50
Ta có : 5^30 < 5^50 => 1/5^30 > 1/5^50
=> -1/5^30 < -1/5^50
=> (-1/5)^30 < (-1/5)^50
Tk mk nha
\(\left(\frac{-1}{5}\right)^{30}=-\left(\frac{1}{5}\right)^{30}=-\left(\frac{1}{5^{30}}\right)\)
\(\left(\frac{-1}{5}\right)^{50}=-\left(\frac{1}{5}\right)^{50}=-\left(\frac{1}{5^{50}}\right)\)
ta thấy \(5^{30}< 5^{50}\Rightarrow\frac{1}{5^{30}}>\frac{1}{5^{50}}\Rightarrow-\left(\frac{1}{5^{30}}\right)< -\left(\frac{5}{5^{50}}\right)\)
\(\Rightarrow\left(\frac{-1}{5}\right)^{30}< \left(\frac{-1}{5}\right)^{50}\)
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a) ta có: 7^10 < 7^14 = (7^2)^7 = 49^7 < 50^7
=> 7^10 < 50^7
b) ta có: 5^30 = (5^3)^10 = 125^10 > 124^10
=> 5^30 > 124^10
c) ta có: 9^21 = (9^3)^7=729^7
phần d thì mk ko bk, xl bn nha
`3^{30}` giữ nguyên
`9^{50}=(3^{2})^{50}=3^{100}`
Vì `30 < 100=>3^{30} < 3^{100}`
Hay `3^{30} < 9^{50}`