Question

[buiminh]

rut gon /x-3/+/4+x/+x-5=Q

Answer 1

[Le Thi Khanh Huyen]

Ta có :

TH1 : \(x< -4;\)ta có :

\(Q=\left[-\left(x-3\right)\right]+\left[-\left(x+4\right)\right]+x-5\)

\(=3-x-x-4+x-5\)

\(=-6-x\)

TH2 : \(-4\le x< 3;\)ta có :

\(Q=\left[-\left(x-3\right)\right]+\left(4-x\right)+x-5\)

\(=3-x+4-x+x-5\)

\(=2-x\)

TH3 : \(x\ge3;\)ta có :

\(Q=\left(x-3\right)+\left(4+x\right)+x-5\)

\(=x-3+4+x+x-5\)

\(=3x-4\)